이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "dna.h"
#define _CRT_SECURE_NO_WARNINGS
#include <bits/stdc++.h>
#define M_PI 3.14159265358979323846
#define FILER 0
using ll = long long;
using ull = unsigned long long;
using ld = long double;
const ll MOD = pow(10, 9) + 7;
const ll INFL = 0x3f3f3f3f3f3f3f3f;
const ull INFUL = 0x3f3f3f3f3f3f3f3f;
const ll INFT = 0x3f3f3f3f;
const ull MAX = 1LL << 24;
const ll MODD = 998244353;
const double EPS = 1e-10;
#define V vector
#define pll pair<ll, ll>
#define pull2 pair<ull,ull>
#define MS multiset
#define M map
#define Q queue
#define PQ priority_queue
#define IOF ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL);
#define FOR(typ,i,a,b,c) for(typ i = a; i < b; i += c)
#define FORR(typ,i,a,b,c) for(typ i = a; i > b; i -= c)
#define FORA(a,i) for(auto &i : a)
#define all(v) v.begin(),v.end()
#define sz(v) v.size()
#define sorta(a) sort(all(a))
#define sortd(a) sort(all(a), greater<ll>())
#define setp(x) setprecision(x)<<fixed
#define RET return
#define log(a,b) log(b)/log(a)
#define WH(s) while(s)
#define WHI(t) WH(t--)
#define YES cout<<"YES"<<endl;
#define NO cout<<"NO"<<endl;
#define Yes cout<<"Yes"<<endl;
#define No cout<<"No"<<endl;
#define YESNO(s) cout << (s ? "YES" : "NO") << endl;
#define YesNo(s) cout<<(s?"Yes":"No")<<endl;
#define TYP 0
using namespace std;
V<pll> pa, pc, pt;
V<ll> pf;
V<V<ll>> g;
V<bool> used;
ll res, ia, ic, it, n;
map<char, V<ll>> h;
string a, b;
void dfs(ll u)
{
used[u] = 1;
res++;
FORA(g[u], v) {if (used[v])RET; dfs(v); }
}
void init(std::string a1, std::string b1)
{
n = a1.size(); a = a1, b = b1;
}
int get_distance(int x, int y) {
x++, y++;
ll ans = 0, n1 = y-x+1;
g.assign(n1 + 1, {});
used.assign(n1 + 1, {}); h.clear();
string a1 = '$'+a.substr(x, y-1), b1 = '$'+b.substr(x, y-1);
for (auto c : { 'A','T','C' }) if (count(all(a1), c) != count(all(b1), c)) return -1;
FOR(ll, i, 1, n1 + 1, 1)
if (b1[i] != a1[i])h[b1[i]].push_back(i);
FOR(ll, i, 1, n1 + 1, 1)
{
if (b1[i] == a1[i])continue;
if (h[a1[i]].size())g[i].push_back(*h[a1[i]].begin()), h[a1[i]].erase(h[a1[i]].begin());
}
FOR(ll, i, 1, n1 + 1, 1)
{
if (!used[i]) { res = 0; dfs(i); ans += max(0LL, res - 1); }
}
return ans;
}
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