oj.uz

답안 #613962

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
613962 2022-07-30T14:49:15 Z HediChehaidar Monochrome Points (JOI20_monochrome) C++17
0 / 100
 0 ms 328 KB 
#include<bits/stdc++.h>
typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;
typedef double db;
ll gcd(ll a , ll b) {return b ? gcd(b , a % b) : a ;} // greatest common divisor (PGCD)
ll lcm(ll a , ll b) {return (a * b) / gcd(a , b);} // least common multiple (PPCM)
#define ss second
#define ff first
#define all(x) (x).begin() , (x).end()
#define pb push_back
#define vi vector<int>
#define vii vector<pair<int,int>>
#define vl vector<ll>
#define vll vector<pair<ll,ll>>
#define pii pair<int,int>
#define pll pair<ll,ll>
#define pdd  pair<double,double>
#define vdd  vector<pdd>
#define dte  tuple<double , double , double>
using namespace std;
const int INF = 1000*1000*1000; // 1 e 9
const int MOD = 1e9 + 7;//998244353 ;
const double EPS = 0.000000001; // 1 e -9
const ll inf = (ll)1e18;

int n;
string s;
vi v[2];
int st[(int)2e6 + 10];
void update(int pos , int l , int r , int i){
    if(i > r || i  < l) return ;
    if(l == r){
        st[pos] = 1; return ;
    }
    update(2 * pos + 1 , l , (l+r) / 2 , i); update(2 * pos + 2 , (l+r) / 2 + 1 , r, i );
    st[pos] = st[2 * pos + 1] + st[2 * pos + 2];
}
int rq(int pos , int l , int r , int i  , int j){
    if(i > r || j < l) return 0;
    if(i <= l && j >= r) return st[pos];
    return rq(2 * pos + 1 , l , (l+r) / 2 , i , j) + rq(2 * pos + 2 , (l+r) / 2 + 1 , r , i , j);
}

int main(){
    //ifstream fin ("testing.txt");
    //ofstream fout ("output.txt");
    ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    cin>>n>>s;
    for(int i = n ; i < 2 * n ; i++){
        int id = s[i] == 'B';
        v[id].pb(i);
    }
    reverse(all(v[0]));
    reverse(all(v[1]));
    ll ans = 0;
    for(int i = 0 ; i < n ; i++){
        int id = s[i] == 'W';
        ans += rq(0 , 0 , 2 * n - 1 , n , v[id].back());
        update(0 , 0 , 2 * n - 1 , v[id].back());
        v[id].pop_back();
    }
    cout << ans << "\n";
    return 0;
}

/*
    Think of : BS / DFS / BFS / SSSP / SCC / MSP / MAX FLOW / TOPSORT / LCA / MATRIX / DP(bitmask) / 2 POINTERS / SEG TREE / MATH / UN FIND / MO / HLD
    Read the statement CAREFULLY !!
    Make a GREADY APPROACH !!!! (start from highest / lowest)
    Make your own TESTS !!
    Be careful from CORNER CASES !
*/

Subtask #1
0.0 / 4.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 212 KB Output is correct
2 Correct 0 ms 212 KB Output is correct
3 Correct 0 ms 328 KB Output is correct
4 Correct 0 ms 328 KB Output is correct
5 Incorrect 0 ms 212 KB Output isn't correct
6 Halted 0 ms 0 KB -

Subtask #2
0.0 / 21.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 212 KB Output is correct
2 Correct 0 ms 212 KB Output is correct
3 Correct 0 ms 328 KB Output is correct
4 Correct 0 ms 328 KB Output is correct
5 Incorrect 0 ms 212 KB Output isn't correct
6 Halted 0 ms 0 KB -

Subtask #3
0.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 212 KB Output is correct
2 Correct 0 ms 212 KB Output is correct
3 Correct 0 ms 328 KB Output is correct
4 Correct 0 ms 328 KB Output is correct
5 Incorrect 0 ms 212 KB Output isn't correct
6 Halted 0 ms 0 KB -

Subtask #4
0.0 / 65.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 212 KB Output is correct
2 Correct 0 ms 212 KB Output is correct
3 Correct 0 ms 328 KB Output is correct
4 Correct 0 ms 328 KB Output is correct
5 Incorrect 0 ms 212 KB Output isn't correct
6 Halted 0 ms 0 KB -