제출 #66430

#제출 시각아이디문제언어결과실행 시간메모리
66430aquablitz11낙하산 고리들 (IOI12_rings)C++14
0 / 100
1016 ms58384 KiB
#include <bits/stdc++.h> using namespace std; using pii = pair<int, int>; const int N = 1e6+10; // graph data int n; vector<pii> E, ES; vector<int> G[N]; int dfs(int u, int p, int s, int t) { if (u == t) return 1; for (auto v : G[u]) if (v != p && (u != s || v != t)) { int r = dfs(v, u, s, t); if (r) return r+1; } return 0; } // dsu with copying for experimentation int par[N], mfcnt, firstcycle; int root(int u) { if (par[u] == u) return u; return par[u] = root(par[u]); } bool merge(int u, int v) { //fprintf(stderr, "merge(%d, %d)\n", u, v); u = root(u), v = root(v); if (u == v) { if (++mfcnt == 1) firstcycle = dfs(u, -1, u, v); return false; } par[u] = v; return true; } int _np[N], _nv[N], nmfcnt, tick; int &np(int u) { if (_nv[u] != tick) { _np[u] = par[u]; _nv[u] = tick; } return _np[u]; } int nroot(int u) { if (np(u) == u) return u; return np(u) = nroot(np(u)); } bool nmerge(int u, int v) { //fprintf(stderr, "nmerge(%d, %d)\n", u, v); u = nroot(u), v = nroot(v); if (u == v) return ++nmfcnt, false; np(u) = v; return true; } // state control (degree freq. histogram) int cntok, cnt3, cnt4; pii mxdeg(0, -1); void testmod(int a, int b) { if (a <= 2) --cntok; if (a == 3) --cnt3; if (a >= 4) --cnt4; if (b <= 2) ++cntok; if (b == 3) ++cnt3; if (b >= 4) ++cnt4; } // rebuild dsu with exceptions bool must_skip(int u) { if (mxdeg.first < 3) return false; if (u == mxdeg.second) return true; if (mxdeg.first == 3) { for (auto v : G[mxdeg.second]) if (v == u) return true; } return false; } void build_dsu() { //fprintf(stderr, "rebuild dsu!\n"); ES.clear(); for (int i = 0; i < n; ++i) par[i] = i; for (auto e : E) { int u = e.first, v = e.second; if (must_skip(u) || must_skip(v)) { ES.emplace_back(u, v); //fprintf(stderr, "skip edge %d %d\n", u, v); continue; } merge(e.first, e.second); } } bool modify(int u) { testmod(G[u].size()-1, G[u].size()); if (G[u].size() > mxdeg.first) { mxdeg = pii(G[u].size(), u); if (mxdeg.first == 3 || mxdeg.first == 4) return true; } return false; } // testing functions bool test(int u) { //fprintf(stderr, "test(%d)\n", u); testmod(G[u].size(), G[u].size()-1); for (auto v : G[u]) testmod(G[v].size(), G[v].size()-1); ++tick; nmfcnt = mfcnt; bool ok = cnt3 == 0 && cnt4 == 0; if (ok) for (auto e : ES) { if (e.first == u || e.second == u) continue; if (!nmerge(e.first, e.second)) ok = false; if (!ok) break; } testmod(G[u].size()-1, G[u].size()); for (auto v : G[u]) testmod(G[v].size()-1, G[v].size()); return ok; } // problem functions: void Init(int n) { //fprintf(stderr, "Init(%d)\n", n); ::n = n; build_dsu(); } void Link(int u, int v) { //fprintf(stderr, "Link(%d, %d)\n", u, v); G[u].push_back(v); G[v].push_back(u); bool m = modify(u) | modify(v); if (m) { E.emplace_back(u, v); build_dsu(); } else if (!must_skip(u) && !must_skip(v)) { E.emplace_back(u, v); merge(u, v); } else { ES.emplace_back(u, v); } } int CountCritical() { //fprintf(stderr, "CountCritical()\n"); if (mxdeg.first <= 2) { if (mfcnt > 1) return 0; else if (mfcnt == 1) return firstcycle; else return n; } if (mxdeg.first == 3) { int cnt = 0; if (test(mxdeg.second)) ++cnt; for (auto v : G[mxdeg.second]) if (test(v)) ++cnt; return cnt; } if (cnt4 > 1) return 0; return test(mxdeg.second) ? 1 : 0; }

컴파일 시 표준 에러 (stderr) 메시지

rings.cpp: In function 'bool modify(int)':
rings.cpp:107:21: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
     if (G[u].size() > mxdeg.first) {
         ~~~~~~~~~~~~^~~~~~~~~~~~~
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