oj.uz

답안 #807598

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
807598 2023-08-04T20:03:48 Z alex_2008 디지털 회로 (IOI22_circuit) C++17
16 / 100
 872 ms 5200 KB 
#include "circuit.h"
#include <cmath>
#include <algorithm>
#include <vector>
#include <iostream>
using namespace std;
typedef long long ll;
int NN, MM;
const int N = 2e5 + 10, P = 1000002022;
int p[N], d[N];
int lazy[4 * N];
int a[N];
ll pref[N];
pair <ll, ll> tree[4 * N];
ll tree2[4 * N];
ll binpow(ll a, ll n) {
	if (n == 0) return 1;
	if (n % 2 == 0) {
		ll u = binpow(a, n / 2);
		return (u * u) % P;
	}
	return (a * binpow(a, n - 1)) % P;
}
bool ch = true;
void pushh(int v, int tl, int tr) {
	if (lazy[v]) {
		lazy[v] = 0;
		if (tl != tr) {
			lazy[2 * v] = (lazy[2 * v] + 1) % 2;
			lazy[2 * v + 1] = (lazy[2 * v + 1] + 1) % 2;
			swap(tree[2 * v].first, tree[2 * v].second);
			swap(tree[2 * v + 1].first, tree[2 * v + 1].second);
		}
	}
}
void build_tree(int v, int tl, int tr) {
	if (tl == tr) {
		if (a[tl] == 1) tree[v] = { 1, 0 };
		else tree[v] = { 0, 1 };
	}
	else {
		int tm = (tl + tr) / 2;
		build_tree(2 * v, tl, tm);
		build_tree(2 * v + 1, tm + 1, tr);
		ll a = tree[2 * v].first, b = tree[2 * v].second, c = tree[2 * v + 1].first, d = tree[2 * v + 1].second;
		tree[v].first = 2 * a * c + a * d + b * c;
		tree[v].second = 2 * b * d + a * d + b * c;
		tree[v].first %= P;
		tree[v].second %= P;
	}
}
void update(int v, int tl, int tr, int l, int r) {
	if (tl > r || tr < l) return;
	if (tl >= l && tr <= r) {
		lazy[v] = (lazy[v] + 1) % 2;
		swap(tree[v].first, tree[v].second);
		return;
	}
	pushh(v, tl, tr);
	int tm = (tl + tr) / 2;
	update(2 * v, tl, tm, l, r);
	update(2 * v + 1, tm + 1, tr, l, r);
	ll a = tree[2 * v].first, b = tree[2 * v].second, c = tree[2 * v + 1].first, d = tree[2 * v + 1].second;
	tree[v].first = 2 * a * c + a * d + b * c;
	tree[v].second = 2 * b * d + a * d + b * c;
	tree[v].first %= P;
	tree[v].second %= P;
}
void pushh2(int v, int tl, int tr) {
	if (lazy[v]) {
		lazy[v] = 0;
		if (tl != tr) {
			lazy[2 * v] = (lazy[2 * v] + 1) % 2;
			lazy[2 * v + 1] = (lazy[2 * v + 1] + 1) % 2;
			int tm = (tl + tr) / 2;
			ll u = pref[tm];
			if (tl) u -= pref[tl - 1];
			u %= P;
			tree2[2 * v] = (u + P - tree2[2 * v]) % P;
			u = pref[tr] - pref[tm];
			u %= P;
			tree2[2 * v + 1] = (u + P - tree2[2 * v + 1]) % P;
		}
	}
}
void build_tree2(int v, int tl, int tr) {
	if (tl == tr) {
		if (a[tl]) {
			tree2[v] = pref[tl];
			if (tl) tree2[v] -= pref[tl - 1];
		}
		tree2[v] %= P;
	}
	else {
		int tm = (tl + tr) / 2;
		build_tree2(2 * v, tl, tm);
		build_tree2(2 * v + 1, tm + 1, tr);
		tree2[v] = tree2[2 * v] + tree2[2 * v + 1];
		tree2[v] %= P;
	}
}
void update2(int v, int tl, int tr, int l, int r) {
	if (tl > r || tr < l) return;
	if (tl >= l && tr <= r) {
		lazy[v] = (lazy[v] + 1) % 2;
		ll u = pref[tr];
		if (tl) u -= pref[tl - 1];
		u %= P;
		tree2[v] = (u - tree2[v] + P) % P;
		return;
	}
	pushh2(v, tl, tr);
	int tm = (tl + tr) / 2;
	update2(2 * v, tl, tm, l, r);
	update2(2 * v + 1, tm + 1, tr, l, r);
	tree2[v] = tree2[2 * v] + tree2[2 * v + 1];
	tree2[v] %= P;
}
void init(int N, int M, std::vector<int> P, std::vector<int> A) {
	NN = N, MM = M;
	for (int i = 0; i < N + M - 1; i++) {
		p[i] = P[i];
		if (i == 0) d[0] = 0;
		if (i > 0 && p[i] != (i - 1) / 2) ch = false;
		d[i] = d[P[i]] + 1;
	}
	for (int i = 0; i < M; i++) {
		a[i] = A[i];
	}
	if (M != N + 1) ch = false;
	int u = log2(M);
	if ((1 << u) != M) ch = false;
	if (ch) build_tree(1, 0, M - 1);
	else {
		for (int i = 0; i < M; i++) {
			pref[i] = binpow(2, N - d[i + N]);
			if (i) pref[i] += pref[i - 1];
		}
		build_tree2(1, 0, M - 1);
	}
}
int count_ways(int L, int R) {
	if (ch) {
		update(1, 0, MM - 1, L - NN, R - NN);
		return tree[1].first;
	}
	else {
		update2(1, 0, MM - 1, L - NN, R - NN);
		return tree2[1];
	}
}

Subtask #1
0 / 2.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 336 KB Output is correct
2 Incorrect 0 ms 240 KB 1st lines differ - on the 1st token, expected: '1', found: '2'
3 Halted 0 ms 0 KB -

Subtask #2
0 / 7.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 336 KB Output is correct
2 Correct 1 ms 336 KB Output is correct
3 Correct 0 ms 336 KB Output is correct
4 Correct 1 ms 336 KB Output is correct
5 Correct 0 ms 336 KB Output is correct
6 Incorrect 1 ms 292 KB 1st lines differ - on the 1st token, expected: '706880838', found: '853441430'
7 Halted 0 ms 0 KB -

Subtask #3
0 / 9.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 336 KB Output is correct
2 Incorrect 0 ms 240 KB 1st lines differ - on the 1st token, expected: '1', found: '2'
3 Halted 0 ms 0 KB -

Subtask #4
4.0 / 4.0

# 결과 실행 시간 메모리 Grader output
1 Correct 433 ms 2728 KB Output is correct
2 Correct 737 ms 5172 KB Output is correct
3 Correct 740 ms 5200 KB Output is correct
4 Correct 760 ms 5168 KB Output is correct

Subtask #5
12.0 / 12.0

# 결과 실행 시간 메모리 Grader output
1 Correct 433 ms 2728 KB Output is correct
2 Correct 737 ms 5172 KB Output is correct
3 Correct 740 ms 5200 KB Output is correct
4 Correct 760 ms 5168 KB Output is correct
5 Correct 528 ms 2768 KB Output is correct
6 Correct 770 ms 5156 KB Output is correct
7 Correct 858 ms 5152 KB Output is correct
8 Correct 606 ms 5200 KB Output is correct
9 Correct 305 ms 464 KB Output is correct
10 Correct 872 ms 592 KB Output is correct
11 Correct 615 ms 592 KB Output is correct
12 Correct 627 ms 592 KB Output is correct

Subtask #6
0 / 27.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 336 KB Output is correct
2 Correct 1 ms 336 KB Output is correct
3 Correct 0 ms 336 KB Output is correct
4 Correct 1 ms 336 KB Output is correct
5 Correct 0 ms 336 KB Output is correct
6 Incorrect 1 ms 292 KB 1st lines differ - on the 1st token, expected: '706880838', found: '853441430'
7 Halted 0 ms 0 KB -

Subtask #7
0 / 28.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 336 KB Output is correct
2 Incorrect 0 ms 240 KB 1st lines differ - on the 1st token, expected: '1', found: '2'
3 Halted 0 ms 0 KB -

Subtask #8
0 / 11.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 336 KB Output is correct
2 Incorrect 0 ms 240 KB 1st lines differ - on the 1st token, expected: '1', found: '2'
3 Halted 0 ms 0 KB -