Submission #83211

#	Time	Username	Problem	Language	Result	Execution time	Memory
83211		qkxwsm	Rail (IOI14_rail)	C++14	30 / 100	110 ms	20992 KiB

rail

#include "rail.h"
#include <bits/stdc++.h>

using namespace std;

template<class T>
void readi(T &x)
{
	T input = 0;
	bool negative = false;
	char c = ' ';
	while (c < '-')
	{
		c = getchar();
	}
	if (c == '-')
	{
		negative = true;
		c = getchar();
	}
	while (c >= '0')
	{
		input = input * 10 + (c - '0');
		c = getchar();
	}
	if (negative)
	{
		input = -input;
	}
	x = input;
}
template<class T>
void printi(T output)
{
	if (output == 0)
	{
		putchar('0');
		return;
	}
	if (output < 0)
	{
		putchar('-');
		output = -output;
	}
	int aout[20];
	int ilen = 0;
	while(output)
	{
		aout[ilen] = ((output % 10));
		output /= 10;
		ilen++;
	}
	for (int i = ilen - 1; i >= 0; i--)
	{
		putchar(aout[i] + '0');
	}
	return;
}
template<class T>
void ckmin(T &a, T b)
{
	a = min(a, b);
}
template<class T>
void ckmax(T &a, T b)
{
	a = max(a, b);
}
long long randomize(long long mod)
{
	return ((1ll << 30) * rand() + (1ll << 15) * rand() + rand()) % mod;
}

#define MP make_pair
#define PB push_back
#define PF push_front
#define LB lower_bound
#define UB upper_bound
#define fi first
#define se second
#define debug(x) cerr << #x << " = " << x << endl;

const long double PI = 4.0 * atan(1.0);
const long double EPS = 1e-20;

#define MAGIC 347
#define SINF 10007
#define CO 1000007
#define INF 1000000007
#define BIG 1000000931
#define LARGE 1696969696967ll
#define GIANT 2564008813937411ll
#define LLINF 2696969696969696969ll
#define MAXN 5013

long long normalize(long long x, long long mod = INF)
{
	return (((x % mod) + mod) % mod);
}

typedef long long ll;
typedef long double ld;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;

int N, P;
int dist[MAXN][MAXN];

int query(int x, int y)
{
	if (x > y) swap(x, y);
	return (x == y ? 0 : (dist[x][y] ? dist[x][y] : dist[x][y] = getDistance(x, y)));
}

void findLocation(int n, int first, int location[], int stype[])
{
	N = n;
	//let's say we know all the answers to 0
	stype[0] = 1;
	location[0] = first;
	if (N == 1)
	{
		return;
	}
	int A = -1, D;
	D = INF;
	for (int i = 0; i < N; i++)
	{
		if (i == 0) continue;
		int cur = query(0, i);
		if (cur < D)
		{
			A = i;
			D = cur;
		}
	}
	stype[A] = 2;
	location[A] = location[0] + D;
	vector<pii> rt, lt;
	for (int i = 0; i < N; i++)
	{
		if (i == 0 || i == A) continue;
 		if (query(A, i) > query(0, i))
		{
			//it's to the right
			rt.PB({query(0, i) - D, i});
		}
		else if (query(A, i) < D)
		{
			stype[i] = 1;
			location[i] = location[A] - query(A, i);
		}
		else
		{
			//it's to the left
			lt.PB({query(A, i) - D, i});
		}
	}
	sort(rt.begin(), rt.end());
	int rec = A;
	for (pii p : rt)
	{
		int idx = p.se;
		if (query(0, idx) == query(0, rec) + query(rec, idx))
		{
			location[idx] = location[rec] - query(rec, idx);
			stype[idx] = 1;
		}
		else
		{
			location[idx] = location[0] + query(0, idx);
			stype[idx] = 2;
			rec = idx;
		}
	}
	sort(lt.begin(), lt.end());
	rec = 0;
	for (pii p : lt)
	{
		int idx = p.se;
		if (query(A, idx) == query(A, rec) + query(rec, idx))
		{
			location[idx] = location[rec] + query(rec, idx);
			stype[idx] = 2;
		}
		else
		{
			location[idx] = location[A] - query(A, idx);
			stype[idx] = 1;
			rec = idx;
		}
	}
	// for (int i = 0; i < N; i++)
	// {
	// 	cerr << stype[i] << ' ' << location[i] << endl;
	// }
	//for a given 0: you can find the next 1
	//1 for type C, 2 for type D, 0 for nothing!
}
/*
4 4
1 2
2 5
1 3
1 1
*/

• Subtask 1: 8 / 8
• Subtask 2: 22 / 22
• Subtask 3: 0 / 26
• Subtask 4: 0 / 44