Submission #713747

#TimeUsernameProblemLanguageResultExecution timeMemory
713747PixelCatMechanical Doll (IOI18_doll)C++14
6 / 100
75 ms11048 KiB
#ifdef NYAOWO #include "grader.cpp" #define OUT_VEC(x) { cout << #x << ":"; { for(auto &IT:x) cout << " " << IT; } cout << "\n"; } #else #define OUT_VEC(x) #endif #include "doll.h" #include <bits/stdc++.h> #define For(i, a, b) for(int i = a; i <= b; i++) #define F first #define S second #define all(x) x.begin(), x.end() #define sz(x) ((int)x.size()) #define eb emplace_back using namespace std; using LL = long long; using pii = pair<int, int>; const int MAXM = 100010; void create_circuit(int M, std::vector<int> A) { vector<vector<int>> adj(M + 1, vector<int>()); vector<int> x, y; int n = sz(A); For(i, 0, n - 2) { adj[A[i]].eb(A[i + 1]); } adj[A.back()].eb(0); vector<int> ans(M + 1); ans[0] = A[0]; For(i, 1, M) { if(sz(adj[i]) == 0) { ans[i] = 0; } else if(sz(adj[i]) == 1) { ans[i] = adj[i][0]; } else { int tot = sz(adj[i]); int now = sz(x) + 1; ans[i] = -now; For(j, 0, tot - 3) { x.eb(adj[i][j]); y.eb(-(now + 1)); now++; } x.eb(adj[i][tot - 2]); y.eb(adj[i][tot - 1]); } } OUT_VEC(ans); OUT_VEC(x); OUT_VEC(y); answer(ans, x, y); }
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