Submission #732121

#TimeUsernameProblemLanguageResultExecution timeMemory
732121GrindMachineCalvinball championship (CEOI15_teams)C++17
0 / 100
373 ms660 KiB
// Om Namah Shivaya #include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; typedef long long int ll; typedef long double ld; typedef pair<int, int> pii; typedef pair<ll, ll> pll; #define fastio ios_base::sync_with_stdio(false); cin.tie(NULL) #define pb push_back #define endl '\n' #define sz(a) a.size() #define setbits(x) __builtin_popcountll(x) #define ff first #define ss second #define conts continue #define ceil2(x, y) ((x + y - 1) / (y)) #define all(a) a.begin(), a.end() #define rall(a) a.rbegin(), a.rend() #define yes cout << "Yes" << endl #define no cout << "No" << endl #define rep(i, n) for(int i = 0; i < n; ++i) #define rep1(i, n) for(int i = 1; i <= n; ++i) #define rev(i, s, e) for(int i = s; i >= e; --i) #define trav(i, a) for(auto &i : a) template<typename T> void amin(T &a, T b) { a = min(a, b); } template<typename T> void amax(T &a, T b) { a = max(a, b); } #ifdef LOCAL #include "debug.h" #else #define debug(x) 42 #endif /* */ const int MOD = 1e9 + 7; const int N = 1e4 + 5; const int inf1 = int(1e9) + 5; const ll inf2 = ll(1e18) + 5; ll fact[N], ifact[N]; ll bexp(ll a, ll b) { a %= MOD; if (a == 0) return 0; ll res = 1; while (b) { if (b & 1) res = res * a % MOD; a = a * a % MOD; b >>= 1; } return res; } ll invmod(ll a) { return bexp(a, MOD - 2); } ll ncr(ll n, ll r) { if (n < 0 or r < 0 or n < r) return 0; return fact[n] * ifact[r] % MOD * ifact[n - r] % MOD; } ll npr(ll n, ll r) { if (n < 0 or r < 0 or n < r) return 0; return fact[n] * ifact[n - r] % MOD; } void precalc(ll n) { fact[0] = 1; rep1(i, n) fact[i] = fact[i - 1] * i % MOD; ifact[n] = invmod(fact[n]); rev(i, n - 1, 0) ifact[i] = ifact[i + 1] * (i + 1) % MOD; } void solve(int test_case) { ll n; cin >> n; vector<ll> a(n + 5); rep1(i, n) cin >> a[i]; vector<ll> dp(n + 5); dp[0] = 1; rep1(i, n) { rep1(j, i) { dp[i] += ncr(i - 1, j - 1) * dp[i - j]; dp[i] %= MOD; } } ll ans = dp[n]; cout << ans << endl; } int main() { precalc(N - 1); fastio; int t = 1; // cin >> t; rep1(i, t) { solve(i); } return 0; }
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