#include "homecoming.h"
#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define inf 1000000000000000000
#define umax(x,y) x=max(x,y)
ll psum[2000005],psum2[2000005];
long long solve(int N, int K, int *A, int *B) {
vector< vector<ll> > dp[2];
for(int i=0;i<2;i++) {
dp[i].resize(N+2);
for(int j=0;j<N+2;j++) {
dp[i][j].resize(K+1);
}
}
for(int i=N;i>=1;i--) {
A[i]=A[i-1];
B[i]=B[i-1];
}
for(int i=1;i<=N;i++) psum[i]=psum[i-1]+B[i],psum2[i]=psum2[i-1]+A[i];
for(int i=1;i<=N;i++) for(int j=0;j<=min(i-1,K);j++) for(int t=0;t<2;t++) dp[t][i][j]=-inf;
dp[1][1][0]=0;
for(int i=1;i<=N;i++) {
for(int j=0;j<=min(i-1,K);j++) {
umax(dp[1][i+1][j+(j==i-1)],dp[1][i][j]-B[i]+(i+1-K+1>=1?A[i+1-K+1]:0));
umax(dp[0][i+1][j],dp[1][i][j]);
if(i+K<=N+1) {
umax(dp[1][i+K][j],dp[0][i][j]+A[i]-(psum[i+K-1]-psum[i-1]));
}
else {
int amount=min(N+1-i,j+N+1-i-K+1);
umax(dp[1][K+1][j],dp[0][i][j]+psum2[i+amount-1]-psum2[i-1]);
}
umax(dp[0][i+1][j],dp[0][i][j]);
}
}
ll res=0;
for(int i=0;i<=min(N-1,K);i++) umax(res,max(dp[0][N+1][i],dp[1][N+1][i]));
return res;
}
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Incorrect |
2 ms |
376 KB |
Output isn't correct |
2 |
Halted |
0 ms |
0 KB |
- |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Incorrect |
2 ms |
376 KB |
Output isn't correct |
2 |
Halted |
0 ms |
0 KB |
- |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Incorrect |
192 ms |
82536 KB |
Output isn't correct |
2 |
Halted |
0 ms |
0 KB |
- |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Incorrect |
2 ms |
376 KB |
Output isn't correct |
2 |
Halted |
0 ms |
0 KB |
- |