oj.uz

답안 #646738

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
646738 2022-09-30T13:53:39 Z inksamurai Krov (COCI17_krov) C++17
112 / 140
 1500 ms 22188 KB 
#include <bits/stdc++.h>

// cut here
#ifdef _MSC_VER
#include <intrin.h>
#endif
 
namespace atcoder {
 
namespace internal {
 
int ceil_pow2(int n) {
    int x = 0;
    while ((1U << x) < (unsigned int)(n)) x++;
    return x;
}
 
int bsf(unsigned int n) {
#ifdef _MSC_VER
    unsigned long index;
    _BitScanForward(&index, n);
    return index;
#else
    return __builtin_ctz(n);
#endif
}
 
}  // namespace internal
 
}  // namespace atcoder
 
 
namespace atcoder {
 
template <class S, S (*op)(S, S), S (*e)()> struct segtree {
  public:
    segtree() : segtree(0) {}
    segtree(int n) : segtree(std::vector<S>(n, e())) {}
    segtree(const std::vector<S>& v) : _n(int(v.size())) {
        log = internal::ceil_pow2(_n);
        size = 1 << log;
        d = std::vector<S>(2 * size, e());
        for (int i = 0; i < _n; i++) d[size + i] = v[i];
        for (int i = size - 1; i >= 1; i--) {
            update(i);
        }
    }
 
    void set(int p, S x) {
        assert(0 <= p && p < _n);
        p += size;
        d[p] = x;
        for (int i = 1; i <= log; i++) update(p >> i);
    }
 
    S get(int p) {
        assert(0 <= p && p < _n);
        return d[p + size];
    }
 
    S prod(int l, int r) {
        assert(0 <= l && l <= r && r <= _n);
        S sml = e(), smr = e();
        l += size;
        r += size;
 
        while (l < r) {
            if (l & 1) sml = op(sml, d[l++]);
            if (r & 1) smr = op(d[--r], smr);
            l >>= 1;
            r >>= 1;
        }
        return op(sml, smr);
    }
 
    S all_prod() { return d[1]; }
 
    template <bool (*f)(S)> int max_right(int l) {
        return max_right(l, [](S x) { return f(x); });
    }
    template <class F> int max_right(int l, F f) {
        assert(0 <= l && l <= _n);
        assert(f(e()));
        if (l == _n) return _n;
        l += size;
        S sm = e();
        do {
            while (l % 2 == 0) l >>= 1;
            if (!f(op(sm, d[l]))) {
                while (l < size) {
                    l = (2 * l);
                    if (f(op(sm, d[l]))) {
                        sm = op(sm, d[l]);
                        l++;
                    }
                }
                return l - size;
            }
            sm = op(sm, d[l]);
            l++;
        } while ((l & -l) != l);
        return _n;
    }
 
    template <bool (*f)(S)> int min_left(int r) {
        return min_left(r, [](S x) { return f(x); });
    }
    template <class F> int min_left(int r, F f) {
        assert(0 <= r && r <= _n);
        assert(f(e()));
        if (r == 0) return 0;
        r += size;
        S sm = e();
        do {
            r--;
            while (r > 1 && (r % 2)) r >>= 1;
            if (!f(op(d[r], sm))) {
                while (r < size) {
                    r = (2 * r + 1);
                    if (f(op(d[r], sm))) {
                        sm = op(d[r], sm);
                        r--;
                    }
                }
                return r + 1 - size;
            }
            sm = op(d[r], sm);
        } while ((r & -r) != r);
        return 0;
    }
 
  private:
    int _n, size, log;
    std::vector<S> d;
 
    void update(int k) { d[k] = op(d[2 * k], d[2 * k + 1]); }
};
 
}  // namespace atcoder
// cut here 

using namespace std;
#define int ll
#define rep(i,n) for(int i=0;i<n;i++)
#define rng(i,c,n) for(int i=c;i<n;i++)
#define per(i,n) for(int i=n-1;i>=0;i--)
#define fi first
#define se second
#define pb push_back
#define sz(a) (int)a.size()
#define vec(...) vector<__VA_ARGS__>
#define _3SJjfN1 ios::sync_with_stdio(0),cin.tie(0)
typedef long long ll;
using pii=pair<int,int>;
using vi=vector<int>;
void print(){cout<<'\n';}
template<class h,class...t>
void print(const h&v,const t&...u){cout<<v<<' ',print(u...);}
// e

struct coordinates{
	vi xs;
	void clear(){
		xs.clear();
	}
	void add(int x){
		xs.pb(x);
	}
	void affine(){
		sort(xs.begin(),xs.end());
		xs.erase(unique(xs.begin(),xs.end()),xs.end());
	}
};

int op(int l,int r){return l+r;}
int e(){return 0;}

signed main(){
_3SJjfN1;
	int n;
	cin>>n;
	vi a(n);
	rep(i,n){
		cin>>a[i];
	}
	// to the left i need
	// x - pvt = y - i

	// to the right i need
	// x - y = i - pvt
	// x + pvt = i + y
	coordinates tmp;
	rep(i,n){
		tmp.add(a[i]-i);
		tmp.add(a[i]+i);
	}
	tmp.affine();
	const int m=sz(tmp.xs);

	vi idsl(n),idsr(n);
	rep(i,n){
		{
			int v=a[i]-i;
			int j=lower_bound(tmp.xs.begin(),tmp.xs.end(),v)-tmp.xs.begin();
			idsl[i]=j;
		}
		{
			int v=a[i]+i;
			int j=lower_bound(tmp.xs.begin(),tmp.xs.end(),v)-tmp.xs.begin();
			idsr[i]=j;
		}
	}

	atcoder::segtree<int,op,e> segl(m),cntl(m),segr(m),cntr(m);
	int psunl=0,pcntl=0,psunr=0,pcntr=0;

	auto af=[&](int pvt,int x)->int{
		int res=0;
		// to the left 
		int v=x-pvt;
		// >=
		int j=lower_bound(tmp.xs.begin(),tmp.xs.end(),v)-tmp.xs.begin();
		int sun=psunl,now=pcntl;
		if(j>=0 and j<sz(tmp.xs)){
			int vala=segl.prod(j,m);
			int valb=cntl.prod(j,m);
			res+=vala-valb*v;
			sun-=vala;
			now-=valb;
		}
		// <=
		if(j>=0 and j<=sz(tmp.xs)){
			res+=now*v-sun;
		}
		// to the right
		v=x+pvt;
		j=lower_bound(tmp.xs.begin(),tmp.xs.end(),v)-tmp.xs.begin();
		sun=psunr,now=pcntr;
		if(j>=0 and j<sz(tmp.xs)){
			int vala=segr.prod(j,m);
			int valb=cntr.prod(j,m);
			res+=vala-valb*v;
			sun-=vala;
			now-=valb;
		}
		// <=
		if(j>=0 and j<=sz(tmp.xs)){
			res+=now*v-sun;
		}
		return res;
	};

	rep(i,n){
		int v=a[i]+i;
		int j=idsr[i];
		psunr+=v;
		pcntr+=1;
		segr.set(j,segr.get(j)+v);
		cntr.set(j,cntr.get(j)+1);
	}
	const int inf=1e18;
	int ans=inf;
	rep(i,n){
		int l=max(i+1,n-i),r=1e9;
		while(r-l>3){
			int ml=(2*l+r)/3;
			int mr=(l+2*r)/3;
			int fl=af(i,ml);
			int fr=af(i,mr);
			if(fl<fr){
				r=mr;
			}else{
				l=ml;
			}
		}
		rng(j,l,r+1){
			ans=min(ans,af(i,j));
		}
		int v=a[i]+i;
		int j=idsr[i];
		psunr-=v;
		pcntr-=1;
		segr.set(j,segr.get(j)-v);
		cntr.set(j,cntr.get(j)-1);
		v=a[i]-i;
		j=idsl[i];
		psunl+=v;
		pcntl+=1;
		segl.set(j,segl.get(j)+v);
		cntl.set(j,cntl.get(j)+1);
	}
	print(ans);
}

Subtask #1
14.0 / 14.0

# 결과 실행 시간 메모리 Grader output
1 Correct 10 ms 468 KB Output is correct
2 Correct 11 ms 468 KB Output is correct

Subtask #2
14.0 / 14.0

# 결과 실행 시간 메모리 Grader output
1 Correct 10 ms 340 KB Output is correct
2 Correct 11 ms 528 KB Output is correct

Subtask #3
14.0 / 14.0

# 결과 실행 시간 메모리 Grader output
1 Correct 17 ms 596 KB Output is correct
2 Correct 18 ms 596 KB Output is correct

Subtask #4
14.0 / 14.0

# 결과 실행 시간 메모리 Grader output
1 Correct 27 ms 1000 KB Output is correct
2 Correct 37 ms 672 KB Output is correct

Subtask #5
14.0 / 14.0

# 결과 실행 시간 메모리 Grader output
1 Correct 28 ms 732 KB Output is correct
2 Correct 27 ms 724 KB Output is correct

Subtask #6
14.0 / 14.0

# 결과 실행 시간 메모리 Grader output
1 Correct 77 ms 1628 KB Output is correct
2 Correct 84 ms 1076 KB Output is correct
3 Correct 41 ms 1004 KB Output is correct

Subtask #7
14.0 / 14.0

# 결과 실행 시간 메모리 Grader output
1 Correct 472 ms 5732 KB Output is correct
2 Correct 336 ms 3660 KB Output is correct
3 Correct 448 ms 5780 KB Output is correct
4 Correct 560 ms 5956 KB Output is correct

Subtask #8
14.0 / 14.0

# 결과 실행 시간 메모리 Grader output
1 Correct 729 ms 6480 KB Output is correct
2 Correct 882 ms 10872 KB Output is correct
3 Correct 712 ms 11108 KB Output is correct
4 Correct 724 ms 11020 KB Output is correct

Subtask #9
0 / 14.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 1593 ms 7628 KB Time limit exceeded
2 Halted 0 ms 0 KB -

Subtask #10
0 / 14.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 1588 ms 22188 KB Time limit exceeded
2 Halted 0 ms 0 KB -