oj.uz

Submission #611912

# Submission time Handle Problem Language Result Execution time Memory
611912 2022-07-29T08:40:36 Z tranxuanbach Raisins (IOI09_raisins) C++17
100 / 100
 111 ms 13984 KB 
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;

#define endl '\n'
#define fi first
#define se second
#define For(i, l, r) for (auto i = (l); i < (r); i++)
#define ForE(i, l, r) for (auto i = (l); i <= (r); i++)
#define FordE(i, l, r) for (auto i = (l); i >= (r); i--)
#define Fora(v, a) for (auto v: (a))
#define bend(a) (a).begin(), (a).end()
#define isz(a) ((signed)(a).size())

using ll = long long;
using ld = long double;
using pii = pair <int, int>;
using vi = vector <int>;
using vpii = vector <pii>;
using vvi = vector <vi>;

const int N = 50 + 2;

int n, m;
int a[N][N];

int b[N][N];

int sumsubrect(int x1, int y1, int x2, int y2){
    return b[x2][y2] - b[x2][y1 - 1] - b[x1 - 1][y2] + b[x1 - 1][y1 - 1];
}

int dp[N][N][N][N];

signed main(){
    ios_base::sync_with_stdio(0);
    cin.tie(0); cout.tie(0);
    // freopen("KEK.inp", "r", stdin);
    // freopen("KEK.out", "w", stdout);
    cin >> n >> m;
    ForE(i, 1, n){
        ForE(j, 1, m){
            cin >> a[i][j];
        }
    }

    ForE(i, 1, n){
        ForE(j, 1, m){
            b[i][j] = b[i][j - 1] + b[i - 1][j] - b[i - 1][j - 1] + a[i][j];
        }
    }
    ForE(lenx, 1, n){
        ForE(x1, 1, n - lenx + 1){
            int x2 = x1 + lenx - 1;
            ForE(leny, 1, m){
                ForE(y1, 1, m - leny + 1){
                    int y2 = y1 + leny - 1;
                    dp[x1][x2][y1][y2] = INT_MAX;
                    For(x, x1, x2){
                        dp[x1][x2][y1][y2] = min(dp[x1][x2][y1][y2], dp[x1][x][y1][y2] + dp[x + 1][x2][y1][y2]);
                    }
                    For(y, y1, y2){
                        dp[x1][x2][y1][y2] = min(dp[x1][x2][y1][y2], dp[x1][x2][y1][y] + dp[x1][x2][y + 1][y2]);
                    }
                    dp[x1][x2][y1][y2] += sumsubrect(x1, y1, x2, y2);
                    if (lenx == 1 and leny == 1){
                        dp[x1][x2][y1][y2] = 0;
                    }
                }
            }
        }
    }
    cout << dp[1][n][1][m] << endl;
}

/*
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INPUT:                                            |
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OUTPUT:                                           |
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*/

Subtask #1
100.0 / 100.0

# Verdict Execution time Memory Grader output
1 Correct 1 ms 340 KB Output is correct
2 Correct 1 ms 340 KB Output is correct
3 Correct 1 ms 340 KB Output is correct
4 Correct 1 ms 336 KB Output is correct
5 Correct 1 ms 468 KB Output is correct
6 Correct 1 ms 596 KB Output is correct
7 Correct 1 ms 924 KB Output is correct
8 Correct 2 ms 1748 KB Output is correct
9 Correct 3 ms 2828 KB Output is correct
10 Correct 4 ms 3276 KB Output is correct
11 Correct 4 ms 2388 KB Output is correct
12 Correct 11 ms 5716 KB Output is correct
13 Correct 17 ms 7024 KB Output is correct
14 Correct 5 ms 2772 KB Output is correct
15 Correct 22 ms 7756 KB Output is correct
16 Correct 4 ms 5052 KB Output is correct
17 Correct 10 ms 7636 KB Output is correct
18 Correct 60 ms 12356 KB Output is correct
19 Correct 90 ms 12928 KB Output is correct
20 Correct 111 ms 13984 KB Output is correct