제출 #623428

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
623428		yuto1115	친구 (IOI14_friend)	C++17	46 / 100	28 ms	1368 KiB

friend

#include "friend.h"
#include <bits/stdc++.h>
#define rep(i, n) for(ll i = 0; i < ll(n); ++i)
#define rep2(i, s, n) for(ll i = ll(s); i < ll(n); ++i)
#define rrep(i, n) for(ll i = ll(n) - 1; i >= 0; --i)
#define rrep2(i, n, t) for(ll i = ll(n) - 1; i >= ll(t); --i)
#define pb push_back
#define eb emplace_back
#define SZ(a) int(a.size())
#define all(a) a.begin(), a.end()
using namespace std;
using ll = long long;
using P = pair<int, int>;
using vi = vector<int>;
using vvi = vector<vi>;
using vl = vector<ll>;
using vvl = vector<vl>;
using vp = vector<P>;
using vvp = vector<vp>;
using vb = vector<bool>;
using vvb = vector<vb>;
using vs = vector<string>;
const int inf = 1001001001;
const ll linf = 1001001001001001001;

template<class T>
bool chmin(T &a, T b) {
    if (a > b) {
        a = b;
        return true;
    }
    return false;
}

template<class T>
bool chmax(T &a, T b) {
    if (a < b) {
        a = b;
        return true;
    }
    return false;
}

// Find out best sample
int findSample(int n, int confidence[], int host[], int protocol[]) {
    if (n <= 10) {
        vvb G(n, vb(n));
        rep2(nx, 1, n) {
            int i = host[nx];
            if (protocol[nx] != 1) G[i][nx] = G[nx][i] = true;
            if (protocol[nx] != 0) {
                rep(j, nx) {
                    if (!G[i][j]) continue;
                    G[j][nx] = G[nx][j] = true;
                }
            }
        }
        int mx = 0;
        rep(bit, 1 << n) {
            bool ok = true;
            rep(i, n) rep(j, n) {
                    if ((bit >> i & 1) and (bit >> j & 1) and G[i][j]) ok = false;
                }
            if (!ok) continue;
            int now = 0;
            rep(i, n) if (bit >> i & 1) now += confidence[i];
            chmax(mx, now);
        }
        return mx;
    } else if (*min_element(protocol + 1, protocol + n) == *max_element(protocol + 1, protocol + n)) {
        if (protocol[1] == 0) {
            vvi G(n);
            rep2(i, 1, n) {
                G[i].pb(host[i]);
                G[host[i]].pb(i);
            }
            auto dfs = [&](auto &dfs, int u, int p) -> P {
                P res(0, confidence[u]);
                for (int v: G[u]) {
                    if (v == p) continue;
                    P now = dfs(dfs, v, u);
                    res.first += max(now.first, now.second);
                    res.second += now.first;
                }
                return res;
            };
            P ans = dfs(dfs, 0, -1);
            return max(ans.first, ans.second);
        } else if (protocol[1] == 1) {
            return accumulate(confidence, confidence + n, 0);
        } else {
            return *max_element(confidence, confidence + n);
        }
    } else {
        return 0;
    }
}

• Subtask 1: 11 / 11
• Subtask 2: 8 / 8
• Subtask 3: 8 / 8
• Subtask 4: 19 / 19
• Subtask 5: 0 / 23
• Subtask 6: 0 / 31