Submission #768115

#TimeUsernameProblemLanguageResultExecution timeMemory
768115GrindMachineThe Big Prize (IOI17_prize)C++17
20 / 100
95 ms336 KiB
// Om Namah Shivaya #include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; typedef long long int ll; typedef long double ld; typedef pair<int, int> pii; typedef pair<ll, ll> pll; #define fastio ios_base::sync_with_stdio(false); cin.tie(NULL) #define pb push_back #define endl '\n' #define sz(a) a.size() #define setbits(x) __builtin_popcountll(x) #define ff first #define ss second #define conts continue #define ceil2(x, y) ((x + y - 1) / (y)) #define all(a) a.begin(), a.end() #define rall(a) a.rbegin(), a.rend() #define yes cout << "Yes" << endl #define no cout << "No" << endl #define rep(i, n) for(int i = 0; i < n; ++i) #define rep1(i, n) for(int i = 1; i <= n; ++i) #define rev(i, s, e) for(int i = s; i >= e; --i) #define trav(i, a) for(auto &i : a) template<typename T> void amin(T &a, T b) { a = min(a, b); } template<typename T> void amax(T &a, T b) { a = max(a, b); } #ifdef LOCAL #include "debug.h" #else #define debug(x) 42 #endif /* refs: edi f(i+1) > f(i)^2 #of non-lollipops = O(sqrt(n)) just check all non-lollipops for diamond efficiently find all non-lollipops */ const int MOD = 1e9 + 7; const int N = 1e5 + 5; const int inf1 = int(1e9) + 5; const ll inf2 = ll(1e18) + 5; #include "prize.h" pii ask2(int i){ vector<int> v = ask(i); return {v[0],v[1]}; } int find_best(int n) { int mx = -1, pos = -1; rep(i,450){ auto [cl,cr] = ask2(i); int cnt = cl+cr; if(cnt == 0){ return i; } if(cnt > mx){ mx = cnt; pos = i; } } assert(pos != -1); // find the closest non-lollipop with ind > i // given that the curr pos is a lollipop while(true){ int l = pos, r = n-1; auto [fcl,fcr] = ask2(pos); int first = -1; while(l <= r){ // is there a lollipop in range [pos,mid]? int mid = (l+r) >> 1; auto [cl,cr] = ask2(mid); int cnt = cl+cr; bool ok = false; // mid is a lollipop if(cnt != mx){ ok = true; } else{ // mid is not a lollipop if(cl > fcl){ ok = true; } } if(ok){ first = mid; r = mid-1; } else{ l = mid+1; } } if(first == -1){ break; } pos = -1; // find the closest pos >= first that is a lollipop for(int i = first; i < n; ++i){ auto [cl,cr] = ask2(i); int cnt = cl+cr; if(cnt == 0){ return i; } if(cnt == mx){ pos = i; break; } } if(pos == -1) break; } // assert(0); return -1; }
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