# | 제출 시각 | 아이디 | 문제 | 언어 | 결과 | 실행 시간 | 메모리 |
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653603 | 2022-10-27T11:32:55 Z | AdamGS | Uplifting Excursion (BOI22_vault) | C++17 | 0 ms | 0 KB |
#include<bits/stdc++.h> #pragma GCC optimize("Ofast") using namespace std; typedef long long ll; const int maxn = 100; int M; ll L; vector<int> pos(maxn+5), neg(maxn+5); void solve(){ cin >> M >> L; for(int i = 1; i <= M; i++) cin >> neg[M-i+1]; ll ans; cin >> ans; for(int i = 1; i <= M; i++) cin >> pos[i]; int maxn3 = (maxn*maxn+1)/2*maxn; vector<ll> knapsack1(maxn3+5, -1e18), knapsack2(maxn3+5, -1e18); knapsack1[0] = knapsack2[0] = 0; for(int i = 1; i <= M; i++){ int bigof = max(pos[i], neg[i]); for(int make = maxn3 - i; make >= 0; make--){ for(int use=0; use < pos[i]; ++use) if(kanpsack1[make]<knapsack1[make-use*i]) knapsack1[make]=knapsack1[make-use*i]; for(int use=0; use<neg[i]; ++use) if(knapsack2[make]<knapsack2[make-use*i]) knapsack2[make]=knapsack2[make-use*i]; } } ll add = -1e18; for(int i = 0; i <= maxn3; i++){ ll need = L-i; if(need > 0){ continue; }else if(need == 0){ add = max(add, knapsack1[i]); }else if(-need >= maxn3 || knapsack2[-need] < 0 || knapsack1[i] < 0){ continue; }else{ add = max(add, knapsack1[i] + knapsack2[-need]); } } if(add == -1e18){ cout << "impossible\n"; }else{ cout << ans+add; } } int main(){ ios::sync_with_stdio(false); cin.tie(0); int tt = 1; // cin >> tt; while(tt--){ solve(); } }