이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include<bits/stdc++.h>
using namespace std;
#define int long long
#define endl '\n'
#define FF first
#define SS second
#define all(a) a.begin(), a.end()
#define mod (int)(1000000007)
signed main(){
ios_base::sync_with_stdio(0);cin.tie(0);
int n, k;
cin>>n>>k;
vector<int>A(n);
for(int i=0;i<n;i++){
cin>>A[i];
}
for(int i=0, a;i<n;i++){
cin>>a;
A[i]-=a;
}
sort(all(A));
vector<int>Pre(n);
Pre[0]=A[0];
int ans=1e18;
for(int i=1;i<n;i++)
Pre[i]=Pre[i-1]+A[i];
int md=(n-k)/2;
for(int i=0;i<n;i++){
int sum=0;
if(i+k-1<n){
int ind=(md>=i? k+md:md), val=A[ind];
if(ind<i){
sum=(val*(ind+1))-Pre[ind];
int len=(i-1)-(ind+1)+1+(n-1)-(i+k)+1;
sum+=Pre[n-1]-(i+k?Pre[i+k-1]:0)+(i?Pre[i-1]:0)-Pre[ind]-val*len;
}
else{
sum=Pre[n-1]-Pre[ind]-val*((n-1)-(ind+1)+1);
int len=i+(ind)-(i+k)+1;
sum+=val*len-(Pre[ind]-Pre[i+k-1]+(i?Pre[i-1]:0));
}
}
else{
int l=k-((n-1)-i+1)-1, ind=md+l, val=A[ind];
sum=(ind-(l)+1)*val-(Pre[ind]-(l?Pre[l-1]:0))+Pre[i-1]-Pre[ind]-val*(i-ind-1);
}
ans=min(ans, sum);
}
cout<<ans;
}
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