제출 #770806

#제출 시각아이디문제언어결과실행 시간메모리
770806perchutsDetecting Molecules (IOI16_molecules)C++17
100 / 100
47 ms7336 KiB
#include <bits/stdc++.h> #define all(x) x.begin(), x.end() #define sz(x) (int) x.size() #define endl '\n' #define pb push_back #define _ ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL); #include "molecules.h" using namespace std; using ll = long long; using ull = unsigned long long; using ii = pair<int,int>; using iii = tuple<int,int,int>; const int inf = 2e9+1; const int mod = 1e9+7; const int maxn = 3e5+100; template<typename X, typename Y> bool ckmin(X& x, const Y& y) { return (y < x) ? (x=y,1):0; } template<typename X, typename Y> bool ckmax(X& x, const Y& y) { return (x < y) ? (x=y,1):0; } std::vector<int> find_subset(int l, int u, std::vector<int> w) { vector<pair<ll, int>> v; int n = sz(w); for (int i = 0; i < n; ++i) v.pb({w[i], i}); sort(all(v)); vector<ll> pref(n); pref[0] = v[0].first; for (int i = 1; i < n; ++i) pref[i] = pref[i-1] + v[i].first; vector<int> ans; for (int i = 0; i < n; ++i) { ll mn = pref[i], mx = pref[n - 1] - (i == n - 1 ? 0 : pref[n - 2 - i]); if (l <= mn && mn <= u) { for (int j = 0; j <= i; ++j) ans.pb(v[j].second); return ans; } if (l <= mx && mx <= u) { for (int j = n - 1 - i; j <= n - 1; ++j) ans.pb(v[j].second); return ans; } if (mn < l && u < mx) { // there is a good sum somewhere ll sum = mn, j = i; for (; j >= 0; --j) { if (sum - v[j].first + v[n - 1 - i + j].first < l) { ans.pb(v[n - 1 - i + j].second); sum += - v[j].first + v[n - 1 - i + j].first; } else break; } for (int k = 0; k < j; ++k) ans.pb(v[k].second); while (sum < l) sum += -v[j].first + v[j+1].first, j++; assert(l <= sum && sum <= u); ans.pb(v[j].second); return ans; } } // no answer found return ans; } // int main() { // int n, l, u; // assert(3 == scanf("%d %d %d", &n, &l, &u)); // std::vector<int> w(n); // for (int i = 0; i < n; i++) // assert(1 == scanf("%d", &w[i])); // std::vector<int> result = find_subset(l, u, w); // printf("%d\n", (int)result.size()); // for (int i = 0; i < (int)result.size(); i++) // printf("%d%c", result[i], " \n"[i == (int)result.size() - 1]); // }
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