Submission #779357

#	Time	Username	Problem	Language	Result	Execution time	Memory
779357		danikoynov	Building Bridges (CEOI17_building)	C++14	30 / 100	3056 ms	97192 KiB

building

#include<bits/stdc++.h>
#define endl '\n'

using namespace std;
typedef long long ll;

void speed()
{
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
    cout.tie(NULL);
}

const ll inf = 1e18;
const int maxn = 1e5 + 10;

struct line
{
    ll k, m;
    bool fresh;

    line(bool _fresh = false, ll _k = 0, ll _m = 0)
    {
        fresh = _fresh;
        k = _k;
        m = _m;
    }

    ll get_value(ll x)
    {
        return k * x + m;
    }
};

const int maxc = 1e6 + 10;

line tree[4 * maxc];

void add_line(int root, ll left, ll right, line cur)
{
    if (tree[root].fresh)
    {
        tree[root] = cur;
        return;
    }

    ll mid = (left + right) / 2;
    if (tree[root].get_value(mid) > cur.get_value(mid))
        swap(tree[root], cur);

    if (tree[root].get_value(left) > cur.get_value(left))
        add_line(root * 2, left, mid, cur);
    if (tree[root].get_value(right) > cur.get_value(right))
        add_line(root * 2 + 1, mid + 1, right, cur);
}

ll query(int root, ll left, ll right, ll x)
{
    if (tree[root].fresh)
        return inf;

    if (left == right)
        return tree[root].get_value(x);

    ll mid = (left + right) / 2, val;
    if (x <= mid)
        val = query(root * 2, left, mid, x);
    else
        val = query(root * 2 + 1, mid + 1, right, x);

    return min(val, tree[root].get_value(x));
}

int n;
ll h[maxn], w[maxn], pref[maxn], dp[maxn];
void solve()
{
    cin >> n;
    for (int i = 1; i <= n; i ++)
        cin >> h[i];
    for (int i = 1; i <= n; i ++)
        cin >> w[i], pref[i] = pref[i - 1] + w[i];

    dp[1] = 0;
    for (int i = 2; i <= n; i ++)
    {
        dp[i] = inf;
        for (int j = 1; j < i; j ++)
        {
            ///dp[i] = min(dp[i], dp[j] + pref[i - 1] - pref[j] + (h[i] - h[j]) * (h[i] - h[j]));
            dp[i] = min(dp[i], dp[j] + pref[i - 1] - pref[j] + h[i] * h[i] + h[j] * h[j] - 2 * h[i] * h[j]);
        }
    }

    cout << dp[n] << endl;
}

int main()
{
    solve();
    return 0;
}
/**
6
3 8 7 1 6 6
0 -1 9 1 2 0
*/

• Subtask 1: 30 / 30
• Subtask 2: 0 / 30
• Subtask 3: 0 / 40