제출 #741909

#제출 시각아이디문제언어결과실행 시간메모리
741909baojiaopisu친구 (IOI14_friend)C++14
100 / 100
39 ms7420 KiB
#include "friend.h" #include<bits/stdc++.h> using namespace std; using ll = long long; using ld = long double; using ull = unsigned long long; using pii = pair<int, int>; using pll = pair<ll, ll>; using pld = pair<ld, ld>; #define fi first #define se second #define left BAO #define right ANH #define pb push_back #define pf push_front #define mp make_pair #define ins insert #define btpc __builtin_popcount #define btclz __builtin_clz #define sz(x) (int)(x.size()); #define all(x) x.begin(), x.end() #define debug(...) " [" << #__VA_ARGS__ ": " << (__VA_ARGS__) << "] " mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); int d4x[4] = {1, 0, -1, 0}; int d4y[4] = {0, 1, 0, -1}; int d8x[8] = {0, 1, 1, 1, 0, -1, -1, -1}; int d8y[8] = {1, 1, 0, -1, -1, -1, 0, 1}; template<class X, class Y> bool minimize(X &x, const Y &y) { if (x > y) { x = y; return true; } return false; } template<class X, class Y> bool maximize(X &x, const Y &y) { if (x < y) { x = y; return true; } return false; } const int MOD = 1e9 + 7; //998244353 template<class X, class Y> void add(X &x, const Y &y) { x = (x + y); if(x >= MOD) x -= MOD; } template<class X, class Y> void sub(X &x, const Y &y) { x = (x - y); if(x < 0) x += MOD; } /* Author : Le Ngoc Bao Anh, 12A5, LQD High School for Gifted Student*/ const ll INF = 1e9; const int N = 1e5 + 10; vector<pii> g[N]; int dp[N][2]; void dfs(int u) { reverse(all(g[u])); for(auto nxt : g[u]) { int v = nxt.fi; int t = nxt.se; dfs(v); if(t == 0) { dp[u][0] += max(dp[v][0], dp[v][1]); dp[u][1] += dp[v][0]; } if(t == 1) { dp[u][1] += max(dp[v][0], dp[v][1]); maximize(dp[u][1], dp[u][0] + dp[v][1]); dp[u][0] += dp[v][0]; } if(t == 2) { dp[u][1] = max(dp[u][1] + dp[v][0], dp[u][0] + dp[v][1]); dp[u][0] += dp[v][0]; } } } int findSample(int n, int confidence[], int host[], int protocol[]) { for(int i = 1; i < n; i++) { g[host[i]].pb(mp(i, protocol[i])); } for(int i = 0; i < n; i++) dp[i][1] = confidence[i]; dfs(0); return max(dp[0][0], dp[0][1]); }
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