oj.uz

답안 #681700

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
681700 2023-01-13T18:39:52 Z qwerasdfzxcl Izvanzemaljci (COI21_izvanzemaljci) C++17
68 / 100
 1004 ms 4300 KB 
#include <bits/stdc++.h>

typedef long long ll;
using namespace std;
struct Square{
    ll l, x, y;
    Square(){}
    Square(ll _l, ll _x, ll _y): l(_l), x(_x), y(_y) {}

    void print(){printf("%lld %lld %lld\n", x, y, l);}
};
pair<int, int> a[100100], a0[100100];
int mn[100100], mx[100100];

void solve1(int n){
    sort(a+1, a+n+1);
    int y1 = a[1].second, y2 = a[1].second;
    for (int i=1;i<=n;i++){
        y1 = min(y1, a[i].second);
        y2 = max(y2, a[i].second);
    }

    Square ans(max(max(a[n].first-a[1].first, y2-y1), 1), a[1].first, y1);
    ans.print();
}

pair<int, pair<Square, Square>> solve2x(int n){
    sort(a+1, a+n+1);
    a[n+1].first = 1e9+100;
    mn[n] = a[n].second;
    mx[n] = a[n].second;
    for (int i=n-1;i>0;i--){
        mn[i] = min(mn[i+1], a[i].second);
        mx[i] = max(mx[i+1], a[i].second);
    }

    int y1 = 1e9, y2 = -1e9, ans = 2e9 + 100;
    pair<Square, Square> ret;
    for (int i=1;i<=n;i++){
        y1 = min(y1, a[i].second);
        y2 = max(y2, a[i].second);

        int L1 = max(y2-y1, a[i].first-a[1].first);
        int L2 = max(mx[i+1]-mn[i+1], a[n].first-a[i+1].first);
        L1 = max(L1, 1);
        L2 = max(L2, 1);

        if (ans > max(L1, L2) && a[i].first < a[i+1].first){
            ans = max(L1, L2);
            ret = make_pair(Square(L1, (ll)a[i].first-L1, (ll)y1), Square(L2, (ll)a[i+1].first, (ll)mn[i+1]));
        }
    }

    return {ans, ret};
}

void solve2(int n){
    auto [ans1, p1] = solve2x(n);
    for (int i=1;i<=n;i++) swap(a[i].first, a[i].second);
    auto [ans2, p2] = solve2x(n);

    auto p = p1;
    if (ans2 < ans1){
        p = p2;
        swap(p.first.x, p.first.y);
        swap(p.second.x, p.second.y);
    }

    p.first.print();
    p.second.print();
}

vector<Square> rans3;
pair<int, int> b[100100];
bool solve3x(int s, int e, ll L, ll mnx){
    if (s>e){
        rans3.emplace_back(1, 2e9+5000, 2e9+5000);
        rans3.emplace_back(1, 2e9+6000, 2e9+6000);
        return 1;
    }

    sort(b+s, b+e+1);
    b[e+1].first = 1e9+100;
    mn[e] = b[e].second;
    mx[e] = b[e].second;
    for (int i=e-1;i>=s;i--){
        mn[i] = min(mn[i+1], b[i].second);
        mx[i] = max(mx[i+1], b[i].second);
    }

    ll y1 = 1e18, y2 = -1e18, ans = 1e18;
    pair<Square, Square> ret;
    for (int i=s;i<=e;i++){
        y1 = min(y1, (ll)b[i].second);
        y2 = max(y2, (ll)b[i].second);

        ll L1 = max(y2-y1, (ll)b[i].first-b[s].first);
        ll L2 = max(mx[i+1]-mn[i+1], b[e].first-b[i+1].first);
        L1 = max(L1, 1LL);
        L2 = max(L2, 1LL);

        if (ans > max(L1, L2) && b[i].first < b[i+1].first){
            ll X = min(b[i+1].first-1-L1, (ll)b[s].first);
            if (X < mnx) continue;

            ans = max(L1, L2);
            ret = make_pair(Square(L1, X, y1), Square(L2, b[i+1].first, mn[i+1]));
        }
    }

    if (ans <= L){
        rans3.push_back(ret.first);
        rans3.push_back(ret.second);
        return 1;
    }

    return 0;
}

bool solve3xx(int n, ll L){
    rans3.clear();
    sort(a+1, a+n+1);

    ll y1 = 1e18, y2 = -1e18;
    for (int i=1;i<=n+1;){
        int r = i;
        ll py1 = y1, py2 = y2;

        while(r<=n && a[i].first==a[r].first){
            y1 = min(y1, (ll)a[r].second);
            y2 = max(y2, (ll)a[r].second);
            ++r;
        }

        ll len = max((ll)a[i].first - a[1].first, y2-y1);

        if (len > L || i==n+1){
            if (py1==1e18) return 0;

            for (int j=i;j<=n;j++) b[j] = a[j];
            if (solve3x(i, n, L, a[i-1].first+1)){
                ll rlen = max((ll)a[i-1].first - a[1].first, py2-py1);
                rlen = max(rlen, 1LL);
                rans3.emplace_back(rlen, a[i-1].first-rlen, py1);
                return 1;
            }
            return 0;
        }


        i = r;
    }

    assert(0);
}

bool solve3xy(int n, ll L){
    rans3.clear();
    sort(a+1, a+n+1);

    ll y1 = 1e18, y2 = -1e18;
    for (int i=1;i<=n+1;){
        int r = i;
        ll py1 = y1, py2 = y2;

        while(r<=n && a[i].first==a[r].first){
            y1 = min(y1, (ll)a[r].second);
            y2 = max(y2, (ll)a[r].second);
            ++r;
        }

        ll len = max((ll)a[i].first - a[1].first, y2-y1);

        if (len > L || i==n+1){
            if (py1==1e18) return 0;

            for (int j=i;j<=n;j++) b[j] = {a[j].second, a[j].first};
            if (solve3x(i, n, L, -1e18)){
                for (auto &S:rans3) swap(S.x, S.y);
                ll rlen = max((ll)a[i-1].first - a[1].first, py2-py1);
                rlen = max(rlen, 1LL);
                rans3.emplace_back(rlen, a[i-1].first-rlen, py1);
                return 1;
            }
            return 0;
        }


        i = r;
    }

    assert(0);
}

bool ok(int n, ll L){
    for (int i=1;i<=n;i++) a[i] = a0[i];

    //if (L==2) printf("\nok\n");
    if (solve3xx(n, L)) return 1;

    //if (L==2) printf("ok\n");
    if (solve3xy(n, L)) return 1;
    for (int i=1;i<=n;i++) a[i].first = -a[i].first;
    //if (L==2) printf("ok\n");
    if (solve3xy(n, L)){
        for (auto &S:rans3) S.x = -S.x-S.l;
        return 1;
    }
    for (int i=1;i<=n;i++) a[i].first = -a[i].first;


    ///swap xy
    for (int i=1;i<=n;i++) swap(a[i].first, a[i].second);

    //if (L==2) printf("ok\n");
    if (solve3xx(n, L)){
        for (auto &S:rans3) swap(S.x, S.y);
        return 1;
    }
    //if (L==2) printf("ok\n");
    if (solve3xy(n, L)){
        for (auto &S:rans3) swap(S.x, S.y);
        return 1;
    }
    for (int i=1;i<=n;i++) a[i].first = -a[i].first;
    //if (L==2) printf("ok\n");
    if (solve3xy(n, L)){
        for (auto &S:rans3) S.x = -S.x-S.l;
        for (auto &S:rans3) swap(S.x, S.y);
        return 1;
    }

    return 0;
}

void solve3(int n){
    ll l = 1, r = 2e9+100, ans = -1;
    while(l<=r){
        ll m = (l+r)/2;
        if (ok(n, m)) r = m-1, ans = m;
        else l = m+1;
    }

    assert(ans!=-1);
    ok(n, ans);
    for (auto &S:rans3) S.print();
}

int main(){
    int n, k;
    scanf("%d %d", &n, &k);
    for (int i=1;i<=n;i++) scanf("%d %d", &a[i].first, &a[i].second);
    for (int i=1;i<=n;i++) a0[i] = a[i];
    if (k==1) solve1(n);
    if (k==2) solve2(n);
    if (k==3) solve3(n);
    return 0;
}

Compilation message

izvanzemaljci.cpp: In function 'int main()':
izvanzemaljci.cpp:251:10: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
  251 |     scanf("%d %d", &n, &k);
      |     ~~~~~^~~~~~~~~~~~~~~~~
izvanzemaljci.cpp:252:33: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
  252 |     for (int i=1;i<=n;i++) scanf("%d %d", &a[i].first, &a[i].second);
      |                            ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Subtask #1
5.0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 212 KB Output is correct
2 Correct 1 ms 212 KB Output is correct
3 Correct 1 ms 212 KB Output is correct
4 Correct 0 ms 212 KB Output is correct
5 Correct 0 ms 212 KB Output is correct
6 Correct 1 ms 212 KB Output is correct
7 Correct 32 ms 1740 KB Output is correct
8 Correct 31 ms 1740 KB Output is correct
9 Correct 30 ms 1852 KB Output is correct
10 Correct 31 ms 1804 KB Output is correct
11 Correct 33 ms 1868 KB Output is correct

Subtask #2
21.0 / 21.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 212 KB Output is correct
2 Correct 0 ms 212 KB Output is correct
3 Correct 1 ms 212 KB Output is correct
4 Correct 0 ms 212 KB Output is correct
5 Correct 0 ms 212 KB Output is correct
6 Correct 0 ms 212 KB Output is correct
7 Correct 0 ms 212 KB Output is correct
8 Correct 0 ms 212 KB Output is correct
9 Correct 0 ms 212 KB Output is correct
10 Correct 40 ms 2668 KB Output is correct
11 Correct 42 ms 2736 KB Output is correct
12 Correct 43 ms 2648 KB Output is correct
13 Correct 40 ms 2764 KB Output is correct
14 Correct 41 ms 2740 KB Output is correct
15 Correct 42 ms 2764 KB Output is correct
16 Correct 47 ms 2736 KB Output is correct
17 Correct 38 ms 2496 KB Output is correct
18 Correct 34 ms 2404 KB Output is correct
19 Correct 35 ms 2328 KB Output is correct
20 Correct 33 ms 2392 KB Output is correct
21 Correct 43 ms 2760 KB Output is correct
22 Correct 45 ms 2688 KB Output is correct
23 Correct 40 ms 2680 KB Output is correct

Subtask #3
12.0 / 12.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 212 KB Output is correct
2 Correct 0 ms 212 KB Output is correct
3 Correct 1 ms 316 KB Output is correct
4 Correct 1 ms 316 KB Output is correct
5 Correct 0 ms 212 KB Output is correct
6 Correct 0 ms 212 KB Output is correct
7 Correct 0 ms 212 KB Output is correct
8 Correct 0 ms 212 KB Output is correct
9 Correct 1 ms 212 KB Output is correct
10 Correct 1 ms 212 KB Output is correct
11 Correct 1 ms 340 KB Output is correct
12 Correct 1 ms 212 KB Output is correct
13 Correct 0 ms 320 KB Output is correct
14 Correct 1 ms 212 KB Output is correct
15 Correct 0 ms 212 KB Output is correct
16 Correct 1 ms 212 KB Output is correct
17 Correct 1 ms 212 KB Output is correct
18 Correct 1 ms 212 KB Output is correct
19 Correct 0 ms 340 KB Output is correct
20 Correct 1 ms 320 KB Output is correct
21 Correct 0 ms 324 KB Output is correct
22 Correct 1 ms 340 KB Output is correct
23 Correct 1 ms 212 KB Output is correct
24 Correct 1 ms 320 KB Output is correct
25 Correct 1 ms 340 KB Output is correct
26 Correct 0 ms 340 KB Output is correct

Subtask #4
30.0 / 30.0

# 결과 실행 시간 메모리 Grader output
1 Correct 10 ms 376 KB Output is correct
2 Correct 13 ms 340 KB Output is correct
3 Correct 8 ms 340 KB Output is correct
4 Correct 13 ms 384 KB Output is correct
5 Correct 12 ms 384 KB Output is correct
6 Correct 9 ms 332 KB Output is correct
7 Correct 8 ms 384 KB Output is correct
8 Correct 11 ms 332 KB Output is correct
9 Correct 11 ms 388 KB Output is correct
10 Correct 8 ms 340 KB Output is correct
11 Correct 11 ms 384 KB Output is correct
12 Correct 8 ms 340 KB Output is correct
13 Correct 8 ms 340 KB Output is correct
14 Correct 8 ms 340 KB Output is correct
15 Correct 7 ms 328 KB Output is correct
16 Correct 7 ms 340 KB Output is correct
17 Correct 5 ms 384 KB Output is correct
18 Correct 6 ms 376 KB Output is correct
19 Correct 9 ms 468 KB Output is correct
20 Correct 5 ms 328 KB Output is correct
21 Correct 5 ms 340 KB Output is correct
22 Correct 5 ms 340 KB Output is correct
23 Correct 5 ms 344 KB Output is correct
24 Correct 6 ms 380 KB Output is correct

Subtask #5
0 / 32.0

# 결과 실행 시간 메모리 Grader output
1 Correct 9 ms 324 KB Output is correct
2 Correct 8 ms 340 KB Output is correct
3 Correct 11 ms 388 KB Output is correct
4 Correct 7 ms 340 KB Output is correct
5 Correct 13 ms 388 KB Output is correct
6 Correct 9 ms 328 KB Output is correct
7 Correct 10 ms 340 KB Output is correct
8 Correct 11 ms 352 KB Output is correct
9 Correct 10 ms 328 KB Output is correct
10 Correct 8 ms 384 KB Output is correct
11 Correct 8 ms 340 KB Output is correct
12 Correct 9 ms 340 KB Output is correct
13 Correct 8 ms 384 KB Output is correct
14 Incorrect 1004 ms 4300 KB Output isn't correct
15 Halted 0 ms 0 KB -