답안 #62701

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
62701 2018-07-29T20:40:56 Z eriksuenderhauf Sailing Race (CEOI12_race) C++11
90 / 100
3000 ms 7808 KB
#pragma GCC optimize("O3")
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#define enl printf("\n")
#define case(t) printf("Case #%d: ", (t))
#define ni(n) scanf("%d", &(n))
#define nl(n) scanf("%I64d", &(n))
#define nai(a, n) for (int i = 0; i < (n); i++) ni(a[i])
#define nal(a, n) for (int i = 0; i < (n); i++) nl(a[i])
#define pri(n) printf("%d\n", (n))
#define prl(n) printf("%I64d\n", (n))
#define pii pair<int, int>
#define pll pair<long long, long long>
#define vii vector<pii>
#define vi vector<int>
#define pb push_back
#define mp make_pair
#define fi first
#define se second
using namespace std;
using namespace __gnu_pbds;
typedef long long ll;
typedef cc_hash_table<int,int,hash<int>> ht;
const double pi = acos(-1);
const int MOD = 1e9 + 7;
const int INF = 1e9 + 7;
const int MAXN = 5e2 + 5;
const double eps = 1e-9;
int ans[MAXN], mx[MAXN][MAXN][2];
int dp[MAXN][MAXN][2], dp2[MAXN][MAXN][2];
bool adj[MAXN][MAXN];
int n;

int pr(int& x)
{
    x--;
    if (x < 1) x += n;
}

int nx(int& x)
{
    x++;
    if (x > n) x -= n;
}

int norm(int x)
{
    if (x < 1) return x + n;
    if (x > n) return x - n;
    return x;
}

int solve(int l, int r, int k) // path ends at r, interval at l
{
    if (dp[l][r][k] != -1)
        return dp[l][r][k];
    int ret = 0;
    if (k) { // ccw
        for (int i = norm(r + 1); i != l; nx(i))
            if (adj[r][i])
                ret = max(ret, max(solve(r, i, 0),  solve(l, i, 1)) + 1);
    } else { // cw
        for (int i = norm(l + 1); i != r; nx(i))
            if (adj[r][i])
                ret = max(ret, max(solve(r, i, 1), solve(l, i, 0)) + 1);
    }
    return dp[l][r][k] = ret;
}

int f2(int l, int r, int k)
{
    if (l == r)
        return 0;
    if (dp2[l][r][k] != -1)
        return dp2[l][r][k];
    int ret = adj[l][r] ? 0 : -INF;
    if (k) {
        for (int i = norm(r + 1); i != l; nx(i))
            if (adj[l][i])
                ret = max(ret, f2(i, r, 1));
    } else {
        for (int i = norm(l + 1); i != r; nx(i))
            if (adj[l][i])
                ret = max(ret, f2(i, r, 0));
    }
    return dp2[l][r][k] = ret + 1;
}

int main()
{
    for (int i = 0; i < MAXN; i++)
        for (int j = 0; j < MAXN; j++)
            dp[i][j][0] = dp[i][j][1] = -1,
            dp2[i][j][0] = dp2[i][j][1] = -1;
    int k;
    ni(n), ni(k);
    for (int i = 1; i <= n; i++)
    {
        for (;;)
        {
            int x;
            ni(x);
            if (x == 0)
                break;
            adj[i][x] = 1;
        }
    }
    for (int i = 1; i <= n; i++)
        for (int j = 1; j <= n; j++)
        {
            if (!adj[i][j])
                continue;
            ans[i] = max(ans[i], solve(i, j, 0) + 1);
            ans[i] = max(ans[i], solve(i, j, 1) + 1);
        }
    for (int i = 1; k == 1 && i <= n; i++)
    {
        memset(mx, 0, sizeof mx);
        for (int x = norm(i + 1); x != i; nx(x))
            for (int y = norm(x + 2); y != i; nx(y))
                if (adj[i][norm(y - 1)])
                    mx[x][y][0] = max(solve(x, norm(y - 1), 0) + 1, mx[x][norm(y - 1)][0]);
                else
                    mx[x][y][0] = max(0, mx[x][norm(y - 1)][0]);
        for (int x = norm(i - 1); x != i; pr(x))
            for (int y = norm(x - 2); y != i; pr(y))
                if (adj[i][norm(y + 1)])
                    mx[y][x][1] = max(solve(x, norm(y + 1), 1) + 1, mx[norm(y + 1)][x][1]);
                else
                    mx[y][x][1] = max(0, mx[norm(y + 1)][x][1]);

        for (int l = norm(i + 1); l != norm(i - 2); nx(l))
            for (int j = norm(l + 2); j != i; nx(j))
                if (adj[l][j])
                {
                    ans[l] = max(ans[l], f2(j, i, 0) + mx[l][j][0] + 1);
                    ans[l] = max(ans[l], f2(j, i, 0) + mx[l][j][1] + 1);
                }
        for (int l = norm(i + 1); l != norm(i - 2); nx(l))
            for (int j = norm(l + 2); j != i; nx(j))
                if (adj[j][l])
                {
                    ans[j] = max(ans[j], f2(l, i, 1) + mx[l][j][0] + 1);
                    ans[j] = max(ans[j], f2(l, i, 1) + mx[l][j][1] + 1);
                }
    }
    int ind = 0;
    for (int i = 1; i <= n; i++)
        if (ans[ind] < ans[i])
            ind = i;
    printf("%d\n%d\n", ans[ind], ind);
    return 0;
}

Compilation message

race.cpp: In function 'int pr(int&)':
race.cpp:39:1: warning: no return statement in function returning non-void [-Wreturn-type]
 }
 ^
race.cpp: In function 'int nx(int&)':
race.cpp:45:1: warning: no return statement in function returning non-void [-Wreturn-type]
 }
 ^
race.cpp: In function 'int main()':
race.cpp:97:10: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
     ni(n), ni(k);
          ^
race.cpp:97:10: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
race.cpp:7:20: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
 #define ni(n) scanf("%d", &(n))
               ~~~~~^~~~~~~~~~~~
race.cpp:103:13: note: in expansion of macro 'ni'
             ni(x);
             ^~
# 결과 실행 시간 메모리 Grader output
1 Correct 6 ms 4344 KB Output is correct
2 Correct 10 ms 6504 KB Output is correct
3 Correct 12 ms 6504 KB Output is correct
4 Correct 16 ms 6548 KB Output is correct
5 Correct 8 ms 6548 KB Output is correct
6 Correct 21 ms 6588 KB Output is correct
7 Correct 11 ms 6588 KB Output is correct
8 Correct 30 ms 6848 KB Output is correct
9 Correct 14 ms 6848 KB Output is correct
10 Correct 11 ms 6848 KB Output is correct
11 Correct 14 ms 6848 KB Output is correct
12 Correct 167 ms 6956 KB Output is correct
13 Correct 574 ms 7156 KB Output is correct
14 Correct 140 ms 7156 KB Output is correct
15 Correct 2920 ms 7236 KB Output is correct
16 Correct 2679 ms 7480 KB Output is correct
17 Correct 2649 ms 7556 KB Output is correct
18 Correct 238 ms 7556 KB Output is correct
19 Execution timed out 3035 ms 7768 KB Time limit exceeded
20 Execution timed out 3016 ms 7808 KB Time limit exceeded