제출 #658520

#제출 시각아이디문제언어결과실행 시간메모리
658520joelgun14Swap Swap Sort (CCO21_day1problem1)C++17
0 / 25
148 ms24004 KiB
// header file #include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> // pragma #pragma GCC optimize("Ofast") #pragma GCC optimize("unroll-loops") // macros #define endl "\n" #define ll long long #define mp make_pair #define ins insert #define lb lower_bound #define pb push_back #define ub upper_bound #define lll __int128 #define fi first #define se second using namespace std; using namespace __gnu_pbds; typedef tree<int, null_type, less_equal<int>, rb_tree_tag, tree_order_statistics_node_update> ordered_multiset; const int lim = 1e5 + 5; int block = sqrt(1e5); struct fenwick { long long a[lim]; fenwick() { memset(a, 0, sizeof(a)); } void update(int idx, int val) { while(idx < lim) { a[idx] += val; idx += (idx&-idx); } } long long query(int idx) { long long res = 0; while(idx > 0) { res += a[idx]; idx -= (idx&-idx); } return res; } long long query(int l, int r) { return query(r) - query(l - 1); } }; int main() { ios_base::sync_with_stdio(0); cin.tie(NULL); int n, k, q; cin >> n >> k >> q; int a[n + 1]; for(int i = 1; i <= n; ++i) cin >> a[i]; // max swaps -> (n - 1) * n / 2 // use inversion counting aja // check how many inversions would change // between 2 objects, the inversions can be counted from one of them // for the smaller one, // for each number, memo inversions? // sparse? // buat yang >= sqrt(n) -> memo aja inversionnya berapa, at most n (precomp O(nsqrtnlogn)) // buat yang <= sqrt(n) -> coba brute force, O(nsqrtnlogn) // observe: banyak inversion antara 2 elemen tidak mungkin berubah // calculate inversion in O(log) // use the fact of sqrt // sqrt + fofline // <= sqrt -> calculate inversion for each number // >= sqrt -> use <= sqrt value OR precompute int cnt[k + 1], p[k + 1]; for(int i = 1; i <= k; ++i) p[i] = i; memset(cnt, 0, sizeof(cnt)); vector<int> pos[k + 1]; for(int i = 1; i <= n; ++i) { ++cnt[a[i]], pos[a[i]].pb(i); } ll diff[q + 1]; vector<pair<pair<int, int>, int>> query; ll cur = 0; fenwick bit; for(int i = 1; i <= n; ++i) { cur += bit.query(a[i] - 1); bit.update(a[i], 1); } vector<ll> inv[k + 1]; for(int i = 1; i <= k; ++i) { if(cnt[i] > block) { int pre[n + 1]; pre[0] = 0; for(int j = 1; j <= n; ++j) { pre[j] = pre[j - 1]; if(a[j] == i) ++pre[j]; } inv[i].pb(0); for(int j = 1; j <= k; ++j) { ll res = 0; if(i != j) { for(auto x : pos[j]) { res += pre[x]; } } inv[i].pb(cnt[i] * cnt[j] - 2 * res); } } } for(int i = 1; i <= q; ++i) { int j; cin >> j; if(cnt[p[j]] <= block && cnt[p[j + 1]] <= block) { int l = 0, res = 0; for(int i = 0; i < pos[p[j]].size(); ++i) { while(l < pos[p[j + 1]].size() && pos[p[j + 1]][l] < pos[p[j]][i]) ++l; res += l; } diff[i] = cnt[p[j]] * cnt[p[j + 1]] - 2 * res; } else { if(cnt[p[j]] > cnt[p[j + 1]]) diff[i] = -inv[p[j]][p[j + 1]]; else diff[i] = inv[p[j + 1]][p[j]]; } cur += diff[i]; cout << cur << endl; swap(p[j], p[j + 1]); } return 0; }

컴파일 시 표준 에러 (stderr) 메시지

Main.cpp: In function 'int main()':
Main.cpp:112:30: warning: comparison of integer expressions of different signedness: 'int' and 'std::vector<int>::size_type' {aka 'long unsigned int'} [-Wsign-compare]
  112 |             for(int i = 0; i < pos[p[j]].size(); ++i) {
      |                            ~~^~~~~~~~~~~~~~~~~~
Main.cpp:113:25: warning: comparison of integer expressions of different signedness: 'int' and 'std::vector<int>::size_type' {aka 'long unsigned int'} [-Wsign-compare]
  113 |                 while(l < pos[p[j + 1]].size() && pos[p[j + 1]][l] < pos[p[j]][i])
      |                       ~~^~~~~~~~~~~~~~~~~~~~~~
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