이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include<bits/stdc++.h>
#include "boxes.h"
using namespace std;
#define MAX 1000006
#define ll long long
#define umin(x,y) x=min(x,y)
#define umax(x,y) x=max(x,y)
#define inf 100000000000000000
int Left[MAX],Right[MAX];
ll sumR[MAX],sumL[MAX];
long long delivery(int N, int K, int L, int P[]) {
int curL=0,curR=0;
int pro=0;
for(int i=0;i<N;i++) {
if(P[i]==0) continue ;
if(P[i]<=(L-1)/2) {
Left[curL++]=P[i];
}
else if(P[i]>=(L%2?(L+1)/2:L/2+1)) {
Right[curR++]=P[i];
}
else {
pro++;
}
}
for(int i=0;i<curR;i++) {
if(i-K>=0) sumR[i]=sumR[i-K]+Right[i]*2;
else sumR[i]=Right[i]*2;
}
for(int i=0;i<curL;i++) {
if(i-K>=0) sumL[i]=sumL[i-K]+Left[i]*2;
else sumL[i]=Left[i]*2;
}
ll ans=(pro+K-1)/K*L/2;
int rem=(pro?K-pro%K:0);
ll add=inf;
for(int i=0;i<=(N-pro+K-1)/K;i++) {
int use=min(rem+i*K,N-pro);
ll cev=inf;
for(int j=0;j<=use;j++) {
umin(cev,(curR-1-j>=0?sumR[curR-1-j]:0)+(curL-1-use+j>=0?sumL[curL-1-use+j]:0));
}
umin(add,cev+1ll*L*i);
}
return ans+add;
}
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