답안 #762455

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
762455 2023-06-21T12:16:55 Z otarius Growing Trees (BOI11_grow) C++17
0 / 100
1000 ms 4260 KB
#include <bits/stdc++.h>
using namespace std;
 
#define ff first
#define sc second
#define pb push_back
#define ll long long
#define pll pair<ll, ll>
#define pii pair <int, int>
#define ull unsigned long long
 
// #define int long long
// #define int unsigned long long
 
const ll inf = 1e18 + 7;
const ll weirdMod = 998244353;

struct node {
    int mn, mx;
} t[400040];
int lazy[400040], n, m;
void prop(int v, int tl, int tr) {
    t[v].mn += lazy[v] * (tr - tl + 1);
    t[v].mx += lazy[v] * (tr - tl + 1);
    if (tl != tr) {
        lazy[2 * v] += lazy[v];
        lazy[2 * v + 1] += lazy[v];
    } lazy[v] = 0;
}
void set_val(int v, int tl, int tr, int pos, int val) {
    if (tl == tr) {
        t[v].mn = t[v].mx = val;
        return;
    } int tm = (tl + tr) / 2;
    if (pos <= tm)
        set_val(2 * v, tl, tm, pos, val);
    else set_val(2 * v + 1, tm + 1, tr, pos, val);
    t[v].mn = min(t[2 * v].mn, t[2 * v + 1].mn);
    t[v].mx = max(t[2 * v].mx, t[2 * v + 1].mx);
}
int get_val(int v, int tl, int tr, int pos) {
    if (lazy[v])
        prop(v, tl, tr);
    if (tl == tr)
        return t[v].mn;
    int tm = (tl + tr) / 2;
    if (pos <= tm)
        return get_val(2 * v, tl, tm, pos);
    else return get_val(2 * v + 1, tm + 1, tr, pos);
    t[v].mn = min(t[2 * v].mn, t[2 * v + 1].mn);
    t[v].mx = max(t[2 * v].mx, t[2 * v + 1].mx);
}
void add_one(int v, int tl, int tr, int l, int r) {
    if (lazy[v])
        prop(v, tl, tr);
    if (tr < l || r < tl)
        return;
    if (l <= tl && tr <= r) {
        t[v].mn += tr - tl + 1;
        t[v].mx += tr - tl + 1;
        if (tl != tr) {
            lazy[2 * v]++;
            lazy[2 * v + 1]++;
        } return;
    } int tm = (tl + tr) / 2;
    add_one(2 * v, tl, tm, l, min(r, tm));
    add_one(2 * v + 1, tm + 1, tr, max(l, tm + 1), r);
    t[v].mn = min(t[2 * v].mn, t[2 * v + 1].mn);
    t[v].mx = max(t[2 * v].mx, t[2 * v + 1].mx);
}
int find_first(int v, int tl, int tr, int val) {
    if (lazy[v]) prop(v, tl, tr);
    if (t[v].mx < val) return tr + 1;
    if (tl == tr) return tl;
    int tm = (tl + tr) / 2;
    int ans = find_first(2 * v, tl, tm, val);
    if (ans == tm + 1)
        return find_first(2 * v + 1, tm + 1, tr, val);
    else return ans;
}
int find_second(int v, int tl, int tr, int val) {
    if (lazy[v]) prop(v, tl, tr);
    if (val < t[v].mn) return tl - 1;
    if (tl == tr) return tl;
    int tm = (tl + tr) / 2;
    int ans = find_second(2 * v + 1, tm + 1, tr, val);
    if (ans == tm)
        return find_second(2 * v, tl, tm, val);
    else return ans;
}
void upd_query(int c, int h) {
    int pos = find_first(1, 1, n, h);
    int num = get_val(1, 1, n, pos + c - 1);
    int l = find_first(1, 1, n, num);
    int r = find_second(1, 1, n, num);
    add_one(1, 1, n, pos, l - 1); c -= l - pos;
    add_one(1, 1, n, max(l, r - c + 1), r);
}
void ans_query(int l, int r) {
    cout << find_second(1, 1, n, r) - find_first(1, 1, n, l) + 1 << '\n';
}
void solve() {
    cin >> n >> m;
    vector<int> vec(n);
    for (auto &v : vec) cin >> v;
    sort(vec.begin(), vec.end());
    for (int i = 1; i <= n; i++)
        set_val(1, 1, n, i, vec[i - 1]);
    char v; int l, r;
    for (int i = 1; i <= m; i++) {
        cin >> v >> l >> r;
        if (v == 'F') upd_query(l, r);
        else ans_query(l, r);
    }
}
int32_t main() {
    ios_base::sync_with_stdio(false);
    cin.tie(nullptr); cout.tie(nullptr);
 
    int t = 1;
    // cin >> t;
    while (t--) {
        solve();
    } return 0;
}
# 결과 실행 시간 메모리 Grader output
1 Execution timed out 1070 ms 3960 KB Time limit exceeded
2 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Incorrect 2 ms 340 KB Output isn't correct
2 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Execution timed out 1066 ms 812 KB Time limit exceeded
2 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Incorrect 107 ms 768 KB Output isn't correct
2 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Execution timed out 1079 ms 2140 KB Time limit exceeded
2 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Execution timed out 1069 ms 3700 KB Time limit exceeded
2 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Execution timed out 1082 ms 3868 KB Time limit exceeded
2 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Execution timed out 1078 ms 3904 KB Time limit exceeded
2 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Execution timed out 1069 ms 3768 KB Time limit exceeded
2 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Incorrect 446 ms 4260 KB Output isn't correct
2 Halted 0 ms 0 KB -