제출 #707011

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
707011		ToroTN	Palindromic Partitions (CEOI17_palindromic)	C++14	0 / 100	17 ms	15920 KiB

palindromic

#include<bits/stdc++.h>
using namespace std;
#define ll long long
ll t,cnt_67,cnt_97,pow_97[1000005],pow_67[1000005],MOD=1e9+7,it;
ll cnt2_67,cnt2_97,cnt,type=-1;
string s;
int main()
{
    ios_base::sync_with_stdio(0),cin.tie(0);
    pow_97[0]=1;
    pow_67[0]=1;
    for(int i=1;i<=1000000;i++)
    {
        pow_97[i]=pow_97[i-1]*97;
        pow_97[i]%=MOD;
        pow_67[i]=pow_67[i-1]*67;
        pow_67[i]%=MOD;
    }
    cin >> t;
    while(t--)
    {
        cin >> s;
        cnt_97=0;
        cnt_67=0;
        cnt2_97=0;
        cnt2_67=0;
        it=0;
        cnt=0;
        type=-1;
        for(int i=0;i<s.size()/2;i++)
        {
            cnt_67+=pow_67[it]*s[i];
            cnt_97+=pow_97[it]*s[i];
            cnt2_67*=67;
            cnt2_67+=s[s.size()-1-i];
            cnt2_97*=97;
            cnt2_97+=s[s.size()-1-i];
            ++it;
            if(cnt2_67==cnt_67&&cnt2_97==cnt_97)
            {
                //printf("%d\n",i);
                cnt_67=0;
                cnt2_67=0;
                cnt_97=0;
                cnt2_97=0;
                cnt+=2;
                if(s.size()%2==0&&i==s.size()/2-1)
                {
                    type=0;
                }
                it=0;
            }
        }
        ++cnt;
        if(type==0)--cnt;
        printf("%lld\n",cnt);
    }
}

컴파일 시 표준 에러 (stderr) 메시지

palindromic.cpp: In function 'int main()':
palindromic.cpp:30:22: warning: comparison of integer expressions of different signedness: 'int' and 'std::__cxx11::basic_string<char>::size_type' {aka 'long unsigned int'} [-Wsign-compare]
   30 |         for(int i=0;i<s.size()/2;i++)
      |                     ~^~~~~~~~~~~
palindromic.cpp:47:36: warning: comparison of integer expressions of different signedness: 'int' and 'std::__cxx11::basic_string<char>::size_type' {aka 'long unsigned int'} [-Wsign-compare]
   47 |                 if(s.size()%2==0&&i==s.size()/2-1)
      |                                   ~^~~~~~~~~~~~~~

• Subtask 1: 0 / 15
• Subtask 2: 0 / 20
• Subtask 3: 0 / 25
• Subtask 4: 0 / 40