답안 #815579

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
815579 2023-08-08T17:05:29 Z t6twotwo 사탕 분배 (IOI21_candies) C++17
38 / 100
5000 ms 27884 KB
#include "candies.h"
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
constexpr ll inf = 1e18;
vector<ll> mn, mn2, mx, mx2, lazy;
void apply_add(int p, ll v) {
    lazy[p] += v;
    mn[p] += v;
    mx[p] += v;
    if (mn2[p] != inf) {
        mn2[p] += v;
    }
    if (mx2[p] != -inf) {
        mx2[p] += v;
    }
}
void apply_upd(int p, ll cmn, ll cmx) {
    if (cmn == cmx) {
        mn[p] = mx[p] = cmn;
        mn2[p] = inf;
        mx2[p] = -inf;
    } else {
        if (cmn < mx[p]) {
            if (mn[p] == mx[p]) {
                mn[p] = cmn;
            }
            if (mn2[p] == mx[p]) {
                mn2[p] = cmn;
            }
            mx[p] = cmn;
        }
        if (cmx > mn[p]) {
            if (mx[p] == mn[p]) {
                mx[p] = cmx;
            }
            if (mx2[p] == mn[p]) {
                mx2[p] = cmx;
            }
            mn[p] = cmx;
        }
    }
}
void push_add(int p) {
    apply_add(p * 2, lazy[p]);
    apply_add(p * 2 + 1, lazy[p]);
    lazy[p] = 0;
}
void push_upd(int p) {
    apply_upd(p * 2, mx[p], mn[p]);
    apply_upd(p * 2 + 1, mx[p], mn[p]);
}
void pull(int p) {
    int l = p * 2;
    int r = p * 2 + 1;
    mx[p] = max(mx[l], mx[r]);
    mn[p] = min(mn[l], mn[r]);
    mx2[p] = max(mx[p] == mx[l] ? mx2[l] : mx[l], mx[p] == mx[r] ? mx2[r] : mx[r]);
    mn2[p] = min(mn[p] == mn[l] ? mn2[l] : mn[l], mn[p] == mn[r] ? mn2[r] : mn[r]);
}
void add(int p, int l, int r, int L, int R, int v) {
    if (R <= l || r <= L) {
        return;
    }
    if (L <= l && r <= R) {
        apply_add(p, v);
        return;
    }
    int m = (l + r + 1) / 2;
    push_add(p);
    push_upd(p);
    add(p * 2, l, m, L, R, v);
    add(p * 2 + 1, m, r, L, R, v);
    pull(p);
}
void upd(int p, int l, int r, int L, int R, ll v, bool f) {
    if (R <= l || r <= L || (!f && v >= mx[p]) || (f && v <= mn[p])) {
        return;
    }
    if (L <= l && r <= R && (mn[p] == mx[p] || (!f && v > mx2[p]) || (f && v < mn2[p]))) {
        if (f) {
            apply_upd(p, inf, v);
        } else {
            apply_upd(p, v, -inf);
        }
        return;
    }
    int m = (l + r + 1) / 2;
    push_add(p);
    push_upd(p);
    upd(p * 2, l, m, L, R, v, f);
    upd(p * 2 + 1, m, r, L, R, v, f);
    pull(p);
}
vector<int> distribute_candies(vector<int> C, vector<int> L, vector<int> R, vector<int> V) {
    for (int &x : R) {
        x++;
    }
    int N = C.size(), Q = V.size();
    if (N <= 2000 && Q <= 2000) {
        vector<int> A(N);
        for (int i = 0; i < Q; i++) {
            for (int j = L[i]; j < R[i]; j++) {
                A[j] += V[i];
                A[j] = max(A[j], 0);
                A[j] = min(A[j], C[j]);
            }
        }
        return A;
    }
    if (*min_element(V.begin(), V.end()) > 0) {
        vector<ll> s(N + 1);
        for (int i = 0; i < Q; i++) {
            s[L[i]] += V[i];
            s[R[i]] -= V[i];
        }
        vector<int> A(N);
        for (int i = 0; i < N; i++) {
            A[i] = min((ll)C[i], s[i]);
            s[i + 1] += s[i];
        }
        return A;
    }
    int M = 2 << __lg(N - 1);
    if (L == vector(Q, 0) && R == vector(Q, N)) {
        vector<int> ord(N);
        iota(ord.begin(), ord.end(), 0);
        sort(ord.begin(), ord.end(), [&](int i, int j) {
            return C[i] < C[j];
        });
        vector<int> st(2 * M), df(2 * M);
        auto pull = [&](int i) {
            st[i] = max(st[i * 2], st[i * 2 + 1]);
            df[i] = max(df[i * 2], df[i * 2 + 1]);
        };
        auto upd = [&](auto upd, int p, int l, int r, int L, int R, int f, int v) -> void {
            if (R <= l || r <= L) {
                return;
            }
            if (l + 1 == r) {
                assert(p - M == l);
                if (f == 0) {
                    st[p] = 0;
                    df[p] = C[ord[l]];
                } else if (f == 1) {
                    st[p] = C[ord[l]];
                    df[p] = 0;
                } else {
                    st[p] += v;
                    df[p] -= v;
                }
                return;
            }
            int m = (l + r + 1) / 2;
            upd(upd, p * 2, l, m, L, R, f, v);
            upd(upd, p * 2 + 1, m, r, L, R, f, v);
            pull(p);
        };
        auto find = [&](auto find, int p, int l, int r, int v, vector<int> &s) -> int {
            if (l + 1 == r) {
                return l;
            }
            int m = (l + r + 1) / 2;
            if (s[p * 2] >= v) {
                return find(find, p * 2, l, m, v, s);
            } else {
                return find(find, p * 2 + 1, m, r, v, s);
            }
        };
        for (int i = 0; i < N; i++) {
            df[i + M] = C[ord[i]];
        }
        for (int i = M - 1; i; i--) {
            pull(i);
        }
        for (int i = 0; i < Q; i++) {
            if (V[i] < 0) {
                int f = st[1] < -V[i] ? N : find(find, 1, 0, M, -V[i], st);
                upd(upd, 1, 0, M, 0, f, 0, 0);
                upd(upd, 1, 0, M, f, N, 2, V[i]);
            } else {
                int f = df[1] < V[i] ? N : find(find, 1, 0, M, V[i], df);
                upd(upd, 1, 0, M, 0, f, 1, 0);
                upd(upd, 1, 0, M, f, N, 2, V[i]);
            }
        }
        auto qry = [&](auto qry, int p, int l, int r) -> void {
            if (l + 1 == r) {
                return;
            }
            int m = (l + r + 1) / 2;
            // push(p, l, r);
            qry(qry, p * 2, l, m);
            qry(qry, p * 2 + 1, m, r);
        };
        qry(qry, 1, 0, M);
        vector<int> ans(N);
        for (int i = 0; i < N; i++) {
            ans[ord[i]] = st[i + M];
        }
        return ans;
    }
    mn.resize(2 * M, 0);
    mx.resize(2 * M, 0);
    mn2.resize(2 * M, inf);
    mx2.resize(2 * M, -inf);
    lazy.resize(2 * M);
    for (int i = 0; i < Q; i++) {
        add(1, 0, M, L[i], R[i], V[i]);
        if (V[i] > 0) {
            upd(1, 0, M, L[i], R[i], C[0], 0);
        } else {
            upd(1, 0, M, L[i], R[i], 0, 1);
        }
    }
    for (int i = 1; i < M; i++) {
        push_add(i);
        push_upd(i);
    }
    vector<int> ans(N);
    for (int i = 0; i < N; i++) {
        ans[i] = mx[i + M];
    }
    return ans;
}
# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 212 KB Output is correct
2 Correct 0 ms 212 KB Output is correct
3 Correct 1 ms 340 KB Output is correct
4 Correct 1 ms 340 KB Output is correct
5 Correct 3 ms 340 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 82 ms 8892 KB Output is correct
2 Correct 83 ms 8816 KB Output is correct
3 Correct 93 ms 8896 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 212 KB Output is correct
2 Correct 157 ms 5708 KB Output is correct
3 Correct 58 ms 24372 KB Output is correct
4 Correct 418 ms 27884 KB Output is correct
5 Correct 497 ms 27880 KB Output is correct
6 Correct 693 ms 27876 KB Output is correct
7 Correct 677 ms 27880 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 212 KB Output is correct
2 Correct 1 ms 212 KB Output is correct
3 Execution timed out 5040 ms 6504 KB Time limit exceeded
4 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 212 KB Output is correct
2 Correct 0 ms 212 KB Output is correct
3 Correct 1 ms 340 KB Output is correct
4 Correct 1 ms 340 KB Output is correct
5 Correct 3 ms 340 KB Output is correct
6 Correct 82 ms 8892 KB Output is correct
7 Correct 83 ms 8816 KB Output is correct
8 Correct 93 ms 8896 KB Output is correct
9 Correct 0 ms 212 KB Output is correct
10 Correct 157 ms 5708 KB Output is correct
11 Correct 58 ms 24372 KB Output is correct
12 Correct 418 ms 27884 KB Output is correct
13 Correct 497 ms 27880 KB Output is correct
14 Correct 693 ms 27876 KB Output is correct
15 Correct 677 ms 27880 KB Output is correct
16 Correct 0 ms 212 KB Output is correct
17 Correct 1 ms 212 KB Output is correct
18 Execution timed out 5040 ms 6504 KB Time limit exceeded
19 Halted 0 ms 0 KB -