제출 #639212

#제출 시각아이디문제언어결과실행 시간메모리
639212KK_1729Autići (COCI22_autici)C++14
10 / 50
13 ms2004 KiB
#include <bits/stdc++.h> using namespace std; // -------Macros--------- #define int long long #define double long long double #define pb push_back #define str string #define vi vector<int> #define mp make_pair #define mi map<int, int> #define umi unordered_map<int, int> #define FOR(i,a,b) for (int i = (a); i < (b); ++i) #define all(a) a.begin(), a.end() #define endl "\n" // ------------------------ // --------------------------Constants------------------------------ const int INF = 1e17; const int MOD = 1e9+7; const int MOD2 = 998244353; // const long long double PI = 3.1415926535897932384626433832795028841971693993751058209749445923078164062862089986280348253421170679; // ------------------------------------------------------------------- // ----------------------Pre Written Functions--------------------------- int sum(vector<int> a){ // Returns the sum of values in a vector<int> int total = 0; for (int x : a) total += x; return total; } template<typename T> void printVector(T a){ // cout << "[ "; for (auto x: a) cout << x << " "; // cout << "]" << endl; } template<typename T> void printMap(T a){ cout << "{ "; for (auto x: a){ cout << x.first << ": " << x.second << " "; } cout << "}" << endl; } int gcd(int a, int b) { if (b == 0) return a; return gcd(b, a % b); } // Function to return LCM of two numbers int lcm(int a, int b) { return (a / gcd(a, b)) * b; } // ------------------------------------------------------------------------ vi decToBinary(int n) { // array to store binary number vi binaryNum(100); // counter for binary array int i = 0; while (n > 0) { // storing remainder in binary array binaryNum[i] = n % 2; n = n / 2; i++; } return binaryNum; } int ceildiv(int x, int y){ return (x+y-1)/y; } int min_element(vi a){ int m = 10000000000000; for (auto x: a){ m = min(m, x); } return m; } int max_element(vi a){ int m = -1; for (auto x: a){ m = max(m, x); } return m; } void solve(){ int n; cin >> n; vi a(n); FOR(i,0,n) cin >> a[i]; // printVector(a); // cout << endl; sort(all(a)); if (n == 1){ cout << 0 << endl; return; } int ans = 0; FOR(i,0,n){ if (i < n-2) ans += 2*a[i]; else ans += a[i]; // cout << a[i] << endl; } // printVector(a); cout << ans << endl; } int32_t main(){ // FastIO ios::sync_with_stdio(false);cin.tie(0);cout.tie(0); // freopen("input.txt", "r", stdin); // freopen("output.txt", "w", stdout); // int t; cin >> t; int t = 1; while (t--) solve(); }
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