# | 제출 시각 | 아이디 | 문제 | 언어 | 결과 | 실행 시간 | 메모리 |
---|---|---|---|---|---|---|---|
757891 | APROHACK | 정렬하기 (IOI15_sorting) | C++14 | 2 ms | 596 KiB |
이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "sorting.h"
#include <bits/stdc++.h>
#define ll long long
#define pb push_back
#define ff first
#define ss second
using namespace std;
vector<int>arr;
vector<int>whereIs[2];
vector<int>current;
int buenos;
void cambiar(vector<int>&v, int i, int j){
int temp = v[i];
v[i] = v[j];
v[j] = temp;
}
bool sorted(int n){
return buenos == n;
}
int findSwapPairs(int N, int S[], int M, int X[], int Y[], int P[], int Q[]) {
buenos = 0;
vector<int>copia;
bool valid = true;
for(int i = 0 ; i < N ; i ++){
whereIs[0].pb(0);
whereIs[1].pb(0);
if(S[i] != i)valid = false;
}
if(valid)return 0;
for(int i = 0 ; i < N ; i ++){
copia.pb(S[i]);
current.pb(S[i]);
arr.pb(S[i]);
whereIs[0][S[i]] = i;
whereIs[1][S[i]] = i;
if(current[i] == i)buenos ++;
}
for(int i = 0 ; i < N ; i ++){
cambiar(copia, X[i], Y[i]);
//for(auto j : copia) cout << j << " " ;
//cout << endl;
}
for(int i = 0 ; i < N ; i ++){
//cout << "donde esta " << copia[i] << " = " << whereIs[copia[i]] << endl;
arr[whereIs[0][copia[i]]] = i;
}
for(int i = 0 ; i < N ; i ++){
whereIs[0][arr[i]] = i;
}
int currentC = 0, movimientos = 0;
int i = 0;
int temporal, t2;
while(i < N){
//for(auto k : current)cout << k << " ";
//cout << endl;
if(sorted(N))return movimientos;
cambiar(arr, X[i], Y[i]);
whereIs[0][arr[X[i]]] = X[i];
whereIs[0][arr[Y[i]]] = Y[i];
temporal = 0, t2 = 0;
if(current[X[i]] == X[i])temporal ++;
if(current[Y[i]] == Y[i])temporal ++;
cambiar(current, X[i], Y[i]);
if(current[X[i]] == X[i])t2 ++;
if(current[Y[i]] == Y[i])t2 ++;
buenos += t2-temporal;
whereIs[1][current[X[i]]] = X[i];
whereIs[1][current[Y[i]]] = Y[i];
while(currentC < N and whereIs[1][currentC] == whereIs[0][currentC])currentC++;
if(currentC < N){
P[i] = whereIs[1][currentC];
Q[i] = whereIs[0][currentC];
temporal = 0;
t2 = 0;
if(current[P[i]] == P[i])temporal ++;
if(current[Q[i]] == Q[i])temporal ++;
cambiar(current, P[i], Q[i]);
if(current[P[i]] == P[i])t2 ++;
if(current[Q[i]] == Q[i])t2 ++;
buenos += t2-temporal;
whereIs[1][current[P[i]]] = P[i];
whereIs[1][current[Q[i]]] = Q[i];
i++;
currentC++;
movimientos++;
}else{
i++;
currentC++;
movimientos++;
}
}
//for(auto k : current)cout << k << " ";
return movimientos;
}
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