oj.uz

답안 #742156

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
742156 2023-05-15T17:17:57 Z GrindMachine Selling RNA Strands (JOI16_selling_rna) C++17
100 / 100
 848 ms 781128 KB 
// Om Namah Shivaya

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>

using namespace std;
using namespace __gnu_pbds;

template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
typedef long long int ll;
typedef long double ld;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;

#define fastio ios_base::sync_with_stdio(false); cin.tie(NULL)
#define pb push_back
#define endl '\n'
#define sz(a) a.size()
#define setbits(x) __builtin_popcountll(x)
#define ff first
#define ss second
#define conts continue
#define ceil2(x, y) ((x + y - 1) / (y))
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
#define yes cout << "Yes" << endl
#define no cout << "No" << endl

#define rep(i, n) for(int i = 0; i < n; ++i)
#define rep1(i, n) for(int i = 1; i <= n; ++i)
#define rev(i, s, e) for(int i = s; i >= e; --i)
#define trav(i, a) for(auto &i : a)

template<typename T>
void amin(T &a, T b) {
    a = min(a, b);
}

template<typename T>
void amax(T &a, T b) {
    a = max(a, b);
}

#ifdef LOCAL
#include "debug.h"
#else
#define debug(x) 42
#endif

/*

refs:
https://github.com/Yehezkiel01/CompetitiveProgramming/blob/master/JOIOC/JOIOC-16-selling_rna.cpp


count #of strings that have prefix = p, suffix = q
if suffix condition doesn't exist, then we can solve this using a simple trie

how to consider this condition

we can add all input strings to a trie

for a query, we can go to the node representing the string p in the trie
prefix condition is satisfied

we want to count the #of leaves in the subtree of this node that correspond to q

put reversed string @ every leaf

for all (reversed) strings in the subtree of the current node, find the #of strings that are a prefix of reversed q

consider the original trie as a tree
store a trie @ every node and do small to large merging

*/

const int MOD = 1e9 + 7;
const int N = 1e5 + 5;
const int inf1 = int(1e9) + 5;
const ll inf2 = ll(1e18) + 5;

int get(char ch) {
    int x = -1;
    if (ch == 'A') x = 0;
    if (ch == 'G') x = 1;
    if (ch == 'C') x = 2;
    if (ch == 'U') x = 3;

    return x;
}

vector<int> ans(N);

struct Trie {
    struct node {
        int f[4];
        int cnt, end;
        string str = "";

        node() {
            memset(f, -1, sizeof f);
            cnt = 0, end = 0;
            str = "";
        }
    };

    vector<node> tr;
    int siz = 0;

    Trie() {
        tr.pb(node());
        siz++;
    }

    void insert(string s, int add) {
        int u = 0;
        trav(ch, s) {
            int x = get(ch);

            if (tr[u].f[x] == -1) {
                tr.pb(node());
                tr[u].f[x] = siz++;
            }

            u = tr[u].f[x];
            tr[u].cnt += add;
        }

        tr[u].end++;

        reverse(all(s));
        tr[u].str = s;
    }

    vector<vector< pair<string, int> >> queries;

    void init_queries() {
        queries.resize(siz);
    }

    void insert_query(string p, string q, int id) {
        int u = 0;

        trav(ch, p) {
            int x = get(ch);
            if (tr[u].f[x] == -1) {
                u = -1;
                break;
            }

            u = tr[u].f[x];
        }

        if (u != -1) {
            reverse(all(q));
            queries[u].pb({q, id});
        }
    }

    void merge(Trie &trie1, Trie &trie2, int u1, int u2) {
        rep(x, 4) {
            int v1 = trie1.tr[u1].f[x];
            int v2 = trie2.tr[u2].f[x];

            if (v2 == -1) conts;

            if (v1 == -1) {
                trie1.tr.pb(node());
                trie1.tr[u1].f[x] = trie1.siz++;
                v1 = trie1.tr[u1].f[x];
            }

            trie1.tr[v1].cnt += trie2.tr[v2].cnt;
            merge(trie1, trie2, v1, v2);
        }
    }

    vector<Trie> trie;

    void dfs(int u) {
        rep(x, 4) {
            int v = tr[u].f[x];
            if (v == -1) conts;

            dfs(v);

            if (trie[v].siz > trie[u].siz) {
                swap(trie[u], trie[v]);
            }

            merge(trie[u], trie[v], 0, 0);
        }

        if (!tr[u].str.empty()) {
            trie[u].insert(tr[u].str, tr[u].end);
        }

        for (auto [q, id] : queries[u]) {
            int curr = 0;

            trav(ch, q) {
                int x = get(ch);

                if (trie[u].tr[curr].f[x] == -1) {
                    curr = -1;
                    break;
                }

                curr = trie[u].tr[curr].f[x];
            }

            if (curr != -1) {
                ans[id] = trie[u].tr[curr].cnt;
            }
        }
    }

    void dfs() {
        trie.resize(siz);
        dfs(0);
    }
};

void solve(int test_case)
{
    int n, m; cin >> n >> m;
    vector<string> a(n);
    rep(i, n) cin >> a[i];

    // insert all initial strings into trie
    Trie trie;
    rep(i, n) trie.insert(a[i], 1);

    // insert all query strings into their appropriate positions
    trie.init_queries();

    rep(i, m) {
        string p, q; cin >> p >> q;
        trie.insert_query(p, q, i);
    }

    // answer queries by dfs + small to large merging
    trie.dfs();
    rep(i, m) cout << ans[i] << endl;
}

int main()
{
    fastio;

    int t = 1;
    // cin >> t;

    rep1(i, t) {
        solve(i);
    }

    return 0;
}

Subtask #1
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 724 KB Output is correct
2 Correct 1 ms 724 KB Output is correct
3 Correct 1 ms 724 KB Output is correct
4 Correct 1 ms 724 KB Output is correct
5 Correct 1 ms 724 KB Output is correct
6 Correct 1 ms 724 KB Output is correct
7 Correct 1 ms 724 KB Output is correct

Subtask #2
25.0 / 25.0

# 결과 실행 시간 메모리 Grader output
1 Correct 289 ms 224952 KB Output is correct
2 Correct 311 ms 236072 KB Output is correct
3 Correct 670 ms 558944 KB Output is correct
4 Correct 845 ms 534344 KB Output is correct
5 Correct 847 ms 770172 KB Output is correct
6 Correct 848 ms 781128 KB Output is correct
7 Correct 46 ms 8908 KB Output is correct
8 Correct 462 ms 424608 KB Output is correct
9 Correct 384 ms 343244 KB Output is correct
10 Correct 403 ms 417600 KB Output is correct

Subtask #3
25.0 / 25.0

# 결과 실행 시간 메모리 Grader output
1 Correct 21 ms 5304 KB Output is correct
2 Correct 16 ms 5196 KB Output is correct
3 Correct 25 ms 5196 KB Output is correct
4 Correct 16 ms 3860 KB Output is correct
5 Correct 16 ms 5492 KB Output is correct
6 Correct 21 ms 5484 KB Output is correct

Subtask #4
40.0 / 40.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 724 KB Output is correct
2 Correct 1 ms 724 KB Output is correct
3 Correct 1 ms 724 KB Output is correct
4 Correct 1 ms 724 KB Output is correct
5 Correct 1 ms 724 KB Output is correct
6 Correct 1 ms 724 KB Output is correct
7 Correct 1 ms 724 KB Output is correct
8 Correct 289 ms 224952 KB Output is correct
9 Correct 311 ms 236072 KB Output is correct
10 Correct 670 ms 558944 KB Output is correct
11 Correct 845 ms 534344 KB Output is correct
12 Correct 847 ms 770172 KB Output is correct
13 Correct 848 ms 781128 KB Output is correct
14 Correct 46 ms 8908 KB Output is correct
15 Correct 462 ms 424608 KB Output is correct
16 Correct 384 ms 343244 KB Output is correct
17 Correct 403 ms 417600 KB Output is correct
18 Correct 21 ms 5304 KB Output is correct
19 Correct 16 ms 5196 KB Output is correct
20 Correct 25 ms 5196 KB Output is correct
21 Correct 16 ms 3860 KB Output is correct
22 Correct 16 ms 5492 KB Output is correct
23 Correct 21 ms 5484 KB Output is correct
24 Correct 319 ms 244016 KB Output is correct
25 Correct 326 ms 245156 KB Output is correct
26 Correct 290 ms 243412 KB Output is correct
27 Correct 617 ms 470784 KB Output is correct
28 Correct 148 ms 65664 KB Output is correct
29 Correct 51 ms 12660 KB Output is correct