이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
signed main(){
ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0);
int n,m;
cin>>n>>m;
char arr[n][m];
for(int i = 0;i<n;i++){
string s;cin>>s;
for(int j = 0;j<m;j++){
arr[i][j] = s[j];
}
}
long long l[m] = {0},left[m],right[m];
long long all = 0;
for(int i = 0;i<n;i++){
for(int j = 0;j<m;j++){
if(arr[i][j]=='.')l[j]++;
else l[j] = 0;
}
stack<int> s;
for(int j = 0;j<m;j++){
while(!s.empty()&&l[s.top()]>=l[j]){
s.pop();
}
if(s.empty())left[j] = -1;
else left[j] = s.top();
s.push(j);
}
while(!s.empty())s.pop();
for(int j = m-1;j>=0;j--){
while(!s.empty()&&l[s.top()]>l[j]){
s.pop();
}
if(s.empty())right[j] = m;
else right[j] = s.top();
s.push(j);
}
for(int j = 0;j<m;j++){
long long ans = (l[j]*(l[j]+1))/2;
long long len = (j-left[j]);
len = (len*(len+1))/2;
len*=(right[j]-j);
if(right[j]-j>1)len+=(((j-left[j])+((j-left[j])*((right[j]-j)-1)))*((right[j]-j)-1))/2;
ans*=len;
all+=ans;
}
}
cout<<all<<endl;
}
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |