제출 #767033

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
767033		khshg	Split the Attractions (IOI19_split)	C++14	0 / 100	528 ms	1048576 KiB

split

#include<bits/stdc++.h>
using namespace std;
 
using ll = long long;
using ld = long double;
using str = string;
 
using pi = pair<int, int>;
using pl = pair<ll, ll>;
using pd = pair<ld, ld>;
#define mp make_pair
#define ff first
#define ss second
 
#define ar array
template<class T> using V = vector<T>;
using vi = V<int>;
using vb = V<bool>;
using vl = V<ll>;
using vd = V<ld>;
using vs = V<str>;
using vpi = V<pi>;
using vpl = V<pl>;
using vpd = V<pd>;
 
#define sz(x) (int)((x).size())
#define bg(x) begin(x)
#define all(x) bg(x), end(x)
#define rall(x) (x).rbegin(), (x).rend()
#define sor(x) sort(all(x))
#define rsz resize
#define ins insert
#define pb push_back
#define eb emplace_back
#define ft front()
#define bk back()
#define lb lower_bound
#define ub upper_bound
 
#define FOR(i, a, b) for(int i = (a); i < (b); ++i)
#define F0R(i, a) FOR(i, 0, a)
#define ROF(i, a, b) for(int i = (b) - 1; i >= (a); --i)
#define R0F(i, a) ROF(i, 0, a)
#define rep(a) F0R(_, a)
#define trav(a, x) for(auto& a : x)
 
template<class T> bool ckmin(T& a, const T& b) { return (b < a ? a = b, 1 : 0); }
template<class T> bool ckmax(T& a, const T& b) { return (b > a ? a = b, 1 : 0); }

V<vi> adj;

int bfs(int s) {
	vi q;
	q.pb(s);
	vi dis(sz(adj), 0x3f3f3f3f);
	dis[s] = 0;
	int fn = s;
	while(sz(q)) {
		int cur = q.bk; q.pop_back();
		if(dis[fn] < dis[cur]) fn = cur;
		trav(u, adj[cur]) {
			if(ckmin(dis[u], dis[cur] + 1)) {
				q.pb(u);
			}
		}
	}
	return fn;
}

void find_path(int s, int p, int g, vi& path) {
	path.eb(s);
	if(s == g) return;
	trav(u, adj[s]) {
		if(u == p) continue;
		find_path(u, s, g, path);
		if(path.bk == g) break;
	}
	if(path.bk == g) return;
	path.pop_back();
}

vi ans;

void color(int s, int& cnt, int c) {
	if(!cnt) return;
	--cnt;
	ans[s] = c;
	trav(u, adj[s]) {
		if(!cnt) break;
		if(ans[u] == 0) color(u, cnt, c);
	}
}
vector<int> find_split(int N, int a, int b, int c, vector<int> p, vector<int> Q) {
	adj.rsz(N);
	ans.rsz(N);
	int M = sz(p);
	F0R(i, M) {
		adj[p[i]].pb(Q[i]);
		adj[Q[i]].pb(p[i]);
	}
	int nd1 = bfs(0);
	int nd2 = bfs(nd1);
	int mn = min({a, b, c});
	int mn2 = a + b + c - mn - max({a, b, c});
	int mncolor = (a == mn ? 1 : (b == mn ? 2 : 3));
	int mn2color = (a == mn2 && mncolor != 1 ? 1 : (b == mn2 && mncolor != 2 ? 2 : 3));
	vi path; find_path(nd1, -1, nd2, path);
	int i = 0;
	vi q;
	while(mn) {
		if(q.empty()) q.pb(path[i]);
		int cur = q.bk; q.pop_back();
		ans[cur] = mncolor;
		--mn;
		if(cur == path[i]) {
			++i;
			if(i == sz(path)) return ans;//vi(N, 0);
		}
		trav(u, adj[cur]) {
			if(u == path[i]) continue;
			if(ans[u] == 0) q.pb(u);
		}
	}
	color(b, mn2, mn2color);
	F0R(i, N) {
		if(ans[i] == 0) {
			ans[i] = 6 - mncolor - mn2color;//;
		}
	}
	return ans;
}
/*
int main() {
	int n, m, a, b, c;
	assert(5 == scanf("%d%d%d%d%d", &n, &m, &a, &b, &c));
	vector<int> p(m), q(m);
	for (int i=0; i<m; i++)
		assert(2 == scanf("%d%d", &p[i], &q[i]));
	fclose(stdin);

	vector<int> result = find_split(n, a, b, c, p, q);

	for (int i=0; i<(int)result.size(); i++)
		printf("%s%d", ((i>0)?" ":""), result[i]);
	printf("\n");
	fclose(stdout);
	return 0;
}*/

• Subtask 1: 0 / 7
• Subtask 2: 0 / 11
• Subtask 3: 0 / 22
• Subtask 4: 0 / 24
• Subtask 5: 0 / 36