제출 #614098

#제출 시각아이디문제언어결과실행 시간메모리
614098skittles1412버섯 세기 (IOI20_mushrooms)C++17
0 / 100
403 ms296 KiB
#include "bits/extc++.h" using namespace std; template <typename T> void dbgh(const T& t) { cerr << t << endl; } template <typename T, typename... U> void dbgh(const T& t, const U&... u) { cerr << t << " | "; dbgh(u...); } #ifdef DEBUG #define dbg(...) \ cerr << "L" << __LINE__ << " [" << #__VA_ARGS__ << "]: "; \ dbgh(__VA_ARGS__); #else #define dbg(...) #define cerr \ if (false) \ cerr #endif #define endl "\n" #define long int64_t #define sz(x) int((x).size()) template <typename T> ostream& operator<<(ostream& out, const vector<T>& arr) { for (int i = 0; i < sz(arr); i++) { if (i) { out << " "; } out << arr[i]; } return out; } int use_machine(std::vector<int> x); const int bsize = 93; template <typename T> struct DT { vector<int> query; vector<T> res; operator bool() const { return sz(query); } }; template <typename U, typename T> U feach(int n, int x, int y, const T& t) { vector<int> perm(n); iota(begin(perm), end(perm), 2); perm.insert(perm.end(), x, 0); perm.insert(perm.end(), y, 1); do { U cur = t(perm); if (cur) { return cur; } } while (next_permutation(begin(perm), end(perm))); return U {}; } int eval(int mask, const vector<int>& perm) { auto get = [&](int ind) -> int { if (perm[ind] >= 2) { return (mask >> (perm[ind] - 2)) & 1; } return perm[ind]; }; int ans = 0; for (int i = 0; i < sz(perm) - 1; i++) { ans += get(i) != get(i + 1); } return ans; } // n unknowns, x zeroes, y ones DT<DT<int>> compute_dt(int n, int x, int y) { int tot = n + x + y; return feach<DT<DT<int>>>(n, x, y, [&](const vector<int>& perm) { vector<int> res[tot]; for (int i = 0; i < (1 << n); i++) { res[eval(i, perm)].push_back(i); } DT<DT<int>> ans; ans.query = perm; for (auto& a : res) { DT<int> cur = feach<DT<int>>(n, x, y, [&](const vector<int>& perm) { DT<int> ans2; ans2.query = perm; ans2.res.resize(tot, -1); for (auto& b : a) { int cur = eval(b, perm); if (ans2.res[cur] != -1) { return DT<int> {}; } ans2.res[cur] = b; } return ans2; }); if (!cur) { return DT<DT<int>> {}; } ans.res.push_back(cur); } return ans; }); } struct State { int i = 1, ans = 0, n; vector<int> inds[2]; map<array<int, 3>, DT<DT<int>>> cache; State(int n) : n(n), inds {{0}, {}} {} int query(const vector<int>& arr, const vector<int>& vars) { int cind[2] {}; vector<int> cur; for (auto& a : arr) { if (a < 2) { cur.push_back(inds[a][cind[a]++]); } else { cur.push_back(vars[a - 2]); } } dbg(arr, cur); return use_machine(cur); } void eval(int n, int x, int y) { n = min(n, this->n - i); auto [it, inserted] = cache.insert({{n, x, y}, {}}); if (inserted) { it->second = compute_dt(n, x, y); } vector<int> vars; for (int i = 0; i < n; i++) { vars.push_back(this->i++); } eval(it->second, vars); } void eval(const DT<DT<int>>& dt, const vector<int>& vars) { eval(dt.res[query(dt.query, vars)], vars); } void eval(const DT<int>& dt, const vector<int>& vars) { vector<int> poss; for (int i = 0; i < sz(dt.res); i++) { if (dt.res[i] != -1) { poss.push_back(dt.res[i]); } } int ans; if (sz(poss) == 1) { ans = poss[0]; } else { ans = dt.res[query(dt.query, vars)]; } for (int i = 0; i < sz(vars); i++) { inds[(ans >> i) & 1].push_back(vars[i]); } } void eval_opt() { int a = sz(inds[0]), b = sz(inds[1]); if (a == 1 && b == 0) { eval(1, 1, 0); } else if (a + b == 2) { eval(2, a, b); } else { assert(a + b >= 4); if (a && b) { int ax = min(a, 3), bx = 4 - ax; assert(ax <= a && bx <= b); eval(5, ax, bx); } else { assert(a >= 4 && !b); eval(4, 4, 0); } } } void query_mult() { int cind; if (sz(inds[0]) >= sz(inds[1])) { cind = 0; } else { cind = 1; } vector<int> cur; for (int j = 0; i < n && j < sz(inds[cind]); i++, j++) { cur.push_back(inds[cind][j]); cur.push_back(i); } int cans = use_machine(cur), x = (cans + 1) / 2; if (!cind) { ans += sz(cur) / 2 - x; } else { ans += x; } if (cans & 1) { inds[cind ^ 1].push_back(cur.back()); } else { inds[cind].push_back(cur.back()); } } int solve() { while (i < n) { query_mult(); } return sz(inds[0]) + ans; } }; int count_mushrooms(int n) { State state(n); while (state.i < n && state.i < 2 * bsize - 1) { state.eval_opt(); dbg(state.inds[0], state.inds[1]); } return state.solve(); }
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