제출 #810436

#제출 시각아이디문제언어결과실행 시간메모리
810436WLZ사탕 분배 (IOI21_candies)C++17
0 / 100
93 ms56088 KiB
#include "candies.h" #include <bits/stdc++.h> using namespace std; using ll = long long; const ll LINF = (ll) 1e18; int SZ; vector<ll> mx, mn, lazy_add; void push_add(int idx) { if (lazy_add[idx] == 0) return; mx[idx] += lazy_add[idx]; mn[idx] += lazy_add[idx]; if (2 * idx < SZ) { lazy_add[2 * idx] += lazy_add[idx]; lazy_add[2 * idx + 1] += lazy_add[idx]; } lazy_add[idx] = 0; } void add(int idx, int cl, int cr, int l, int r, int val) { push_add(idx); if (cl > r || cr < l) return; if (l <= cl && cr <= r) { lazy_add[idx] += val; push_add(idx); return; } int mid = (cl + cr) / 2; add(2 * idx, cl, mid, l, r, val); add(2 * idx + 1, mid + 1, cr, l, r, val); mx[idx] = max(mx[2 * idx], mx[2 * idx + 1]); mn[idx] = min(mn[2 * idx], mn[2 * idx + 1]); } void max_eq(int idx, int cl, int cr, int l, int r, ll val) { push_add(idx); if (cl > r || cr < l || mn[idx] >= val) return; if (l <= cl && cr <= r && mx[idx] < val) add(idx, cl, cr, l, r, val - mx[idx]); int mid = (cl + cr) / 2; max_eq(2 * idx, cl, mid, l, r, val); max_eq(2 * idx + 1, mid + 1, cr, l, r, val); mx[idx] = max(mx[2 * idx], mx[2 * idx + 1]); mn[idx] = min(mn[2 * idx], mn[2 * idx + 1]); } void min_eq(int idx, int cl, int cr, int l, int r, ll val) { push_add(idx); if (cl > r || cr < l || mx[idx] <= val) return; if (l <= cl && cr <= r && mn[idx] > val) add(idx, cl, cr, l, r, val - mn[idx]); int mid = (cl + cr) / 2; min_eq(2 * idx, cl, mid, l, r, val); min_eq(2 * idx + 1, mid + 1, cr, l, r, val); mx[idx] = max(mx[2 * idx], mx[2 * idx + 1]); mn[idx] = min(mn[2 * idx], mn[2 * idx + 1]); } vector<int> ans; void calc_ans(int idx, int cl, int cr) { push_add(idx); if (cl == cr) { ans[cl] = mx[idx]; return; } int mid = (cl + cr) / 2; calc_ans(2 * idx, cl, mid); calc_ans(2 * idx + 1, mid + 1, cr); } int n, q; std::vector<int> distribute_candies(std::vector<int> c, std::vector<int> l, std::vector<int> r, std::vector<int> v) { n = (int) c.size(), q = (int) l.size(), SZ = 4 * n + 5; mx.assign(SZ, 0); mn.assign(SZ, 0); lazy_add.assign(SZ, 0); for (int i = 0; i < q; i++) { add(1, 0, n - 1, l[i], r[i], v[i]); max_eq(1, 0, n - 1, 0, n - 1, 0); min_eq(1, 0, n - 1, 0, n - 1, c[0]); } ans.resize(n); calc_ans(1, 0, n - 1); return ans; }
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