제출 #83914

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
83914		nikolapesic2802	로봇 (IOI13_robots)	C++14	100 / 100	2007 ms	12852 KiB

robots

/*
    - Binary search for the answer, and greedily check if we can collect all the items in the given amount of seconds.
    - The check can be done in T*log T so the total complexity is T*log^2 T
*/
#include <bits/stdc++.h>
#include "robots.h"
#define pb push_back
using namespace std;
pair<int,int> maxx=make_pair(INT_MAX,INT_MAX);
int putaway(int a, int b, int t, int x[], int y[], int W[], int S[]) {
    sort(x,x+a);
    sort(y,y+b);
    reverse(y,y+b);
    vector<pair<int,int> > items(t);
    for(int i=0;i<t;i++)
    {
        items[i].first=W[i];
        items[i].second=S[i];
    }
    items.pb(maxx);
    sort(items.begin(),items.end());
    int l=1,r=t+5;
    while(l<r)
    {
        int mid=(l+r)/2;
        int j=0;
        int test=true;
        priority_queue<int> s;
        for(int i=0;i<a;i++)
        {
            while(items[j].first<x[i])
            {
                s.push(items[j].second);
                j++;
            }
            for(int k=0;k<mid;k++)
            {
                if(s.empty())
                    break;
                s.pop();
            }
        }
        for(;j<t;j++)
            s.push(items[j].second);
        for(int i=0;i<b;i++)
        {
            for(int k=0;k<mid;k++)
            {
                if(s.size()==0)
                {
                    break;
                    break;
                }
                if((s.top())<y[i])
                    s.pop();
                else
                {
                    break;
                    break;
                }
            }
        }
        if(s.size()!=0)
            test=false;
        if(test)
        {
            r=mid;
        }
        else
        {
            l=mid+1;
        }
    }
    if(l==t+5)
        return -1;
    return l;
}

• Subtask 1: 14 / 14
• Subtask 2: 14 / 14
• Subtask 3: 25 / 25
• Subtask 4: 37 / 37
• Subtask 5: 10 / 10