oj.uz

답안 #843398

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
843398 2023-09-04T01:33:38 Z Tuanlinh123 공장들 (JOI14_factories) C++17
15 / 100
 8000 ms 152708 KB 
#include "factories.h"
#include <bits/stdc++.h>
#define taskname ""
#define all(x) x.begin(), x.end()
#define rall(x) x.rbegin(), x.rend()
#define ll long long
#define ld long double
#define pb push_back
#define ff first
#define ss second
#define pii pair<int, int>
#define vi vector<int>
#define vll vector<ll>
#define vvi vector<vi>
#define vii vector<pii>
#define isz(x) (int)x.size()
using namespace std;
 
const int mxN = 5e5 + 5;
const ll oo = 1e18;
 
int n;
vector<vii> G;
 
vi vtn;
vector<vii> vt;
 
ll dis[mxN];
pii sparse[19][mxN];
int timer, ecnt, ap[mxN], dep[mxN], cur[mxN], tin[mxN], tout[mxN];
 
void dfs(int v, int p) {
    tin[v] = ++timer;
    dep[v] = dep[p] + 1;
    sparse[0][++ecnt] = {dep[v], v};
    ap[v] = ecnt;
 
    for(auto &[u, w] : G[v]) {
        if(u == p) continue;
        dis[u] = dis[v] + p;
        dfs(u, v);
        sparse[0][++ecnt] = {dep[v], v};
    }
 
    tout[v] = ++timer;
}
 
void build_sparse() {
    for(int p = 1, i = 1; p << 1 <= ecnt; p <<= 1, ++i)
        for(int j = 1; j <= ecnt - (p << 1) + 1; ++j)
            sparse[i][j] = min(sparse[i - 1][j], sparse[i - 1][j + p]);
}
 
bool is_ancestor(int u, int v) {
    return tin[u] <= tin[v] && tout[u] >= tout[v];
}
 
int LCA(int u, int v) {
    int l = ap[u], r = ap[v];
    if(l > r) swap(l, r);
    int len = r - l + 1, lg_len = __lg(len);
    return min(sparse[lg_len][l], sparse[lg_len][r - (1 << lg_len) + 1]).ss;
}
 
void Init(int N, int A[], int B[], int D[]) {
    n = N;
    G.resize(n); vt.resize(n);
    for(int i = 0; i < N - 1; ++i) {
        G[A[i]].emplace_back(B[i], D[i]);
        G[B[i]].emplace_back(A[i], D[i]);
    }
    dfs(0, 0); build_sparse();
}
 
long long Query(int S, int X[], int T, int Y[]) {
    queue<pii> q;
 
    for(int i = 0; i < S; ++i) {
        cur[X[i]] = 1;
        q.emplace(X[i], 0);
        vtn.emplace_back(X[i]);
    }
    for(int i = 0; i < T; ++i) {
        cur[Y[i]] = 2;
        vtn.emplace_back(Y[i]);
    }
 
    sort(all(vtn), [&](int u, int v) {
        return tin[u] < tin[v];
    });
 
    for(int i = 0; i < S + T - 1; ++i) {
        vtn.emplace_back(LCA(vtn[i], vtn[i + 1]));
    }
 
    sort(all(vtn), [&](int u, int v) {
        return tin[u] < tin[v];
    });
    vtn.erase(unique(all(vtn)), vtn.end());
 
    auto add_vt = [&](int u, int v, int w) {
        vt[u].emplace_back(v, w);
        vt[v].emplace_back(u, w);
    };
 
    stack<int> s;
    for(int i = 0; i < isz(vtn); ++i) {
        while(not s.empty() && not is_ancestor(s.top(), vtn[i])) s.pop();
        if(s.empty()) s.emplace(vtn[i]);
        else {
            add_vt(s.top(), vtn[i], dis[vtn[i]] - dis[s.top()]);
            s.emplace(vtn[i]);
        }
    }
 
    ll res = oo;
 
    auto dfs = [&](auto self, int v, int p) -> vll {
        vll cur_dis(2, oo);
        if(cur[v]) cur_dis[cur[v] - 1] = 0;
        for(auto &[u, w] : G[v]) {
            if(u == p) continue;
            vll tmp = self(self, u, v);
            for(int i = 0; i < 2; ++i)
                cur_dis[i] = min(cur_dis[i], tmp[i] + w);
        }
        res = min(res, accumulate(all(cur_dis), 0LL));
        return cur_dis;
    };
 
    dfs(dfs, vtn[0], 0);
 
    for(int i = 0; i < S; ++i) {
        cur[X[i]] = 0;
        vt[X[i]].clear();
    }
    for(int i = 0; i < T; ++i) {
        cur[Y[i]] = 0;
        vt[Y[i]].clear();
    }
    vtn.clear();
 
    return res;
}

Subtask #1
15.0 / 15.0

# 결과 실행 시간 메모리 Grader output
1 Correct 23 ms 45656 KB Output is correct
2 Correct 1330 ms 57540 KB Output is correct
3 Correct 1506 ms 57780 KB Output is correct
4 Correct 1500 ms 57524 KB Output is correct
5 Correct 1665 ms 57504 KB Output is correct
6 Correct 797 ms 57024 KB Output is correct
7 Correct 1503 ms 57864 KB Output is correct
8 Correct 1490 ms 57512 KB Output is correct
9 Correct 1588 ms 57280 KB Output is correct
10 Correct 793 ms 56912 KB Output is correct
11 Correct 1477 ms 57868 KB Output is correct

Subtask #2
0 / 18.0

# 결과 실행 시간 메모리 Grader output
1 Correct 13 ms 45656 KB Output is correct
2 Execution timed out 8026 ms 152708 KB Time limit exceeded
3 Halted 0 ms 0 KB -

Subtask #3
0 / 67.0

# 결과 실행 시간 메모리 Grader output
1 Correct 23 ms 45656 KB Output is correct
2 Correct 1330 ms 57540 KB Output is correct
3 Correct 1506 ms 57780 KB Output is correct
4 Correct 1500 ms 57524 KB Output is correct
5 Correct 1665 ms 57504 KB Output is correct
6 Correct 797 ms 57024 KB Output is correct
7 Correct 1503 ms 57864 KB Output is correct
8 Correct 1490 ms 57512 KB Output is correct
9 Correct 1588 ms 57280 KB Output is correct
10 Correct 793 ms 56912 KB Output is correct
11 Correct 1477 ms 57868 KB Output is correct
12 Correct 13 ms 45656 KB Output is correct
13 Execution timed out 8026 ms 152708 KB Time limit exceeded
14 Halted 0 ms 0 KB -