제출 #6716

#제출 시각아이디문제언어결과실행 시간메모리
6716gs13068역사적 조사 (JOI14_historical)C++98
100 / 100
1104 ms402748 KiB
#include<cstdio>
#include<memory.h>
#include<algorithm>

#define BUCKET 250

int a[100000];
int b[100000];
int c[100000];
int d[1000][100000];
long long x[1000][1000];

char ss[2097152];

inline int getnum()
{
	int t,r=0;
	do{t=getchar();}while(t<40);
	do{r=r*10+t-48;t=getchar();}while(t>40);
	return r;
}

int main()
{
	char *p;
	long long r;
	int s,e,t;
	int i,j,k,n,m;
	scanf("%d %d\n",&n,&m);
	fgets(ss,2097151,stdin);
	p=ss;
	for(i=0;i<n;i++)
	{
        while(*p<40)p++;
        while(*p>40)
		{
			a[i]=a[i]*10+*p-48;
			p++;
		}
		b[i]=a[i];
	}
	std::sort(b,b+n);
	for(i=0;i<n;i++)a[i]=std::lower_bound(b,b+n,a[i])-b;
    for(i=0;i<n/BUCKET;i++)
	{
		if(i>0)memcpy(d[i],d[i-1],n<<2);
		for(j=0;j<BUCKET;j++)d[i][a[i*BUCKET+j]]++;
	}
    for(i=0;i<n/BUCKET;i++)
	{
		memset(c,0,n<<2);
		for(j=i;j<n/BUCKET;j++)
		{
			if(j>i)x[i][j]=x[i][j-1];
			for(k=0;k<BUCKET;k++)
			{
				t=j*BUCKET+k;
				c[a[t]]++;
                if(1LL*b[a[t]]*c[a[t]]>x[i][j])x[i][j]=1LL*b[a[t]]*c[a[t]];
			}
		}
	}
	memset(c,0,n<<2);
	for(i=0;i<m;i++)
	{
		s=getnum()-1;e=getnum();
		if((s+BUCKET-1)/BUCKET<e/BUCKET)
		{
			r=x[(s+BUCKET-1)/BUCKET][e/BUCKET-1];
			for(j=s;j<(s+BUCKET-1)/BUCKET*BUCKET;j++)c[a[j]]++;
			for(j=e/BUCKET*BUCKET;j<e;j++)c[a[j]]++;
			for(j=s;j<(s+BUCKET-1)/BUCKET*BUCKET;j++)if(1LL*b[a[j]]*(c[a[j]]+d[e/BUCKET-1][a[j]]-((s+BUCKET-1)/BUCKET>0?d[(s+BUCKET-1)/BUCKET-1][a[j]]:0))>r)r=1LL*b[a[j]]*(c[a[j]]+d[e/BUCKET-1][a[j]]-((s+BUCKET-1)/BUCKET>0?d[(s+BUCKET-1)/BUCKET-1][a[j]]:0));
			for(j=e/BUCKET*BUCKET;j<e;j++)if(1LL*b[a[j]]*(c[a[j]]+d[e/BUCKET-1][a[j]]-((s+BUCKET-1)/BUCKET>0?d[(s+BUCKET-1)/BUCKET-1][a[j]]:0))>r)r=1LL*b[a[j]]*(c[a[j]]+d[e/BUCKET-1][a[j]]-((s+BUCKET-1)/BUCKET>0?d[(s+BUCKET-1)/BUCKET-1][a[j]]:0));
			for(j=s;j<(s+BUCKET-1)/BUCKET*BUCKET;j++)c[a[j]]=0;
			for(j=e/BUCKET*BUCKET;j<e;j++)c[a[j]]=0;
		}
		else
		{
			r=0;
			for(j=s;j<e;j++)c[a[j]]++;
			for(j=s;j<e;j++)if(1LL*b[a[j]]*c[a[j]]>r)r=1LL*b[a[j]]*c[a[j]];
			for(j=s;j<e;j++)c[a[j]]=0;
		}
		printf("%lld\n",r);
	}
}
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