제출 #719510

#제출 시각아이디문제언어결과실행 시간메모리
719510baojiaopisuDNA 돌연변이 (IOI21_dna)C++17
100 / 100
45 ms16416 KiB
#include<bits/stdc++.h> using namespace std; using ll = long long; using ld = long double; using ull = unsigned long long; using pii = pair<int, int>; using pll = pair<ll, ll>; using pld = pair<ld, ld>; #define fi first #define se second #define left BAO #define right ANH #define pb push_back #define pf push_front #define mp make_pair #define ins insert #define btpc __builtin_popcount #define btclz __builtin_clz #define sz(x) (int)(x.size()); #define all(x) x.begin(), x.end() #define debug(...) " [" << #__VA_ARGS__ ": " << (__VA_ARGS__) << "] " mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); int d4x[4] = {1, 0, -1, 0}; int d4y[4] = {0, 1, 0, -1}; int d8x[8] = {0, 1, 1, 1, 0, -1, -1, -1}; int d8y[8] = {1, 1, 0, -1, -1, -1, 0, 1}; template<class X, class Y> bool minimize(X &x, const Y &y) { if (x > y) { x = y; return true; } return false; } template<class X, class Y> bool maximize(X &x, const Y &y) { if (x < y) { x = y; return true; } return false; } const int MOD = 1e9 + 7; //998244353 template<class X, class Y> void add(X &x, const Y &y) { x = (x + y); if(x >= MOD) x -= MOD; } template<class X, class Y> void sub(X &x, const Y &y) { x = (x - y); if(x < 0) x += MOD; } /* Author : Le Ngoc Bao Anh, 12A5, LQD High School for Gifted Student*/ const ll INF = 1e9; const int N = 1e5 + 10; int d[N][5][5], f[5][5]; int a[N], b[N], pref[N][5]; void init(string A, string B) { int n = A.size(); A = "#" + A; B = "#" + B; for(int i = 1; i <= n; i++) { if(A[i] == 'A') a[i] = 0; if(A[i] == 'T') a[i] = 1; if(A[i] == 'C') a[i] = 2; if(B[i] == 'A') b[i] = 0; if(B[i] == 'T') b[i] = 1; if(B[i] == 'C') b[i] = 2; for(int j = 0; j < 3; j++) { pref[i][j] = pref[i - 1][j] + (a[i] == j) - (b[i] == j); } for(int j = 0; j < 3; j++) { for(int k = 0; k < 3; k++) { d[i][j][k] = d[i - 1][j][k]; } } d[i][a[i]][b[i]]++; } } int get_distance(int l, int r) { l++; r++; for(int i = 0; i < 3; i++) { if(pref[r][i] != pref[l - 1][i]) return -1; } int ans = 0; for(int i = 0; i < 3; i++) { for(int j = 0; j < 3; j++) { f[i][j] = d[r][i][j] - d[l - 1][i][j]; } } for(int i = 0; i < 3; i++) { for(int j = i + 1; j < 3; j++) { int x = min(f[i][j], f[j][i]); ans += x; f[i][j] -= x; f[j][i] -= x; } } int p = 0; for(int i = 0; i < 3; i++) { for(int j = i + 1; j < 3; j++) { if(f[i][j]) p = f[i][j]; } } ans += 2 * p; return ans; }
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