제출 #725654

#제출 시각아이디문제언어결과실행 시간메모리
725654FatihSolak통행료 (IOI18_highway)C++17
51 / 100
224 ms14500 KiB
#include "highway.h" #include <bits/stdc++.h> #define N 200005 using namespace std; vector<pair<int,int>> adj[N]; void find_pair(int n, vector<int> u, vector<int> v, int a, int b) { int m = u.size(); vector<int> w(m,0); long long len = ask(w) / a; int l = 0,r = m-1; while(l < r){ int m = (l + r)/2; for(int i = l;i<=m;i++){ w[i] = 1; } if(ask(w) != len * a){ for(int i = l;i<=m;i++){ w[i] = 0; } r = m; } else l = m + 1; } for(int i = 0;i<m;i++){ adj[u[i]].push_back({v[i],i}); adj[v[i]].push_back({u[i],i}); } // cout << "LEN:"; // cout << len << endl; // cout << "EDGE:"; // cout << u[l] << ' ' << v[l] << endl; queue<int> q; auto bfs = [&](int v){ vector<int> d(n,-1); vector<int> par(n,-1); queue<int> q; q.push(v); d[v] = 0; while(q.size()){ auto tp = q.front(); q.pop(); for(auto u:adj[tp]){ if(d[u.first] == -1){ d[u.first] = d[tp] + 1; par[u.first] = u.second; q.push(u.first); } } } return make_pair(d,par); }; auto x1 = bfs(u[l]); auto x2 = bfs(v[l]); vector<int> ord1; vector<int> ord2; for(int i = 0;i<n;i++){ if(x1.first[i] < x2.first[i]){ ord1.push_back(i); } else if(x2.first[i] < x1.first[i]){ ord2.push_back(i); } else{ for(auto u:adj[i]) w[u.second] = 1; } } sort(ord1.begin(),ord1.end(),[&](int a,int b){ return x1.first[a] < x1.first[b]; }); sort(ord2.begin(),ord2.end(),[&](int a,int b){ return x2.first[a] < x2.first[b]; }); // for(int i = 0;i<m;i++){ // if(w[i] == 0){ // cout << "EDGES:"; // cout << u[i] << ' ' << v[i] << endl; // } // } // cout << "FIRST COMP"; // for(auto u:ord1){ // cout << u << ' '; // } // cout << endl; // cout << "SECOND COMP"; // for(auto u:ord2){ // cout << u << ' '; // } // cout << endl; int s = -1; int t = -1; l = 0, r = (int)ord1.size() - 1; while(l < r){ int m = (l + r)/2; for(int i = m+1;i<=r;i++){ w[x1.second[ord1[i]]] = 1; } if(ask(w) == len * a){ r = m; } else{ for(int i = m+1;i<=r;i++){ w[x1.second[ord1[i]]] = 0; } l = m+1; } } s = ord1[l]; l = 0, r = (int)ord2.size() - 1; while(l < r){ int m = (l + r)/2; for(int i = m+1;i<=r;i++){ w[x2.second[ord2[i]]] = 1; } if(ask(w) == len * a){ r = m; } else{ for(int i = m+1;i<=r;i++){ w[x2.second[ord2[i]]] = 0; } l = m+1; } } t = ord2[l]; answer(s,t); } /* 4 4 1 3 1 3 0 1 0 2 0 3 1 2 */ /* 11 12 16 19 9 10 1 0 2 0 3 1 4 0 5 4 6 3 7 4 8 4 9 5 10 1 9 3 5 1 */
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