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답안 #814886

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
814886 2023-08-08T10:55:02 Z qwerasdfzxcl Posters on the wall (CPSPC17_posters) C++17
40 / 100
 1897 ms 1048576 KB 
#include <bits/stdc++.h>

using namespace std;
typedef long long ll;

constexpr int INF1 = 1e9 + 100;
ll X1[50050], Y1[50050], X2[50050], Y2[50050];
ll X3[50050], Y3[50050], X4[50050], Y4[50050];

ll ans[50050];

vector<ll> X, Y;

inline int getidx(const vector<ll> &a, ll x){return lower_bound(a.begin(), a.end(), x) - a.begin();}

struct PST1{
	
	struct Node{
		ll x, lazy;
		int l, r, t;
		Node(){}
		Node(ll _x, ll _la, int _l, int _r, int _t): x(_x), lazy(_la), l(_l), r(_r), t(_t) {}
	};

	Node tree[10001000];
	int root[200200], X[200200];
	int sz, szT, szR;

	void init(int n){
		sz = n;
		tree[0] = Node(0, 0, 0, 0, 0);
		root[0] = 0;
		X[0] = 0;

		szT = szR = 1;
	}

	int cp(int x, int t){
		tree[szT++] = tree[x];
		tree[szT-1].t = t;
		return szT-1;
	}

	void propagate(int i, int l, int r){
		if (l!=r){
			if (tree[tree[i].l].t != tree[i].t) tree[i].l = cp(tree[i].l, tree[i].t);
			if (tree[tree[i].r].t != tree[i].t) tree[i].r = cp(tree[i].r, tree[i].t);
		}

		if (tree[i].lazy==0) return;
		tree[i].x += tree[i].lazy * (Y[r+1] - Y[l]);

		if (l!=r){
			tree[tree[i].l].lazy += tree[i].lazy;
			tree[tree[i].r].lazy += tree[i].lazy;
		}

		tree[i].lazy = 0;
	}

	void update(int i, int l, int r, int s, int e, ll x){
		propagate(i, l, r);
		if (r<s || e<l) return;

		if (s<=l && r<=e){
			tree[i].lazy += x;
			propagate(i, l, r);
			return;
		}

		int m = (l+r)>>1;
		update(tree[i].l, l, m, s, e, x);
		update(tree[i].r, m+1, r, s, e, x);
		tree[i].x = tree[tree[i].l].x + tree[tree[i].r].x;
	}

	ll query(int i, int l, int r, int s, int e){
		if (r<s || e<l) return 0;
		propagate(i, l, r);

		if (s<=l && r<=e){
			return tree[i].x;
		} 

		int m = (l+r)>>1;
		return query(tree[i].l, l, m, s, e) + query(tree[i].r, m+1, r, s, e);
	}

	int add(){
		root[szR] = cp(root[szR-1], szR);
		szR++;
		return root[szR-1];
	}

	void update(int t, int s, int e, ll x){
		X[szR] = t;
		update(add(), 1, sz, s, e, x);
	}

	ll query(int t, int s, int e){
		t = upper_bound(X+1, X+szR, t) - X - 1;
		return query(root[t], 1, sz, s, e);
	}

}tree1;

pair<ll, ll> operator + (const pair<ll, ll> &a, const pair<ll, ll> &b){return {a.first + b.first, a.second + b.second};}

struct PST2{

	struct Node{
		ll ofs, cnt;
		ll lazyofs;
		int lazycnt, l, r, t;
		Node(){}
		Node(ll _ofs, ll _cnt, ll _lofs, int _lcnt, int _l, int _r, int _t): ofs(_ofs), cnt(_cnt), lazyofs(_lofs), lazycnt(_lcnt), l(_l), r(_r), t(_t) {}
	};

	Node tree[20002000];
	int root[200200], X[200200];
	int sz, szT, szR;

	void init(int n){
		sz = n;
		tree[0] = Node(0, 0, 0, -1, 0, 0, 0);
		root[0] = 0;
		X[0] = -INF1;

		szT = szR = 1;
	}

	int cp(int x, int t){
		tree[szT++] = tree[x];
		tree[szT-1].t = t;
		return szT-1;
	}

	void propagate(int i, int l, int r){
		if (l!=r){
			if (tree[tree[i].l].t != tree[i].t) tree[i].l = cp(tree[i].l, tree[i].t);
			if (tree[tree[i].r].t != tree[i].t) tree[i].r = cp(tree[i].r, tree[i].t);
		}

		if (tree[i].lazycnt==-1) return;
		if (tree[i].lazycnt==0) tree[i].ofs = 0, tree[i].cnt = 0;
		else tree[i].ofs = tree[i].lazyofs * (Y[r+1]-Y[l]), tree[i].cnt = Y[r+1] - Y[l];

		if (l!=r){
			tree[tree[i].l].lazycnt = tree[i].lazycnt;
			tree[tree[i].l].lazyofs = tree[i].lazyofs;
			tree[tree[i].r].lazycnt = tree[i].lazycnt;
			tree[tree[i].r].lazyofs = tree[i].lazyofs;
		}

		tree[i].lazyofs = 0;
		tree[i].lazycnt = -1;
	}

	void update(int i, int l, int r, int s, int e, ll ofs, int typ){
		propagate(i, l, r);
		if (r<s || e<l) return;

		if (s<=l && r<=e){
			tree[i].lazyofs = ofs;
			tree[i].lazycnt = typ;
			propagate(i, l, r);
			return;
		}

		int m = (l+r)>>1;
		update(tree[i].l, l, m, s, e, ofs, typ);
		update(tree[i].r, m+1, r, s, e, ofs, typ);
		tree[i].ofs = tree[tree[i].l].ofs + tree[tree[i].r].ofs;
		tree[i].cnt = tree[tree[i].l].cnt + tree[tree[i].r].cnt;
	}

	pair<ll, ll> query(int i, int l, int r, int s, int e){
		if (r<s || e<l) return {0, 0};
		propagate(i, l, r);

		if (s<=l && r<=e){
			return {tree[i].ofs, tree[i].cnt};
		} 

		int m = (l+r)>>1;
		return query(tree[i].l, l, m, s, e) + query(tree[i].r, m+1, r, s, e);
	}

	int add(){
		root[szR] = cp(root[szR-1], szR);
		szR++;
		return root[szR-1];
	}

	void update(int t, int s, int e, ll ofs, int typ){
		X[szR] = t;
		update(add(), 1, sz, s, e, ofs, typ);
	}

	pair<ll, ll> query(int t, int s, int e){
		t = upper_bound(X+1, X+szR, t) - X - 1;
		return query(root[t], 1, sz, s, e);
	}

}tree2;


int main(){
	int r, c, n, q, MOD;
	scanf("%d %d %d %d %d", &r, &c, &n, &q, &MOD);

	X.push_back(-INF1);
	X.push_back(INF1);
	Y.push_back(-INF1);
	Y.push_back(INF1);

	for (int i=1;i<=n;i++){
		scanf("%lld %lld %lld %lld", X1+i, Y1+i, X2+i, Y2+i);
		if (X1[i] > X2[i]) swap(X1[i], X2[i]);
		if (Y1[i] > Y2[i]) swap(Y1[i], Y2[i]);

		X.push_back(X1[i]);
		X.push_back(X2[i]);
		Y.push_back(Y1[i]);
		Y.push_back(Y2[i]);
	}

	sort(X.begin(), X.end());
	X.erase(unique(X.begin(), X.end()), X.end());

	sort(Y.begin(), Y.end());
	Y.erase(unique(Y.begin(), Y.end()), Y.end());

	vector<array<ll, 3>> E;

	for (int i=1;i<=n;i++){
		X1[i] = getidx(X, X1[i]);
		X2[i] = getidx(X, X2[i]);
		Y1[i] = getidx(Y, Y1[i]);
		Y2[i] = getidx(Y, Y2[i]);

		if (X1[i]==X2[i]) continue;

		E.push_back({X[X1[i]], 2, i});
		E.push_back({X[X2[i]], 1, i});
	}

	sort(E.begin(), E.end());
	int sz = (int)Y.size()-2;
	assert(sz >= 1);
	tree1.init(sz);
	tree2.init(sz);

	for (auto &[x, op, i]:E){
		if (op==2){
			tree2.update(x, Y1[i], Y2[i]-1, -X[X1[i]], 1);
		}

		else if (op==1){ // 삭제 먼저
			tree2.update(x, Y1[i], Y2[i]-1, 0, 0);
			tree1.update(x, Y1[i], Y2[i]-1, X[X2[i]] - X[X1[i]]);
		}
	}

	ll pans = 0;
	for (int i=1;i<=q;i++){
		int v;
		scanf("%lld %lld %lld %lld %d", X3+i, Y3+i, X4+i, Y4+i, &v);

		pans %= MOD;
		X3[i] = (X3[i] + pans * v) % MOD;
		X4[i] = (X4[i] + pans * v) % MOD;
		Y3[i] = (Y3[i] + pans * v) % MOD;
		Y4[i] = (Y4[i] + pans * v) % MOD;
		if (X3[i] > X4[i]) swap(X3[i], X4[i]);
		if (Y3[i] > Y4[i]) swap(Y3[i], Y4[i]);
		
		{
		int op = 3;
		int x = X3[i];
		int l = upper_bound(Y.begin(), Y.end(), Y3[i]) - Y.begin() - 1;
		int r = lower_bound(Y.begin(), Y.end(), Y4[i]) - Y.begin();

		ll S = tree1.query(x, l, r-1);
		ll tmpl = tree1.query(x, l, l) / (Y[l+1] - Y[l]);
		ll tmpr = tree1.query(x, r-1, r-1) / (Y[r] - Y[r-1]);
		S += tmpl * (-Y3[i] + Y[l]) + tmpr * (-Y[r] + Y4[i]);

		auto [ofs, cnt] = tree2.query(x, l, r-1);
		auto [ofsl, cntl] = tree2.query(x, l, l);
		auto [ofsr, cntr] = tree2.query(x, r-1, r-1);

		ofsl /= (Y[l+1] - Y[l]), cntl /= (Y[l+1] - Y[l]);
		ofsr /= (Y[r] - Y[r-1]), cntr /= (Y[r] - Y[r-1]);

		ofs += ofsl * (-Y3[i] + Y[l]), cnt += cntl * (-Y3[i] + Y[l]);
		ofs += ofsr * (-Y[r] + Y4[i]), cnt += cntr * (-Y[r] + Y4[i]);

		if (op==3) S += cnt * X3[i] + ofs;
		else S += cnt * X4[i] + ofs;

		if (op==3) S = -S;
		ans[i] += S;
		}


		{
		int op = 4;
		int x = X4[i];
		int l = upper_bound(Y.begin(), Y.end(), Y3[i]) - Y.begin() - 1;
		int r = lower_bound(Y.begin(), Y.end(), Y4[i]) - Y.begin();

		ll S = tree1.query(x, l, r-1);
		ll tmpl = tree1.query(x, l, l) / (Y[l+1] - Y[l]);
		ll tmpr = tree1.query(x, r-1, r-1) / (Y[r] - Y[r-1]);
		S += tmpl * (-Y3[i] + Y[l]) + tmpr * (-Y[r] + Y4[i]);

		auto [ofs, cnt] = tree2.query(x, l, r-1);
		auto [ofsl, cntl] = tree2.query(x, l, l);
		auto [ofsr, cntr] = tree2.query(x, r-1, r-1);

		ofsl /= (Y[l+1] - Y[l]), cntl /= (Y[l+1] - Y[l]);
		ofsr /= (Y[r] - Y[r-1]), cntr /= (Y[r] - Y[r-1]);

		ofs += ofsl * (-Y3[i] + Y[l]), cnt += cntl * (-Y3[i] + Y[l]);
		ofs += ofsr * (-Y[r] + Y4[i]), cnt += cntr * (-Y[r] + Y4[i]);

		if (op==3) S += cnt * X3[i] + ofs;
		else S += cnt * X4[i] + ofs;

		if (op==3) S = -S;
		ans[i] += S;
		}

		pans = ans[i];
	}

	for (int i=1;i<=q;i++) printf("%lld\n", ans[i]);

}

Compilation message

Main.cpp: In function 'int main()':
Main.cpp:210:7: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
  210 |  scanf("%d %d %d %d %d", &r, &c, &n, &q, &MOD);
      |  ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Main.cpp:218:8: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
  218 |   scanf("%lld %lld %lld %lld", X1+i, Y1+i, X2+i, Y2+i);
      |   ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Main.cpp:268:8: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
  268 |   scanf("%lld %lld %lld %lld %d", X3+i, Y3+i, X4+i, Y4+i, &v);
      |   ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Subtask #1
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 6 ms 3540 KB Output is correct
2 Correct 4 ms 3708 KB Output is correct
3 Correct 4 ms 3924 KB Output is correct

Subtask #2
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 6 ms 3540 KB Output is correct
2 Correct 4 ms 3708 KB Output is correct
3 Correct 4 ms 3924 KB Output is correct
4 Correct 89 ms 58548 KB Output is correct
5 Correct 69 ms 52592 KB Output is correct
6 Correct 71 ms 57028 KB Output is correct

Subtask #3
0 / 40.0

# 결과 실행 시간 메모리 Grader output
1 Correct 6 ms 3540 KB Output is correct
2 Correct 4 ms 3708 KB Output is correct
3 Correct 4 ms 3924 KB Output is correct
4 Correct 89 ms 58548 KB Output is correct
5 Correct 69 ms 52592 KB Output is correct
6 Correct 71 ms 57028 KB Output is correct
7 Correct 424 ms 352992 KB Output is correct
8 Runtime error 1888 ms 1048576 KB Execution killed with signal 11
9 Halted 0 ms 0 KB -

Subtask #4
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 6 ms 3540 KB Output is correct
2 Correct 4 ms 3708 KB Output is correct
3 Correct 4 ms 3924 KB Output is correct
4 Correct 89 ms 58548 KB Output is correct
5 Correct 69 ms 52592 KB Output is correct
6 Correct 71 ms 57028 KB Output is correct
7 Correct 431 ms 339992 KB Output is correct
8 Correct 1372 ms 885016 KB Output is correct
9 Correct 832 ms 747012 KB Output is correct
10 Correct 1283 ms 876084 KB Output is correct
11 Correct 989 ms 737640 KB Output is correct
12 Correct 1187 ms 808336 KB Output is correct

Subtask #5
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 6 ms 3540 KB Output is correct
2 Correct 4 ms 3708 KB Output is correct
3 Correct 4 ms 3924 KB Output is correct
4 Correct 89 ms 58548 KB Output is correct
5 Correct 69 ms 52592 KB Output is correct
6 Correct 71 ms 57028 KB Output is correct
7 Correct 424 ms 352992 KB Output is correct
8 Runtime error 1888 ms 1048576 KB Execution killed with signal 11
9 Halted 0 ms 0 KB -

Subtask #6
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 345 ms 325760 KB Output is correct
2 Correct 1372 ms 866732 KB Output is correct
3 Correct 859 ms 783260 KB Output is correct
4 Correct 1252 ms 864708 KB Output is correct
5 Correct 1012 ms 733092 KB Output is correct
6 Correct 1205 ms 851152 KB Output is correct

Subtask #7
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 345 ms 325760 KB Output is correct
2 Correct 1372 ms 866732 KB Output is correct
3 Correct 859 ms 783260 KB Output is correct
4 Correct 1252 ms 864708 KB Output is correct
5 Correct 1012 ms 733092 KB Output is correct
6 Correct 1205 ms 851152 KB Output is correct
7 Correct 554 ms 489224 KB Output is correct
8 Runtime error 1897 ms 1048576 KB Execution killed with signal 11
9 Halted 0 ms 0 KB -