제출 #752203

#제출 시각아이디문제언어결과실행 시간메모리
752203GrindMachineNautilus (BOI19_nautilus)C++17
66 / 100
1077 ms624 KiB
// Om Namah Shivaya #pragma GCC optimize("O3,unroll-loops") #pragma GCC target("avx2") #include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; typedef long long int ll; typedef long double ld; typedef pair<int, int> pii; typedef pair<ll, ll> pll; #define fastio ios_base::sync_with_stdio(false); cin.tie(NULL) #define pb push_back #define endl '\n' #define sz(a) a.size() #define setbits(x) __builtin_popcountll(x) #define ff first #define ss second #define conts continue #define ceil2(x, y) ((x + y - 1) / (y)) #define all(a) a.begin(), a.end() #define rall(a) a.rbegin(), a.rend() #define yes cout << "Yes" << endl #define no cout << "No" << endl #define rep(i, n) for(int i = 0; i < n; ++i) #define rep1(i, n) for(int i = 1; i <= n; ++i) #define rev(i, s, e) for(int i = s; i >= e; --i) #define trav(i, a) for(auto &i : a) template<typename T> void amin(T &a, T b) { a = min(a, b); } template<typename T> void amax(T &a, T b) { a = max(a, b); } #ifdef LOCAL #include "debug.h" #else #define debug(x) 42 #endif /* */ const int MOD = 1e9 + 7; const int N = 500 + 5; const int inf1 = int(1e9) + 5; const ll inf2 = ll(1e18) + 5; void solve(int test_case) { ll n,m,k; cin >> n >> m >> k; char a[n+5][m+5]; rep(i,n+5) rep(j,m+5) a[i][j] = '#'; rep1(i,n) rep1(j,m) cin >> a[i][j]; string s; cin >> s; s = "$" + s; bitset<N> dp1[n+5], dp2[n+5]; rep1(i,n){ rep1(j,m){ if(a[i][j] == '.'){ dp1[i][j] = 1; } } } rep1(p,k){ char ch = s[p]; rep1(i,n){ if(ch == '?'){ dp2[i] = (dp1[i-1] | dp1[i+1] | (dp1[i] << 1) | (dp1[i] >> 1)); } else{ if(ch == 'N') dp2[i] = dp1[i+1]; if(ch == 'S') dp2[i] = dp1[i-1]; if(ch == 'E') dp2[i] = (dp1[i] << 1); if(ch == 'W') dp2[i] = (dp1[i] >> 1); } rep(j,m+2){ if(a[i][j] == '#'){ dp2[i][j] = 0; } } } rep1(i,n){ dp1[i] = dp2[i]; } } ll ans = 0; rep1(i,n){ rep1(j,m){ ans += dp1[i][j]; } } cout << ans << endl; } int main() { fastio; int t = 1; // cin >> t; rep1(i, t) { solve(i); } return 0; }
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