제출 #615843

#제출 시각아이디문제언어결과실행 시간메모리
615843Koosha_mv버섯 세기 (IOI20_mushrooms)C++14
25 / 100
155 ms32612 KiB
#include "mushrooms.h"
#include <bits/stdc++.h>
using namespace std;
#define dbgv(v) cout<<#v<<" = "; f(i,0,int(v.size())) cout<<v[i]<<" "; cout<<endl
#define dbga(a,x,y) cout<<#a<<" = "; f(i,x,y) cout<<a[i]<<" "; cout<<endl
#define erorp(x) cout<<#x<<"={"<<x.F<<" , "<<x.S<<"}"<<endl
#define eror(x) cout<<#x<<'='<<(x)<<endl
#define f_(i,a,b) for(int i=a;i>=b;i--)
#define f(i,a,b) for(int i=a;i<b;i++)
#define nb(x) __builtin_popcount(x)
#define all(v) v.begin(),v.end()
#define bit(n,k) (((n)>>(k))&1)
#define Add(x,y) x=(x+y)%mod
#define maxm(a,b) a=max(a,b)
#define minm(a,b) a=min(a,b)
#define lst(x) x[x.size()-1]
#define sz(x) int(x.size())
#define mp make_pair
#define ll long long
#define pb push_back
#define S second
#define F first
 
const int N=20202,M=404;
 
int n,ans,dp[N][M];
vector<int> A,B;

int calc(int n,int x){
  if(n<=0 || x>=M) return 0;
  if(dp[n][x]!=-1) return dp[n][x];
  return dp[n][x]=min(calc(n-2,x+2),calc(n-(x+1)/2,x+1))+1; 
}

int get(vector<int> vec){
	if(vec.size()<=A.size()){
		vector<int> res;
		f(i,0,int(vec.size())) res.pb(vec[i]),res.pb(A[i]);
		int prt=use_machine(res);
		if(prt&1) B.pb(vec[0]);
		else A.pb(vec[0]);
		prt=(prt+1)/2;
		return int(vec.size())-prt;
	}
	else{
		vector<int> res;
		f(i,0,int(vec.size())) res.pb(vec[i]),res.pb(B[i]);
		int prt=use_machine(res);
		if(prt&1) A.pb(vec[0]);
		else B.pb(vec[0]);
		prt=(prt+1)/2;
		return prt;
	}
}
int count_mushrooms(int _n) {
	f(i,0,N) f(j,0,M) dp[i][j]=1;
	n=_n;
	A.pb(0);
	ans=A.size();
	vector<int> vec;
	f(i,1,n){
		vec.pb(i);
		if(vec.size()==2 && int(B.size())>0 && max(int(A.size()),int(B.size()))>1){
			if(A.size()>=2 && B.size()>=1){
				vector<int> res;
				res.pb(A[0]);
				res.pb(vec[0]);
				res.pb(A[1]);
				res.pb(B[0]);
				res.pb(vec[1]);
				int prt=use_machine(res)-1;
				if(prt&2){
					B.pb(vec[0]);
				}
				else{
					ans++;
					A.pb(vec[0]);
				}
				if(prt&1){
					ans++;
					A.pb(vec[1]);
				}
				else{
					B.pb(vec[1]);
				}
			}
			else{
				vector<int> res;
				res.pb(B[0]);
				res.pb(vec[0]);
				res.pb(B[1]);
				res.pb(A[0]);
				res.pb(vec[1]);
				int prt=use_machine(res)-1;
				if(prt&2){
					ans++;
					A.pb(vec[0]);
				}
				else{
					B.pb(vec[0]);
				}
				if(prt&1){
					B.pb(vec[1]);
				}
				else{
					ans++;
					A.pb(vec[1]);
				}
			}
			vec.clear();
		}
		else if(i==n-1 || int(vec.size())>=max(int(A.size()),int(B.size()))){
			ans+=get(vec);
			vec.clear();
		}
	}
	return ans;
}
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