이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
#define rep(a, b) for(ll a = 0; a < (b); ++a)
#define st first
#define nd second
#define pb push_back
#define all(a) a.begin(), a.end()
const ll INF=1e18+7;
const int LIM=2e5+7;
ll T[LIM], dp[LIM], kiedy[LIM], x, n, m, w, t;
pair<ll,ll>P[LIM];
int main() {
ios_base::sync_with_stdio(0); cin.tie(0);
cin >> x >> n >> m >> w >> t;
rep(i, n) cin >> T[i];
T[n]=x; ++n;
rep(i, m) cin >> P[i].st >> P[i].nd;
sort(T, T+n);
sort(P, P+m);
rep(i, m) kiedy[i]=INF;
rep(i, n) {
ll po=0, ko=m-1;
while(po<ko) {
ll sr=(po+ko+1)/2;
if(P[sr].st>T[i]%t) ko=sr-1; else po=sr;
}
if(P[po].st>T[i]%t) continue;
kiedy[po]=min(kiedy[po], T[i]/t);
}
rep(i, m+1) {
ll ile=w*(x/t);
if(x%t>P[i].st) ile+=w;
dp[i]=ile;
if(i) dp[i]+=dp[i-1];
if(kiedy[i]==INF) continue;
ll sumc=0;
for(ll j=i-1; j>=0; --j) {
sumc+=P[j+1].nd;
dp[i]=min(dp[i], dp[j]+sumc+(i-j)*kiedy[i]*w);
}
sumc+=P[0].nd;
dp[i]=min(dp[i], sumc+(i+1)*kiedy[i]*w);
}
cout << dp[m-1]+w*(x/t+1) << '\n';
}
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