Submission #766306

#TimeUsernameProblemLanguageResultExecution timeMemory
766306GrindMachineRainforest Jumps (APIO21_jumps)C++17
77 / 100
4072 ms69232 KiB
// Om Namah Shivaya #include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; typedef long long int ll; typedef long double ld; typedef pair<int, int> pii; typedef pair<ll, ll> pll; #define fastio ios_base::sync_with_stdio(false); cin.tie(NULL) #define pb push_back #define endl '\n' #define sz(a) a.size() #define setbits(x) __builtin_popcountll(x) #define ff first #define ss second #define conts continue #define ceil2(x, y) ((x + y - 1) / (y)) #define all(a) a.begin(), a.end() #define rall(a) a.rbegin(), a.rend() #define yes cout << "Yes" << endl #define no cout << "No" << endl #define rep(i, n) for(int i = 0; i < n; ++i) #define rep1(i, n) for(int i = 1; i <= n; ++i) #define rev(i, s, e) for(int i = s; i >= e; --i) #define trav(i, a) for(auto &i : a) template<typename T> void amin(T &a, T b) { a = min(a, b); } template<typename T> void amax(T &a, T b) { a = max(a, b); } #ifdef LOCAL #include "debug.h" #else #define debug(x) 42 #endif /* refs: edi (https://apio2021.toki.id/assets/APIO_2021_Problem_Discussions.pdf) got all but the last subtask edi for last subtask */ const int MOD = 1e9 + 7; const int N = 2e5 + 5; const int inf1 = int(1e9) + 5; const ll inf2 = ll(1e18) + 5; #include "jumps.h" template<typename T> struct sparse_table { /*============================*/ T merge(T a, T b) { return max(a,b); } /*============================*/ vector<vector<T>> table; vector<int> bin_log; int LOG = 0; sparse_table() { } sparse_table(vector<T> &a, int n) { while ((1 << LOG) <= n) LOG++; table = vector<vector<T>>(n, vector<T>(LOG)); bin_log = vector<int>(n + 1); rep(i, n) table[i][0] = a[i]; rep1(j, LOG - 1) { rep(i, n) { int jump = 1 << (j - 1); if (i + jump >= n) { break; } table[i][j] = merge(table[i][j - 1], table[i + jump][j - 1]); } } bin_log[1] = 0; for (int i = 2; i <= n; ++i) { bin_log[i] = bin_log[i / 2] + 1; } } T query(int l, int r) { int len = r - l + 1; int k = bin_log[len]; T val1 = table[l][k]; T val2 = table[r - (1 << k) + 1][k]; return merge(val1, val2); } }; const int LOG = 18; int upl[N][LOG], upr[N][LOG], upb[N][LOG]; vector<int> a; sparse_table<int> sparse; vector<int> pos_of_val; void init(int n, vector<int> h) { a = h; a.pb(inf1); sparse = sparse_table<int>(a,n+1); pos_of_val = vector<int>(n+5); rep(i,n) pos_of_val[a[i]] = i; vector<int> ngel(n,n), nger(n,n); stack<int> st; rep(i,n){ while(!st.empty() and a[i] > a[st.top()]){ nger[st.top()] = i; st.pop(); } st.push(i); } while(!st.empty()) st.pop(); rev(i,n-1,0){ while(!st.empty() and a[i] > a[st.top()]){ ngel[st.top()] = i; st.pop(); } st.push(i); } while(!st.empty()) st.pop(); rep(j,LOG){ upl[n][j] = upr[n][j] = upb[n][j] = n; } rep(i,n){ upl[i][0] = ngel[i]; upr[i][0] = nger[i]; if(a[ngel[i]] > a[nger[i]]){ upb[i][0] = ngel[i]; } else{ upb[i][0] = nger[i]; } } rep1(j,LOG-1){ rep(i,n){ upl[i][j] = upl[upl[i][j-1]][j-1]; upr[i][j] = upr[upr[i][j-1]][j-1]; upb[i][j] = upb[upb[i][j-1]][j-1]; } } } int minimum_jumps(int l1, int l2, int r1, int r2) { if(r1 != r2){ int ans = inf1; for(int r = r1; r <= r2; ++r){ int res = minimum_jumps(l1,l2,r,r); if(res != -1){ amin(ans,res); } } if(ans == inf1) ans = -1; return ans; } int l = -1, r = r1; if(l1 <= r and r <= l2){ return 0; } // some suff is good int lo = l1, hi = l2; int suff = -1; while(lo <= hi){ int mid = (lo+hi) >> 1; if(sparse.query(mid,r) <= a[r]){ suff = mid; hi = mid-1; } else{ lo = mid+1; } } if(suff == -1) return -1; int mx = sparse.query(suff,l2); l = pos_of_val[mx]; int ans = 0; // big jumps until possible rev(j,LOG-1,0){ int nxt = upb[l][j]; if(a[nxt] <= a[r]){ l = nxt; ans += (1 << j); } } // small jumps going in one direction until reach r rev(j,LOG-1,0){ int nxt = upl[l][j]; if(a[nxt] <= a[r]){ l = nxt; ans += (1 << j); } } rev(j,LOG-1,0){ int nxt = upr[l][j]; if(a[nxt] <= a[r]){ l = nxt; ans += (1 << j); } } return ans; /* { int ans = 0; while(l != r){ int lx = upl[l][0], rx = upr[l][0]; if(a[lx] > a[r]){ l = rx; } else if(a[rx] > a[r]){ l = lx; } else{ if(a[lx] > a[rx]){ l = lx; } else{ l = rx; } } ans++; } return ans; } */ }
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