제출 #612357

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
612357		PanTkd	DNA 돌연변이 (IOI21_dna)	C++17	0 / 100	38 ms	4684 KiB

dna

//
//  main.cpp
//
//  Created by Panagiotis Chadjicostas on
//  Copyright © Panagiotis Hadjicostas. All rights reserved.
//

#include <iostream>
#include <algorithm>
#include <bitset>
#include <complex>
#include <deque>
#include <fstream>
#include <iomanip>
#include <iterator>
#include <limits>
#include <list>
#include <cstring>
#include <map>
#include <queue>
#include <set>
#include <stack>
#include <string>
#include <vector>
#include <unordered_map>

using namespace std;

typedef long long ll;
typedef vector<ll> vi;
typedef pair<ll,ll> ii;
#define fo(i,a,b) for(int i = a; i<=b; i++)
#define f(i,b) for(int i=0;i<b;i++)
#define F first
#define S second
#define sz size
#define ls s,m,idx<<1
#define rs m+1,e,idx<<1|1
const ll MOD=ll(1e9)+7;
const ll MAXN=2*ll(1e6);
void checker(){
    ll n=rand()%20+2;
    vi a(n,ll());
    for(ll i=0;i<n;i++){
        a[i]=rand()%20+2;
    }
    for(ll b=0;b<(1<<n);b++){
        vi on,off;
        for(ll i=0;i<n;i++){
            if(i&(1<<i)){
                on.push_back(i);
            }
            else{
                off.push_back(i);
            }
        }
    }
}
///////////////////////////////////////////////////////////////////////
vector<ll> pa,pb,pab;

string ta,tb;
ll k;
void init(string a, string b){
    ll n=a.size();
    k=n;
    pa.assign(n+1,0);
    pb.assign(n+1,0);
    pab.assign(n+1,0);
    a='1'+a;
    b='1'+b;
    ta=a;
    tb=b;
    for(ll i=1;i<=n;i++){
        pa[i]=pa[i-1]+(a[i]=='A');
        pb[i]=pb[i-1]+(b[i]=='A');

        pab[i]=pab[i-1]+(a[i]!=b[i]);
    }
}

int get_distance(int x, int y){
    string p,s;
    x++,y++;
    multiset<char> s1,s2;
    for(ll i=x;i<=y;i++){
        p+=ta[i];
        
        s+=tb[i];
        
    }
    string pp=p,ss=s;
    sort(pp.begin(),pp.end());
    sort(ss.begin(),ss.end());
    if(p==s)
        return 0;
    if(pp!=ss){
        return -1;
    } 
    for(ll i=0;i<y-x+1;i++)
        if(p[i]==s[i])
            return 1;
     
    return 2;   


}

• Subtask 1: 0 / 21
• Subtask 2: 0 / 22
• Subtask 3: 0 / 13
• Subtask 4: 0 / 28
• Subtask 5: 0 / 16