이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#pragma GCC optimize ("O3")
#include "doll.h"
#include <bits/stdc++.h>
#define pii pair<int, int>
#define piii pair<pii, int>
#define vi vector<int>
#define vvi vector<vi>
#define vpii vector<pii>
#define vvpii vector<vpii>
#define f first
#define s second
#define oo 1000000001
#define eb emplace_back
#define pb push_back
#define mpr make_pair
#define size(v) (int)v.size()
#define ln '\n'
#define ull unsigned long long
#define ll long long
#define all(v) v.begin(), v.end()
using namespace std;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
void create_circuit(int M, vi A) {
int N = size(A);
A.eb(0);
vvi g(M + 1);
for (int i = 0; i < N; ++i) {
g[A[i]].eb(A[i + 1]);
}
vi C(M + 1, 0), X, Y;
int S = 0;
C[0] = A[0];
for (int i = 1; i <= M; ++i) {
int ways = size(g[i]);
if (ways) {
int pins = 2;
C[i] = -(S + pins - 1);
X.eb(oo);
Y.eb(oo);
while (pins < ways) {
for (int j = pins / 2; j < pins; ++j) {
X[S + j - 1] = -(S + 2 * j);
Y[S + j - 1] = -(S + 2 * j + 1);
X.eb(oo);
Y.eb(oo);
X.eb(oo);
Y.eb(oo);
}
pins *= 2;
}
vi order;
order.eb(pins);
int sz = 1;
while (pins != 1) {
pins /= 2;
for (int j = 0; j < sz; ++j) {
order.eb(order[j] + pins);
}
sz *= 2;
}
while (!order.empty()) {
--ways;
if ((order.back() & 1)) {
Y[S + order.back() / 2 - 1] = (ways >= 0 ? g[i][ways] : -(S + 1));
} else {
X[S + order.back() / 2 - 1] = (ways >= 0 ? g[i][ways] : -(S + 1));
}
order.pop_back();
}
S = size(X);
}
}
for (int i = 0; i < S; ++i) {
if (Y[i] == oo) {
Y[i] = X[i];
X[i] = -(i + 1);
}
}
answer(C, X, Y);
}
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