답안 #815600

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
815600 2023-08-08T17:17:11 Z t6twotwo 사탕 분배 (IOI21_candies) C++17
38 / 100
5000 ms 27884 KB
#include "candies.h"
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
constexpr ll inf = 1e18;
vector<ll> mn, mn2, mx, mx2, lazy;
void apply_add(int p, ll v) {
    lazy[p] += v;
    mn[p] += v;
    mx[p] += v;
    if (mn2[p] != inf) {
        mn2[p] += v;
    }
    if (mx2[p] != -inf) {
        mx2[p] += v;
    }
}
void apply_upd(int p, ll cmn, ll cmx) {
    if (cmn == cmx) {
        mn[p] = mx[p] = cmn;
        mn2[p] = inf;
        mx2[p] = -inf;
    } else {
        if (cmn < mx[p]) {
            if (mn[p] == mx[p]) {
                mn[p] = cmn;
            }
            if (mn2[p] == mx[p]) {
                mn2[p] = cmn;
            }
            mx[p] = cmn;
        }
        if (cmx > mn[p]) {
            if (mx[p] == mn[p]) {
                mx[p] = cmx;
            }
            if (mx2[p] == mn[p]) {
                mx2[p] = cmx;
            }
            mn[p] = cmx;
        }
    }
}
void push_add(int p) {
    apply_add(p * 2, lazy[p]);
    apply_add(p * 2 + 1, lazy[p]);
    lazy[p] = 0;
}
void push_upd(int p) {
    apply_upd(p * 2, mx[p], mn[p]);
    apply_upd(p * 2 + 1, mx[p], mn[p]);
}
void pull(int p) {
    int l = p * 2;
    int r = p * 2 + 1;
    mx[p] = max(mx[l], mx[r]);
    mn[p] = min(mn[l], mn[r]);
    mx2[p] = max(mx[p] == mx[l] ? mx2[l] : mx[l], mx[p] == mx[r] ? mx2[r] : mx[r]);
    mn2[p] = min(mn[p] == mn[l] ? mn2[l] : mn[l], mn[p] == mn[r] ? mn2[r] : mn[r]);
}
void add(int p, int l, int r, int L, int R, int v) {
    if (R <= l || r <= L) {
        return;
    }
    if (L <= l && r <= R) {
        apply_add(p, v);
        return;
    }
    int m = (l + r + 1) / 2;
    push_add(p);
    push_upd(p);
    add(p * 2, l, m, L, R, v);
    add(p * 2 + 1, m, r, L, R, v);
    pull(p);
}
void upd(int p, int l, int r, int L, int R, ll v, bool f) {
    if (R <= l || r <= L || (!f && v >= mx[p]) || (f && v <= mn[p])) {
        return;
    }
    if (L <= l && r <= R && (mn[p] == mx[p] || (!f && v > mx2[p]) || (f && v < mn2[p]))) {
        if (f) {
            apply_upd(p, inf, v);
        } else {
            apply_upd(p, v, -inf);
        }
        return;
    }
    int m = (l + r + 1) / 2;
    push_add(p);
    push_upd(p);
    upd(p * 2, l, m, L, R, v, f);
    upd(p * 2 + 1, m, r, L, R, v, f);
    pull(p);
}
vector<int> distribute_candies(vector<int> C, vector<int> L, vector<int> R, vector<int> V) {
    for (int &x : R) {
        x++;
    }
    int N = C.size(), Q = V.size();
    if (N <= 2000 && Q <= 2000) {
        vector<int> A(N);
        for (int i = 0; i < Q; i++) {
            for (int j = L[i]; j < R[i]; j++) {
                A[j] += V[i];
                A[j] = max(A[j], 0);
                A[j] = min(A[j], C[j]);
            }
        }
        return A;
    }
    if (*min_element(V.begin(), V.end()) > 0) {
        vector<ll> s(N + 1);
        for (int i = 0; i < Q; i++) {
            s[L[i]] += V[i];
            s[R[i]] -= V[i];
        }
        vector<int> A(N);
        for (int i = 0; i < N; i++) {
            A[i] = min((ll)C[i], s[i]);
            s[i + 1] += s[i];
        }
        return A;
    }
    int M = 2 << __lg(N - 1);
    if (L == vector(Q, 0) && R == vector(Q, N)) {
        vector<int> ord(N);
        iota(ord.begin(), ord.end(), 0);
        sort(ord.begin(), ord.end(), [&](int i, int j) {
            return C[i] < C[j];
        });
        vector<int> st(2 * M), df(2 * M), lz(2 * M, -1);
        vector<ll> sum(2 * M);
        auto pull = [&](int i) {
            st[i] = max(st[i * 2], st[i * 2 + 1]);
            df[i] = max(df[i * 2], df[i * 2 + 1]);
        };
        auto apply = [&](int p, int l, int r, int v, ll s) {
            if (v == 0) {
                st[p] = 0;
                df[p] = C[ord[min(r, N) - 1]];
            } else if (v == 1) {
                st[p] = C[ord[min(r, N) - 1]];
                df[p] = 0;
            }
            st[p] += s;
            df[p] -= s;
            if (v != -1) {
                lz[p] = v;
                sum[p] = s;
            } else {
                sum[p] += s;
            }
        };
        auto push = [&](int p, int l, int r) {
            int m = (l + r + 1) / 2;
            apply(p * 2, l, m, lz[p], sum[p]);
            apply(p * 2 + 1, m, r, lz[p], sum[p]);
            lz[p] = -1;
            sum[p] = 0;
        };
        auto upd = [&](auto upd, int p, int l, int r, int L, int R, int f, int v) -> void {
            if (R <= l || r <= L) {
                return;
            }
            if (l + 1 == r) {
                if (f == 0) {
                    st[p] = 0;
                    df[p] = C[ord[l]];
                } else if (f == 1) {
                    st[p] = C[ord[l]];
                    df[p] = 0;
                } else {
                    st[p] += v;
                    df[p] -= v;
                }
                return;
            }
            // if (L <= l && r <= R) {
            //     if (f == 0) {
            //         apply(p, l, r, 0, 0);
            //     } else if (f == 1) {
            //         apply(p, l, r, 1, 0);
            //     } else {
            //         apply(p, l, r, -1, v);
            //     }
            //     return;
            // }
            int m = (l + r + 1) / 2;
            push(p, l, r);
            upd(upd, p * 2, l, m, L, R, f, v);
            upd(upd, p * 2 + 1, m, r, L, R, f, v);
            pull(p);
        };
        auto find = [&](auto find, int p, int l, int r, int v, vector<int> &s) -> int {
            if (l + 1 == r) {
                return l;
            }
            int m = (l + r + 1) / 2;
            if (s[p * 2] >= v) {
                return find(find, p * 2, l, m, v, s);
            } else {
                return find(find, p * 2 + 1, m, r, v, s);
            }
        };
        for (int i = 0; i < N; i++) {
            df[i + M] = C[ord[i]];
        }
        for (int i = M - 1; i; i--) {
            pull(i);
        }
        for (int i = 0; i < Q; i++) {
            if (V[i] < 0) {
                int f = st[1] < -V[i] ? N : find(find, 1, 0, M, -V[i], st);
                upd(upd, 1, 0, M, 0, f, 0, 0);
                upd(upd, 1, 0, M, f, N, 2, V[i]);
            } else {
                int f = df[1] < V[i] ? N : find(find, 1, 0, M, V[i], df);
                upd(upd, 1, 0, M, 0, f, 1, 0);
                upd(upd, 1, 0, M, f, N, 2, V[i]);
            }
        }
        vector<int> ans(N);
        auto qry = [&](auto qry, int p, int l, int r) -> void {
            if (l + 1 == r) {
                ans[ord[l]] = st[p];
                return;
            }
            int m = (l + r + 1) / 2;
            push(p, l, r);
            qry(qry, p * 2, l, m);
            qry(qry, p * 2 + 1, m, r);
        };
        qry(qry, 1, 0, M);
        return ans;
    }
    mn.resize(2 * M, 0);
    mx.resize(2 * M, 0);
    mn2.resize(2 * M, inf);
    mx2.resize(2 * M, -inf);
    lazy.resize(2 * M);
    for (int i = 0; i < Q; i++) {
        add(1, 0, M, L[i], R[i], V[i]);
        if (V[i] > 0) {
            upd(1, 0, M, L[i], R[i], C[0], 0);
        } else {
            upd(1, 0, M, L[i], R[i], 0, 1);
        }
    }
    for (int i = 1; i < M; i++) {
        push_add(i);
        push_upd(i);
    }
    vector<int> ans(N);
    for (int i = 0; i < N; i++) {
        ans[i] = mx[i + M];
    }
    return ans;
}
# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 212 KB Output is correct
2 Correct 1 ms 212 KB Output is correct
3 Correct 1 ms 340 KB Output is correct
4 Correct 1 ms 340 KB Output is correct
5 Correct 4 ms 340 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 82 ms 8808 KB Output is correct
2 Correct 79 ms 8888 KB Output is correct
3 Correct 78 ms 8808 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 212 KB Output is correct
2 Correct 159 ms 5724 KB Output is correct
3 Correct 56 ms 24272 KB Output is correct
4 Correct 432 ms 27880 KB Output is correct
5 Correct 527 ms 27880 KB Output is correct
6 Correct 712 ms 27884 KB Output is correct
7 Correct 695 ms 27880 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 212 KB Output is correct
2 Correct 0 ms 212 KB Output is correct
3 Execution timed out 5040 ms 6504 KB Time limit exceeded
4 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 212 KB Output is correct
2 Correct 1 ms 212 KB Output is correct
3 Correct 1 ms 340 KB Output is correct
4 Correct 1 ms 340 KB Output is correct
5 Correct 4 ms 340 KB Output is correct
6 Correct 82 ms 8808 KB Output is correct
7 Correct 79 ms 8888 KB Output is correct
8 Correct 78 ms 8808 KB Output is correct
9 Correct 1 ms 212 KB Output is correct
10 Correct 159 ms 5724 KB Output is correct
11 Correct 56 ms 24272 KB Output is correct
12 Correct 432 ms 27880 KB Output is correct
13 Correct 527 ms 27880 KB Output is correct
14 Correct 712 ms 27884 KB Output is correct
15 Correct 695 ms 27880 KB Output is correct
16 Correct 0 ms 212 KB Output is correct
17 Correct 0 ms 212 KB Output is correct
18 Execution timed out 5040 ms 6504 KB Time limit exceeded
19 Halted 0 ms 0 KB -