Submission #763362

#TimeUsernameProblemLanguageResultExecution timeMemory
763362Polar_Bear_2007Xylophone (JOI18_xylophone)C++17
0 / 100
2 ms464 KiB
#ifdef MINHDEPTRAI #include "/Library/Developer/CommandLineTools/usr/include/c++/v1/bits/stdc++.h" #include <chrono> #define __gcd(a, b) gcd(a, b) using namespace std ::chrono; #else #include <bits/stdc++.h> #include <xylophone.h> #endif using namespace std; #define foru(i, a, b) for(int i = a; i <= b; ++i) #define ford(i, a, b) for(int i = a; i >= b; --i) #define IOS ios_base:: sync_with_stdio(false); cin.tie(0); cout.tie(0); #define mp(a, b) make_pair(a, b) #define endl '\n' const int maxN = 2e6 + 5; const int mod = 998244353; const long long inf = 1e17; vector<int> number, triple; int dau[maxN], ans[maxN], counting[maxN]; // int query(int a, int b){ // cout << "? " << a << " " << b << endl; // int val; // cin >> val; // return val; // } // void answer(int i, int a){ // cout << a << " "; // } void solve(int N){ if(N == 2){ answer(1, 1); answer(2, 2); return; } int i = 1, j = 2; while(j <= N){ number.push_back(query(i, j)); i++; j++; } int k = 3; i = 1; while(k <= N){ triple.push_back(query(i, k)); i++; k++; } dau[0] = 1; for(int j = 0; j < (int)triple.size(); j++){ if(triple[j] == number[j + 1] + number[j]){ dau[j + 1] = dau[j]; } else{ dau[j + 1] = -dau[j]; } } bool check = true; int cnt = 0; while(check){ ans[0] = ++cnt; if(cnt > N) break; int pos_one = 0, pos_n = -1; for(int j = 1; j <= N - 1; j++){ ans[j] = ans[j - 1] + number[j - 1] * (-dau[j - 1]); counting[ans[j]]++; if(ans[j] == 1) pos_one = j; if(ans[j] == N) pos_n = j; } foru(j, 0, N - 1){ if(ans[j] < 1 || ans[j] > N || counting[ans[j]] > 2 || pos_one > pos_n){ break; } if(j == N - 1) check = false; } } cnt = 0; while(check){ ans[0] = ++cnt; if(cnt > N) break; int pos_one = 0, pos_n = -1; for(int j = 1; j <= N - 1; j++){ ans[j] = ans[j - 1] + number[j - 1] * dau[j - 1]; counting[ans[j]]++; if(ans[j] == 1) pos_one = j; if(ans[j] == N) pos_n = j; } foru(j, 0, N - 1){ if(ans[j] < 1 || ans[j] > N || counting[ans[j]] > 2 || pos_one > pos_n){ break; } if(j == N - 1) check = false; } } foru(j, 0, N - 1) answer(j + 1, ans[j]); } // signed main(){ // int n; // cin >> n; // solve(n); // }
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