제출 #685705

#제출 시각아이디문제언어결과실행 시간메모리
685705BliznetcDetecting Molecules (IOI16_molecules)C++17
0 / 100
1 ms212 KiB
#include "molecules.h" #define _CRT_SECURE_NO_WARNINGS #include <bits/stdc++.h> #define M_PI 3.14159265358979323846 #define FILER 0 using ll = long long; using ull = unsigned long long; using ld = long double; const ll MOD = pow(10, 9) + 7; const ll INFL = 0x3f3f3f3f3f3f3f3f; const ull INFUL = 0x3f3f3f3f3f3f3f3f; const ll INFT = 0x3f3f3f3f; const ull MAX = 1LL << 24; const ll MODD = 998244353; const double EPS = 1e-10; #define V vector #define pll pair<ll, ll> #define pull2 pair<ull,ull> #define MS multiset #define M map #define Q queue #define PQ priority_queue #define IOF ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); #define FOR(typ,i,a,b,c) for(typ i = a; i < b; i += c) #define FORR(typ,i,a,b,c) for(typ i = a; i > b; i -= c) #define FORA(a,i) for(auto &i : a) #define all(v) v.begin(),v.end() #define sz(v) v.size() #define sorta(a) sort(all(a)) #define sortd(a) sort(all(a), greater<ll>()) #define setp(x) setprecision(x)<<fixed #define RET return #define log(a,b) log(b)/log(a) #define WH(s) while(s) #define WHI(t) WH(t--) #define YES cout<<"YES"<<endl; #define NO cout<<"NO"<<endl; #define Yes cout<<"Yes"<<endl; #define No cout<<"No"<<endl; #define YESNO(s) cout << (s ? "YES" : "NO") << endl; #define YesNo(s) cout<<(s?"Yes":"No")<<endl; #define TYP #define F first #define S second #define pb push_back using namespace std; std::vector<int> find_subset(int l, int u, std::vector<int> w) { int n = w.size(); pair<int,int> a[n + 7]; int sum = 0; for (int i = 1; i <= n; i++) { a[i] = {w[i - 1], i}; sum += a[i].F; } sort (a + 1, a + n + 1); if (sum < l) { return {}; } int r = u; if (a[1].F > u) { return vector<int>(0); } int cur = 0; vector<int> result; for (int i = 1; i <= n; i++) { if (cur + a[i].F >= l) { if (cur + a[i].F <= r) { cur += a[i].F; result.pb(a[i].S); } break; } cur += a[i].F; result.pb(a[i].S); } if (cur < l) { for (int i = 0; i < (int)result.size(); i++) { if (cur - a[i + 1].F + a[n].F <= r) { result[i] = a[n].S; break; } } } if (cur >= l && cur <= r) { return result; } return vector<int> (0); }
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