oj.uz

답안 #66877

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
66877 2018-08-12T17:27:46 Z Benq Sailing Race (CEOI12_race) C++14
95 / 100
 2459 ms 4916 KB 
#include <bits/stdc++.h>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/assoc_container.hpp>
 
using namespace std;
using namespace __gnu_pbds;
 
typedef long long ll;
typedef long double ld;
typedef complex<ld> cd;
 
typedef pair<int, int> pi;
typedef pair<ll,ll> pl;
typedef pair<ld,ld> pd;
 
typedef vector<int> vi;
typedef vector<ld> vd;
typedef vector<ll> vl;
typedef vector<pi> vpi;
typedef vector<pl> vpl;
typedef vector<cd> vcd;
 
template <class T> using Tree = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>;
 
#define FOR(i, a, b) for (int i=a; i<(b); i++)
#define F0R(i, a) for (int i=0; i<(a); i++)
#define FORd(i,a,b) for (int i = (b)-1; i >= a; i--)
#define F0Rd(i,a) for (int i = (a)-1; i >= 0; i--)
 
#define sz(x) (int)(x).size()
#define mp make_pair
#define pb push_back
#define f first
#define s second
#define lb lower_bound
#define ub upper_bound
#define all(x) x.begin(), x.end()
 
const int MOD = 1000000007;
const ll INF = 1e18;
 
bool ok[501][501];
int N,k;
 
int nor(int x) { 
	if (x <= 0) x += N;
	if (x > N) x -= N;
	return x;
}

template<class T> void MX(T& a, T b) { a = max(a,b); }

int alt[2][501][501];
pi ret = {0,1};

void solve0() {
    FOR(len,2,N) FOR(i,1,N+1) {
        int en = nor(i+len);
        FOR(j,1,len) {
            int m = nor(i+j);
            int ex = max(alt[0][m][en],alt[1][i][m])+1;
            if (ok[i][m]) MX(alt[0][i][en],ex);
            if (ok[en][m]) MX(alt[1][i][en],ex);
        }
    }
    
    FOR(i,1,N+1) FOR(j,1,N+1) if (ok[i][j]) 
        MX(ret,{max(alt[1][i][j],alt[0][j][i])+1,i});
}

int no[2][501][501];
   
void test2(int len, int i) {
    int en = nor(i+len);
    for (int j = 0; j < len; ++j) {
        int m = nor(i+j);
        if (j && ok[m][i]) MX(ret,{no[0][i][en]+max(alt[1][m][en],alt[0][en][i])+1,m});
        if (ok[m][en]) MX(no[0][i][en],no[0][i][m]+1);
    }
}

void test4(int len, int i) {
    int st = nor(i-len);
    for (int j = 0; j < len; ++j) {
        int m = nor(i-j);
        if (j && ok[m][i]) MX(ret,{no[1][st][i]+max(alt[0][st][m],alt[1][i][st])+1,m});
        if (ok[m][st]) MX(no[1][st][i],no[1][m][i]+1);
    }
}

void solve1() {
    F0R(i,2) FOR(j,1,N+1) FOR(k,1,N+1) {
        if (j != k) no[i][j][k] = -MOD;
        else no[i][j][k] = 0;
    }
    
    FOR(len,1,N) FOR(i,1,N+1) {
        test2(len,i);
        test4(len,i);
    }
}
 
int main() {
    ios_base::sync_with_stdio(0); cin.tie(0);
    cin >> N >> k;
    // FOR(i,1,N+1) FOR(j,1,N+1) if (i != j) ok[i][j] = rand() % 2;
    FOR(i,1,N+1) {
        int x; 
        while (cin >> x) {
            if (x == 0) break;
            ok[i][x] = 1;
        }
    }
    solve0();
    if (k == 1) solve1();
    cout << ret.f << "\n" << ret.s;
}
 
/* Look for:
* the exact constraints (multiple sets are too slow for n=10^6 :( ) 
* special cases (n=1?)
* overflow (ll vs int?)
* array bounds
*/

Subtask #1
95.0 / 100.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 376 KB Output is correct
2 Correct 3 ms 664 KB Output is correct
3 Correct 2 ms 752 KB Output is correct
4 Correct 5 ms 924 KB Output is correct
5 Correct 4 ms 924 KB Output is correct
6 Correct 7 ms 1024 KB Output is correct
7 Correct 6 ms 1024 KB Output is correct
8 Correct 10 ms 1260 KB Output is correct
9 Correct 7 ms 1260 KB Output is correct
10 Correct 7 ms 1260 KB Output is correct
11 Correct 10 ms 1260 KB Output is correct
12 Correct 117 ms 2384 KB Output is correct
13 Correct 260 ms 3152 KB Output is correct
14 Correct 219 ms 3152 KB Output is correct
15 Incorrect 1642 ms 4876 KB Output isn't correct
16 Correct 2154 ms 4876 KB Output is correct
17 Correct 2040 ms 4876 KB Output is correct
18 Correct 380 ms 4876 KB Output is correct
19 Correct 2435 ms 4916 KB Output is correct
20 Correct 2459 ms 4916 KB Output is correct