oj.uz

답안 #807594

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
807594 2023-08-04T20:01:25 Z alex_2008 디지털 회로 (IOI22_circuit) C++17
16 / 100
 859 ms 5200 KB 
#include "circuit.h"
#include <cmath>
#include <algorithm>
#include <vector>
#include <iostream>
using namespace std;
typedef long long ll;
int NN, MM;
const int N = 2e5 + 10, P = 1000002022;
int p[N], d[N];
int lazy[4 * N];
int a[N];
ll pref[N];
pair <ll, ll> tree[4 * N];
ll tree2[4 * N];
ll binpow(ll a, ll n) {
	if (n == 0) return 1;
	if (n % 2 == 0) {
		ll u = binpow(a, n / 2);
		return (u * u) % P;
	}
	return (a * binpow(a, n - 1)) % P;
}
bool ch = true;
void pushh(int v, int tl, int tr) {
	if (lazy[v]) {
		lazy[v] = 0;
		if (tl != tr) {
			lazy[2 * v] = (lazy[2 * v] + 1) % 2;
			lazy[2 * v + 1] = (lazy[2 * v + 1] + 1) % 2;
			swap(tree[2 * v].first, tree[2 * v].second);
			swap(tree[2 * v + 1].first, tree[2 * v + 1].second);
		}
	}
}
void build_tree(int v, int tl, int tr) {
	if (tl == tr) {
		if (a[tl] == 1) tree[v] = { 1, 0 };
		else tree[v] = { 0, 1 };
	}
	else {
		int tm = (tl + tr) / 2;
		build_tree(2 * v, tl, tm);
		build_tree(2 * v + 1, tm + 1, tr);
		ll a = tree[2 * v].first, b = tree[2 * v].second, c = tree[2 * v + 1].first, d = tree[2 * v + 1].second;
		tree[v].first = 2 * a * c + a * d + b * c;
		tree[v].second = 2 * b * d + a * d + b * c;
		tree[v].first %= P;
		tree[v].second %= P;
	}
}
void update(int v, int tl, int tr, int l, int r) {
	if (tl > r || tr < l) return;
	if (tl >= l && tr <= r) {
		lazy[v] = (lazy[v] + 1) % 2;
		swap(tree[v].first, tree[v].second);
		return;
	}
	pushh(v, tl, tr);
	int tm = (tl + tr) / 2;
	update(2 * v, tl, tm, l, r);
	update(2 * v + 1, tm + 1, tr, l, r);
	ll a = tree[2 * v].first, b = tree[2 * v].second, c = tree[2 * v + 1].first, d = tree[2 * v + 1].second;
	tree[v].first = 2 * a * c + a * d + b * c;
	tree[v].second = 2 * b * d + a * d + b * c;
	tree[v].first %= P;
	tree[v].second %= P;
}
void pushh2(int v, int tl, int tr) {
	if (lazy[v]) {
		lazy[v] = 0;
		if (tl != tr) {
			lazy[2 * v] = (lazy[2 * v] + 1) % 2;
			lazy[2 * v + 1] = (lazy[2 * v + 1] + 1) % 2;
			int tm = (tl + tr) / 2;
			ll u = pref[tm];
			if (tl) u -= pref[tl - 1];
			u %= P;
			tree2[2 * v] = (u + P - tree2[2 * v]) % P;
			u = pref[tr] - pref[tm];
			u %= P;
			tree2[2 * v + 1] = (u + P - tree2[2 * v + 1]) % P;
		}
	}
}
void build_tree2(int v, int tl, int tr) {
	if (tl == tr) {
		if (a[tl]) {
			tree2[v] = pref[tl];
			if (tl) tree2[v] -= pref[tl - 1];
		}
	}
	else {
		int tm = (tl + tr) / 2;
		build_tree2(2 * v, tl, tm);
		build_tree2(2 * v + 1, tm + 1, tr);
		tree2[v] = tree2[2 * v] + tree2[2 * v + 1];
		tree2[v] %= P;
	}
}
void update2(int v, int tl, int tr, int l, int r) {
	if (tl > r || tr < l) return;
	if (tl >= l && tr <= r) {
		lazy[v] = (lazy[v] + 1) % 2;
		ll u = pref[tr];
		if (tl) u -= pref[tl - 1];
		u %= P;
		tree2[v] = (u - tree2[v] + P) % P;
		return;
	}
	pushh2(v, tl, tr);
	int tm = (tl + tr) / 2;
	update2(2 * v, tl, tm, l, r);
	update2(2 * v + 1, tm + 1, tr, l, r);
	tree2[v] = tree2[2 * v] + tree2[2 * v + 1];
	tree2[v] %= P;
}
void init(int N, int M, std::vector<int> P, std::vector<int> A) {
	NN = N, MM = M;
	for (int i = 0; i < N + M - 1; i++) {
		p[i] = P[i];
		if (i == 0) d[0] = 0;
		if (i > 0 && p[i] != (i - 1) / 2) ch = false;
		d[i] = d[P[i]] + 1;
	}
	for (int i = 0; i < M; i++) {
		a[i] = A[i];
	}
	if (M != N + 1) ch = false;
	int u = log2(M);
	if ((1 << u) != M) ch = false;
	if (ch) build_tree(1, 0, M - 1);
	else {
		for (int i = 0; i < M; i++) {
			pref[i] = binpow(2, N - d[i + N]);
			if (i) pref[i] += pref[i - 1];
		}
		build_tree2(1, 0, M - 1);
	}
}
int count_ways(int L, int R) {
	if (ch) {
		update(1, 0, MM - 1, L - NN, R - NN);
		return tree[1].first;
	}
	else {
		update2(1, 0, MM - 1, L - NN, R - NN);
		return tree2[1];
	}
}

Subtask #1
0 / 2.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 336 KB Output is correct
2 Incorrect 1 ms 208 KB 1st lines differ - on the 1st token, expected: '1', found: '2'
3 Halted 0 ms 0 KB -

Subtask #2
0 / 7.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 336 KB Output is correct
2 Correct 0 ms 336 KB Output is correct
3 Correct 1 ms 336 KB Output is correct
4 Correct 1 ms 336 KB Output is correct
5 Correct 1 ms 464 KB Output is correct
6 Incorrect 1 ms 336 KB 1st lines differ - on the 1st token, expected: '706880838', found: '853441430'
7 Halted 0 ms 0 KB -

Subtask #3
0 / 9.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 336 KB Output is correct
2 Incorrect 1 ms 208 KB 1st lines differ - on the 1st token, expected: '1', found: '2'
3 Halted 0 ms 0 KB -

Subtask #4
4.0 / 4.0

# 결과 실행 시간 메모리 Grader output
1 Correct 464 ms 2728 KB Output is correct
2 Correct 690 ms 5172 KB Output is correct
3 Correct 740 ms 5172 KB Output is correct
4 Correct 859 ms 5200 KB Output is correct

Subtask #5
12.0 / 12.0

# 결과 실행 시간 메모리 Grader output
1 Correct 464 ms 2728 KB Output is correct
2 Correct 690 ms 5172 KB Output is correct
3 Correct 740 ms 5172 KB Output is correct
4 Correct 859 ms 5200 KB Output is correct
5 Correct 664 ms 2768 KB Output is correct
6 Correct 628 ms 5192 KB Output is correct
7 Correct 850 ms 5188 KB Output is correct
8 Correct 675 ms 5200 KB Output is correct
9 Correct 320 ms 464 KB Output is correct
10 Correct 583 ms 592 KB Output is correct
11 Correct 619 ms 592 KB Output is correct
12 Correct 671 ms 592 KB Output is correct

Subtask #6
0 / 27.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 336 KB Output is correct
2 Correct 0 ms 336 KB Output is correct
3 Correct 1 ms 336 KB Output is correct
4 Correct 1 ms 336 KB Output is correct
5 Correct 1 ms 464 KB Output is correct
6 Incorrect 1 ms 336 KB 1st lines differ - on the 1st token, expected: '706880838', found: '853441430'
7 Halted 0 ms 0 KB -

Subtask #7
0 / 28.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 336 KB Output is correct
2 Incorrect 1 ms 208 KB 1st lines differ - on the 1st token, expected: '1', found: '2'
3 Halted 0 ms 0 KB -

Subtask #8
0 / 11.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 336 KB Output is correct
2 Incorrect 1 ms 208 KB 1st lines differ - on the 1st token, expected: '1', found: '2'
3 Halted 0 ms 0 KB -