oj.uz

답안 #693923

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
693923 2023-02-03T11:55:30 Z 79brue Izvanzemaljci (COI21_izvanzemaljci) C++17
26 / 100
 64 ms 11724 KB 
#include <bits/stdc++.h>

using namespace std;

typedef long long ll;

int n, k;

void solve1();
void solve2();

int main(){
    scanf("%d %d", &n, &k);
    if(n==1){
        ll x, y;
        scanf("%lld %lld", &x, &y);
        for(int i=0; i<k; i++) printf("%lld %lld 1\n", x+i+i, y+i+i);
        return 0;
    }
    if(k==1) solve1();
    else if(k==2) solve2();
}

void solve1(){
    ll xMin = 1e9, xMax = -1e9, yMin = 1e9, yMax = -1e9;
    for(int i=1; i<=n; i++){
        ll x, y;
        scanf("%lld %lld", &x, &y);
        xMin = min(x, xMin), yMin = min(y, yMin);
        xMax = max(x, xMax), yMax = max(y, yMax);
    }
    printf("%lld %lld %lld", xMin, yMin, max(xMax - xMin, yMax - yMin));
}

void solve2(){
    vector<pair<ll, ll> > points (n);
    vector<ll> x(n), y(n);
    vector<ll> xMin1(n, 1e9), xMax1(n, -1e9), yMin1(n, 1e9), yMax1(n, -1e9);
    vector<ll> xMin2(n, 1e9), xMax2(n, -1e9), yMin2(n, 1e9), yMax2(n, -1e9);
    for(int i=0; i<n; i++) scanf("%lld %lld", &points[i].first, &points[i].second);
    sort(points.begin(), points.end());

    /// 가로로 찾기
    for(int i=0; i<n; i++){
        xMin1[i] = xMax1[i] = xMin2[i] = xMax2[i] = x[i] = points[i].first;
        yMin1[i] = yMax1[i] = yMin2[i] = yMax2[i] = y[i] = points[i].second;
    }
    for(int i=1; i<n; i++){
        xMin1[i] = min(xMin1[i], xMin1[i-1]);
        xMax1[i] = max(xMax1[i], xMax1[i-1]);
        yMin1[i] = min(yMin1[i], yMin1[i-1]);
        yMax1[i] = max(yMax1[i], yMax1[i-1]);
    }
    for(int i=n-2; i>=0; i--){
        xMin2[i] = min(xMin2[i], xMin2[i+1]);
        xMax2[i] = max(xMax2[i], xMax2[i+1]);
        yMin2[i] = min(yMin2[i], yMin2[i+1]);
        yMax2[i] = max(yMax2[i], yMax2[i+1]);
    }

    ll justone = max({1LL, xMax1[n-1] - xMin1[n-1], yMax1[n-1] - yMin1[n-1]}); /// 전체 하나로 할 경우의 답
    ll ans = INT_MAX;
    int ansIdx = -1, ansMode = -1;
    for(int i=0; i<n-1; i++){ /// i 기준 정렬
        if(x[i] == x[i+1]) continue;
        ll tmp = max({1LL, xMax1[i] - xMin1[i], yMax1[i] - yMin1[i], xMax2[i+1] - xMin2[i+1], yMax2[i+1] - yMin2[i+1]});
        if(ans > tmp) ans = tmp, ansIdx = i, ansMode = 0;
    }

    /// 세로로 찾기
    sort(points.begin(), points.end(), [&](auto &a, auto &b){
        return a.second < b.second;
    });

    /// 가로로 찾기
    for(int i=0; i<n; i++){
        xMin1[i] = xMax1[i] = xMin2[i] = xMax2[i] = x[i] = points[i].first;
        yMin1[i] = yMax1[i] = yMin2[i] = yMax2[i] = y[i] = points[i].second;
    }
    for(int i=1; i<n; i++){
        xMin1[i] = min(xMin1[i], xMin1[i-1]);
        xMax1[i] = max(xMax1[i], xMax1[i-1]);
        yMin1[i] = min(yMin1[i], yMin1[i-1]);
        yMax1[i] = max(yMax1[i], yMax1[i-1]);
    }
    for(int i=n-2; i>=0; i--){
        xMin2[i] = min(xMin2[i], xMin2[i+1]);
        xMax2[i] = max(xMax2[i], xMax2[i+1]);
        yMin2[i] = min(yMin2[i], yMin2[i+1]);
        yMax2[i] = max(yMax2[i], yMax2[i+1]);
    }

    for(int i=0; i<n-1; i++){ /// i 기준 정렬
        if(y[i] == y[i+1]) continue;
        ll tmp = max({1LL, xMax1[i] - xMin1[i], yMax1[i] - yMin1[i], xMax2[i+1] - xMin2[i+1], yMax2[i+1] - yMin2[i+1]});
        if(ans > tmp) ans = tmp, ansIdx = i, ansMode = 1;
    }

    /// 답 출력하기
    if(justone <= ans || ansMode == -1){
        printf("%lld %lld %lld\n", xMin1[n-1], yMin1[n-1], justone);
        printf("%lld %lld %lld\n", 2'000'000'000LL, 2'000'000'000LL, justone);
    }
    else if(ansMode == 0){
        sort(points.begin(), points.end());

        /// 가로로 찾기
        for(int i=0; i<n; i++){
            xMin1[i] = xMax1[i] = xMin2[i] = xMax2[i] = x[i] = points[i].first;
            yMin1[i] = yMax1[i] = yMin2[i] = yMax2[i] = y[i] = points[i].second;
        }
        for(int i=1; i<n; i++){
            xMin1[i] = min(xMin1[i], xMin1[i-1]);
            xMax1[i] = max(xMax1[i], xMax1[i-1]);
            yMin1[i] = min(yMin1[i], yMin1[i-1]);
            yMax1[i] = max(yMax1[i], yMax1[i-1]);
        }
        for(int i=n-2; i>=0; i--){
            xMin2[i] = min(xMin2[i], xMin2[i+1]);
            xMax2[i] = max(xMax2[i], xMax2[i+1]);
            yMin2[i] = min(yMin2[i], yMin2[i+1]);
            yMax2[i] = max(yMax2[i], yMax2[i+1]);
        }

        printf("%lld %lld %lld\n", xMax1[ansIdx] - ans, yMin1[ansIdx], ans);
        printf("%lld %lld %lld\n", xMin2[ansIdx+1], yMin2[ansIdx+1], ans);
    }
    else{
        printf("%lld %lld %lld\n", xMin1[ansIdx], yMax1[ansIdx] - ans, ans);
        printf("%lld %lld %lld\n", xMin2[ansIdx+1], yMin2[ansIdx+1], ans);
    }
}

Compilation message

izvanzemaljci.cpp: In function 'int main()':
izvanzemaljci.cpp:13:10: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   13 |     scanf("%d %d", &n, &k);
      |     ~~~~~^~~~~~~~~~~~~~~~~
izvanzemaljci.cpp:16:14: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   16 |         scanf("%lld %lld", &x, &y);
      |         ~~~~~^~~~~~~~~~~~~~~~~~~~~
izvanzemaljci.cpp: In function 'void solve1()':
izvanzemaljci.cpp:28:14: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   28 |         scanf("%lld %lld", &x, &y);
      |         ~~~~~^~~~~~~~~~~~~~~~~~~~~
izvanzemaljci.cpp: In function 'void solve2()':
izvanzemaljci.cpp:40:33: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   40 |     for(int i=0; i<n; i++) scanf("%lld %lld", &points[i].first, &points[i].second);
      |                            ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Subtask #1
5.0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 212 KB Output is correct
2 Correct 0 ms 212 KB Output is correct
3 Correct 0 ms 212 KB Output is correct
4 Correct 0 ms 212 KB Output is correct
5 Correct 1 ms 212 KB Output is correct
6 Correct 0 ms 212 KB Output is correct
7 Correct 23 ms 212 KB Output is correct
8 Correct 24 ms 212 KB Output is correct
9 Correct 24 ms 292 KB Output is correct
10 Correct 22 ms 296 KB Output is correct
11 Correct 24 ms 212 KB Output is correct

Subtask #2
21.0 / 21.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 212 KB Output is correct
2 Correct 0 ms 212 KB Output is correct
3 Correct 0 ms 212 KB Output is correct
4 Correct 0 ms 212 KB Output is correct
5 Correct 1 ms 212 KB Output is correct
6 Correct 0 ms 212 KB Output is correct
7 Correct 0 ms 212 KB Output is correct
8 Correct 0 ms 212 KB Output is correct
9 Correct 0 ms 212 KB Output is correct
10 Correct 52 ms 9832 KB Output is correct
11 Correct 52 ms 9844 KB Output is correct
12 Correct 51 ms 9768 KB Output is correct
13 Correct 60 ms 9832 KB Output is correct
14 Correct 52 ms 9804 KB Output is correct
15 Correct 52 ms 9776 KB Output is correct
16 Correct 64 ms 9832 KB Output is correct
17 Correct 47 ms 10804 KB Output is correct
18 Correct 46 ms 10400 KB Output is correct
19 Correct 52 ms 9500 KB Output is correct
20 Correct 52 ms 10128 KB Output is correct
21 Correct 50 ms 11636 KB Output is correct
22 Correct 53 ms 11688 KB Output is correct
23 Correct 64 ms 11724 KB Output is correct

Subtask #3
0 / 12.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 212 KB Output is correct
2 Incorrect 1 ms 212 KB Unexpected end of file - int64 expected
3 Halted 0 ms 0 KB -

Subtask #4
0 / 30.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 0 ms 212 KB Unexpected end of file - int64 expected
2 Halted 0 ms 0 KB -

Subtask #5
0 / 32.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 0 ms 212 KB Unexpected end of file - int64 expected
2 Halted 0 ms 0 KB -