이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#pragma GCC target("sse,sse2,avx2")
#pragma GCC optimize("unroll-loops,O2")
#define rep(i,l,r) for (int i = l; i < r; i++)
#define repr(i,r,l) for (int i = r; i >= l; i--)
#define X first
#define Y second
#define all(x) (x).begin() , (x).end()
#define pb push_back
#define endl '\n'
#define debug(x) cerr << #x << " : " << x << endl;
using namespace std;
typedef long long ll;
typedef long double ld;
typedef pair<int,int> pll;
constexpr int N = 50+10,mod = 998244353,inf = 1e9+10,sq = 700;
inline int mkay(int a,int b){
if (a+b >= mod) return a+b-mod;
if (a+b < 0) return a+b+mod;
return a+b;
}
inline int poww(int a,int k){
if (k < 0) return 0;
int z = 1;
while (k){
if (k&1) z = 1ll*z*a%mod;
a = 1ll*a*a%mod;
k /= 2;
}
return z;
}
int a[N][N];
int main(){
ios :: sync_with_stdio(0); cin.tie(0);
int n,m;
cin >> n >> m;
ll ans = 0;
while (m--){
int u,v;
cin >> u >> v;
if (a[u][v] == 1){
cout << ans << endl;
continue;
}
a[u][v] = 1;
bool f = 1;
ans++;
while (f){
f = 0;
rep(x,1,n+1){
rep(y,1,n+1){
if (!a[x][y] || !a[y][x]) continue;
rep(z,1,n+1){
if (z == y || a[z][y] || !a[z][x]) continue;
a[z][y] = 1;
f = 1;
ans++;
}
}
}
}
cout << ans << endl;
}
}
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |